\(=\frac{2^3.1.3.5+2^3.3.5.7+2^3.5.7.9+...+2^3.97.99.101}{1.3.5+3.5.7+5.7.9+...+97.99.101}\)

\(=\frac{2^3\left(1.3.5+3.5.7+5.7.9+...+97.99.101\right)}{1.3.5+3.5.7+5.7.9+...+97.99.101}=2^3=8\)

\(A=\dfrac{2.6.10+6.10.14+10.14.18+..+194.198.202}{1.3.5+3.5.7+5.7.9+..+97.99.101}\)

\(=\dfrac{2^3.1.3.5+2^3.3.5.7+2^3.5.7.9+...+2^3.97.99.101}{1.3.5+3.5.7+7.9.11+...+97.99.101}\)

\(=\dfrac{2^3.\left(1.3.5+3.5.7+7.9.11+...+97.99.101\right)}{1.3.5+3.5.7+5.7.9+...+97.99.101}=2^3=8\)

ta có tử =2.(1.3.5)+2.(3.5.7)+2.(5.7.9)+....+2.(97.99.101)

             =2.(1.3.5+3.5.7+5.7.9+....+97.99.101)

mà mẫu =1.3.5+3.5.7+5.7.9+...+97.99.101

suy ra A=2

\(A=\frac{2.6.10+6.10.14+10.14.18+...+194.198.202}{1.3.5+3.5.7+5.7.9+...+97.99.101}\)

\(A=\frac{8.\left(1.3.5+3.5.7+5.7.9+...+97.99.101\right)}{1.3.5+3.5.7+5.7.9+...+97.99.101}\)

\(A=8\)

A =\(\dfrac{2.6.10+6.10.14+10.14.18+...+194.198.202}{1.3.5+3.5.7+5.7.9+...+97.99.101}\)

\(\Rightarrow\)A=\(\dfrac{1.3.5\left(1.3.5+3.5.7+5.7.9+...+97.99.101\right)}{1.3.5+3.5.7+5.7.9+...+97.99.101}\)

A=\(\dfrac{15}{1}\)=15

A=15

=15

A =2.6.10+6.10.14+10.14.18+...+194.198.202/1.3.5+3.5.7+5.7.9+7.9.11+...+97.99.101

   =2.2.2(1.3.5)+2.2.2(3.5.7)+2.2.2(5.7.9)+...+2.2.2(97.99.101)/1.3.5+3.5.7+5.7.9+...+97.99.101

  =2.2.2/1

  =2^3/1

  =8/1

  =8 

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