\(2^{x-3}-3.2^x=-92\)

\(\Rightarrow2^x\left(2^{-3}-3\right)=-92\)

\(\Rightarrow2^x.\dfrac{-23}{8}=-92\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\Rightarrow x=5\)

Bạn ghi lại đề bằng latex nha

2^x-3-3.2^x=-92

<=>2^x:2³-3.2^x=-92

<=>2^x.(\(\dfrac{1}{8}\)-3)=-92

<=>2^x.\(\dfrac{-23}{8}\)=-92

<=>2^x=32

<=>2^x=2⁵

=>x=5

1) \(\dfrac{1}{4}x-\dfrac{1}{3}=\dfrac{-5}{9}\)

\(\Rightarrow\dfrac{1}{4}x=-\dfrac{2}{9}\Rightarrow x=-\dfrac{8}{9}\)

2) \(2^{x-3}-3.2^x=-92\)

\(\Rightarrow2^x\left(2^{-3}-3\right)=-92\)

\(\Rightarrow2^x.\dfrac{-23}{9}=-92\)

\(\Rightarrow2^x=32\Rightarrow x=5\)

\(2^{x-3}-3.2^x=-92\)

\(\Rightarrow2^x:2^3-3.2^x=-92\)

\(\Rightarrow2^x.\frac{1}{2^3}-3.2^x=-92\)

\(\Rightarrow2^x.\left(\frac{1}{2^3}-3\right)=-92\)

\(\Rightarrow2^x.\frac{-23}{8}=-92\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

A= \(\frac{19}{23}\)

\(\frac{19}{23}\)

A= \(\frac{-4}{5}+\frac{4}{3}-\frac{5}{4}+\frac{14}{5}-\frac{7}{3}\)

=\(2-1-\frac{5}{4}\)

=\(\frac{-1}{4}\)

\(\frac{8.2.3.19}{3.5.8.10.92}=\frac{19}{2300}\)

\(\frac{8}{3}\cdot\frac{2}{5}\cdot\frac{3}{8}\cdot10\cdot\frac{19}{92}=\left(\frac{8}{3}\cdot\frac{3}{8}\right)\cdot\left(\frac{2}{5}\cdot10\right)\cdot\frac{19}{92}=1\cdot4\cdot\frac{19}{92}=4\cdot\frac{19}{92}=\frac{19}{23}\)

\(\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10.\frac{19}{92}\)

\(=(\frac{8}{3}.\frac{3}{8}).(\frac{2}{5}.10).\frac{19}{92}\)

\(=4.\frac{19}{92}\)

\(=\frac{19}{23}\)

Hok tôt !!!!!!!!!!!!!!!