Tìm x
x:0,25+x*11=24
1. tìm x
x : 0,25 + x x 11 = 39
`x:0,25+x xx11=39`
`x xx4 + x xx11=39`
`x xx(4+11)=39`
`x xx15=39`
`x =13/5`
X:0,25+X x 11 =39
=> X x 4 + X x 11 =39
=> X x( 4+11) =39
=> X x 15 =39
=> X =39 :15
=> X=2,6
= X x 4 + X x 11 = 39
= X x 15 = 39
= 39 / 15 = 2,6
X : 0,25 + X x 11 = 24
⇒ X x 4 + X x 11 = 24
⇒ X x ( 4+11) = 24
⇒ X x 15 = 24
⇒ X = 24 : 15 = 1,6
X: 0,25 + X x 11 = 24
<=> X x 4 + X x 11= 24
<=> X x (4+11)= 24
<=> X x 15= 24
=> X= 24/15
\(x:0,25+x\times11=24\)
\(\Rightarrow x\times4+x\times11=24\)
\(\Rightarrow x\times\left(4+11\right)=24\)
\(\Rightarrow x\times15=24\)
\(\Rightarrow x=\dfrac{8}{5}\)
Vậy: \(x=\dfrac{8}{5}\)
x : 0,25 + x * 11 =24
(:0,25=*4)
Ta có:x*4+x*11=24
x*(11+4)=24
x*15=24
x=24:15
x=1,6
K nhé
\(x:0,25+x\cdot11=24\)
<=> \(x.\frac{1}{4}+x.11=24\)
<=> \(x.\left(\frac{1}{4}+11\right)=24\)
<=> \(x.\frac{45}{4}=24\)
<=> \(x=\frac{32}{15}\)
\(0,25=\frac{1}{4}\)
\(\Rightarrow x:\frac{1}{4}+x.11=24\) \(\Rightarrow x.4+x.11=24\)
\(\Rightarrow x.\left(4+11\right)=24\)\(\Rightarrow x.15=24\) \(\Rightarrow x=\frac{24}{15}\)
x : 0,25 + x * 11 = 24
X:0,25+x ×11=24
x / 0,25 + x * 11 = 24
x * 4 + x * 11 = 24
x * 15 = 24
x = 24/15
x:0,25+x*11=24
\(x:0,25+x.11=24\)
\(x.\frac{1}{4}+x.11=24\)
\(x.\left(\frac{1}{4}+11\right)=24\)
\(x.\frac{54}{4}=24\)
\(x=24:\frac{54}{4}\)
\(x=24.\frac{4}{45}\)
x=\(\frac{96}{45}\)
vạy x=\(\frac{96}{45}\)
\(x : 0,25 + x * 11 = 24\)
\(x : 1/4 + x * 11= 24\)
\(x * 4 + x * 11 = 24\)
\(x * (4 +11)=24\)
\(x*15=24\)
\(x=24:15\)
\(x = 1,6\)
#chúc_bạn_học_tốt
x : 0,25 + x . 11 = 24
x . 4 + x . 11 = 24
x . ( 4 + 11 ) = 24
x . 15 = 24
x = 24 : 15
x = 1,6
X : 0,25 + X x 11=24
\(x:0,25+x\cdot11=24\)
\(x\cdot4+x\cdot11=24\)
\(x\cdot\left(4+11\right)=24\)
\(x\cdot15=24\)
\(x=24:15\)
\(x=1,6\)
x :0,25 +x x 11 = 24
giúp mình với
\(x\) : 0,25 + \(x\) x 11 = 24
\(x\) x 4 + \(x\) x 11 = 24
\(x\) x (4 + 11) = 24
\(x\) x 15 = 24
x = 24 : 15
x = 1,6
x : 0,25 + x x 11 = 24
X x 4 + X x 11 = 24
X x ( 4 + 11 ) = 24
X x 15 = 24
X = 24 : 15
X = 1,6
tìm x
x:0,25+x*11=24