14+23
so sanh
a, A= 19/41 + 23/53 + 29/61
B= 21/41 + 23/49 + 33/65
b,A= 12/ 14^11 + 23/14^12
B=12/14^12 + 23/ 14^11
so sanh
a, A= 19/41 + 23/53 + 29/61
B= 21/41 + 23/49 + 33/65
b,A= 12/ 14^11 + 23/14^12
B=12/14^12 + 23/ 14^11
35( 14-23) - 23 (14-35)
35( 14-23) - 23 (14-35)=35.14-35.23-23.14+23.35
=(35.14-23.14)+(23.35-35.23)
=14.(35-23)+0
=14.12
=168
=35.14-23.35-23.14+23.35
=(35.14-23.14)+(23.35-35.23)=
=14(35-23)+0
=14.12
=168
35(14-23)-23(14-35)
Ta có: 35(14-23)-23(14-35)
=35.14-35.23-23.14-23.35
=(35.14-23.14)-(35.23-23.35)
= 14.(35-23)-0
=14.12
=168
ta tách: 35(14-23)-23(14-35)=35.14-35.23-23.14-23.35
=(35.14-23x14)-(35.23-23.35)
=14.(35-23)-0
=14.12
=168
Vậy kết quả =168
35.(14-23)-23.(14-35)
35(14-23)-23(14-35)
=35.14-35.23-23.14+23.35
=(23.35-35.23)+14(35-23)
=0+14.12
=168
35.(14-23)-23.(14-35)
= 35 . 14 - 35 . 23 - 23 . 14 + 23 . 35
= 35 . 14 - 23 . 14
= 14 . ( 35 - 23 )
= 14 . 12
= 168
Hok tốt !
so sanh
a, A= 19/41 + 23/53 + 29/61
B= 21/41 + 23/49 + 33/65
b,A= 12/ 14^11 + 23/14^12
B=12/14^12 + 23/ 14^11
14-23+(5-14)-(5-23)+17
35.(14-23).23.(14-35)
\(\dfrac{-19}{23}\) x \(\dfrac{13}{14}\) + \(\dfrac{13}{14}\)\(\) x \(\dfrac{-15}{23}\) - \(\dfrac{13}{14}\) x \(\dfrac{1}{23}\)
Mngười giải giúp em chi tiết nha! Tks
\(\dfrac{-19}{23}\cdot\dfrac{13}{14}+\dfrac{13}{14}\cdot\dfrac{-15}{23}-\dfrac{13}{14}\cdot\dfrac{1}{23}\\ =\dfrac{13}{14}\cdot\left(\dfrac{-19}{23}+\dfrac{-15}{23}-\dfrac{1}{23}\right)\\ =\dfrac{13}{14}\cdot\dfrac{-35}{23}=\dfrac{-65}{46}\)
35.(14-23)-23(14-35)
35.(14-23)-23(14-35)
=35.14-35.23-23.14+23.35
=14.(35-23)-35.23+23.35
=14.12
=168
\(35\cdot\left(14-23\right)-23\cdot\left(14-35\right)\\ =35\cdot14-35\cdot23-23\cdot14+23\cdot35\\ =\left(35\cdot14-23\cdot14\right)+\left(23\cdot35-35\cdot23\right)\\ =14\cdot\left(35-23\right)+0\\=14\cdot12+0\\ =168+0\\ =168 \)