A=1/2+1/4+1/8+1/16+1/32.Tìm A
B1 : Tính nhanh :1/2 + 1/4 + 1/8 +1/16 +1/32+ 1/128+1/256
B2: Tìm a biết a + a + a + 1/2 x 2/5 + a + 8/10= 136
đcm là đầu cắt moi
vì quá dễ nên mình không thể trả lời bạn được nhé!
dễ vl ko làm đc là ngu
A= 1/2 + 1/4 + 1/8 +1/16 +1/32 + 1/64 +1/128 + 1/256 + 1/512 + 1/1024
tìm A/tính nhanh
A = 1/2 + 1/4 + 1/8 + ... + 1/1024
2A = 1 + 1/2 + 1/4 + ... + 1/512
2A - A = (1 + 1/2 + 1/4 + ... + 1/512) - (1/2 + 1/4 + 1/8 + ... + 1/1024)
A = 1 - 1/1024
A = 1023/1024
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+....+\frac{1}{1024}\)
\(\Rightarrow2A=1+\frac{1}{2}+\frac{1}{4}+......+\frac{1}{512}\)
\(\Rightarrow A=2A-A=1-\frac{1}{1024}\)
\(A=\frac{1023}{1024}\)
A=\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}+\frac{1}{1024}\)
2 x A=\(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\)
2 x A - A = \(\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}+\frac{1}{1024}\right)\)
A=\(1-\frac{1}{1024}\)
A=\(\frac{1023}{1024}\)
So sánh A và B biết: A=(2+1)×(2^2+1)×(2^4+1)×(2^8+1)×(2^16+1)×(2^16+1) và B=2^32
Ta có: \(A=\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(=2^{32}-1< 2^{32}\)
\(\Leftrightarrow A< B\)
Tìm cách tính nhanh tổng sau mà không quy đồng mẫu số: A=1/2+1/4+ 1/8+1/16+1/32+1/72+1/128+1/256
Bạn kiểm tra lại đề hộ. Nếu có phân số \(\frac{1}{4}\)thì chịu còn không có thì dễ.
A=1/2+1/4+1/8+1/16+1/32
Tính không quy đồng mẫu:
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{32}-\frac{1}{64}\)
\(A=1-\frac{1}{64}=\frac{63}{64}\)
A = 32 + 16 + 8 + 4 + 2 + 1/64 = 63/64
P/s nhỏ
Bạn vào câu hỏi tương tự nhé
Có nhiều câu giồng bạn lắm
Học tốt nhé!
A= 1/2+1/4+1/8+1/16+1/32+1/64
A=?
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)
\(A=\frac{32+16+8+4+2+1}{64}\)
\(A=\frac{63}{64}\)
Chúc bạn học tốt và tíck cho mìk vs nha!
cach 1
A=1/2+1/4+1/8+1/16+1/32+1/64
ta thấy:1/2=1-1/2; 1/4 = 1/2 - 1/4;... ;1/64 = 1/32 - 1/64
A = 1-1/2+1/2-1/4+1/4-1/8+1/8-1/16+1/16-1/32+1/32-1/64
A=1-1/64
A=63/64
cách 2
A=1/2+1/4+1/8+1/16+1/32+1/64
A x 2=1+1/2+1/4+1/8+1/16+1/32
A x 2 - A= (1+1/2+1/4+1/8+1/16+1/32)-(1/2+1/4+1/8+1/16+1/32+1/64)
A x 2 = 1-1/64
A x 2 =63/64
A =63/64 : 2
A = 63/128
A=1/2+1/4+1/8+1/16+1/32+1/64
A=?
2A = 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32
2A - A = (1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32) - (1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64)
A = 1 - 1/64
A = 63/64
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)
\(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)
\(2A-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\right)\)
\(A=1-\frac{1}{64}=\frac{63}{64}\)
63/64 nha nha nha
A=1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64
A = 1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64
A = 1 - 1/64
A = 63/64
A = 1/2 + 1/4 +1/8+ 1/16 +1/32 +1/64
A = 1- 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64
A = 1 - 1/64
A = 63/64
A=1/2+1/4+1/8+1/16+1/32+1/64
A=32/64+16/64+8/64+4/64+2/64+1/64
A=32+16+8+4+2+1/64
A=63/64