a)1*2*3+2*3*4+...+111*112*113
b)1^3+2^3+3^+...+100^3
1*2*3+2*3*4+...+111*112*113
Tính tổng
a)100+98+96+...+2-97-95-93-...-3
b) 2-4-6+8+10-12-14+16+...-102+104
c) 1+2-3-4+5+6-7-8+9+10-11-12+...-111-112+113+114
a) \(100+98+96+...+2-97-95-93-...-3\)
= \(100+98+\left(96-97\right)+\left(94-95\right)+...+\left(2-3\right)\)
= \(100+98-95\) = \(103\)
b) \(2-4-6+8+10-12-14+16+...-102+104\)
= \(\left(2-4\right)+\left(-6+8\right)+\left(10-12\right)+\left(-14+16\right)+...+\left(-102+104\right)\)
= \(-2+2-2+2-2+...+2\) = \(0\)
c) \(1+2-3-4+5+6-7-8+9+10-11-12+...-111-112+113+114\)
= \(\left(1+2\right)-\left(3+4\right)+\left(5+6\right)-\left(7+8\right)+...\left(113+114\right)\)
= \(3-7+11-15+19-23+...+219-223+227\)
= \(\left(3-7\right)+\left(11-15\right)+\left(19-23\right)+...+\left(219-223\right)+227\)
= \(-4-4-4-4-...-4+227\)
= \(54\left(-4\right)+227\) = \(-216+227\) = \(11\)
1-2+2+3-4+5-...-110+111-112+113
1.Cho f(x)=3x^3/(3x^2-3x+1)
A=f(1/112)+f(2/112)+..+f(110/112)+f(111/112)-1/2
A= 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 +...+110 - 111 - 112 + 113
Tính AGiúp mình vsLời giải:
$A=(1+2-3-4)+(5+6-7-8)+(9+10-11-12)+...+(109+110-111-112)+113$
$=(-4)+(-4)+(-4)+....+(-4)+113$
Số lần xuất hiện của -4 là: $[(112-1):1+1]:4=28$
$A=(-4).28+113=1$
tính tổng hợp lí: a) A = -1+3-5+7-9+...-2009+2011-2013
b)B =2-4+6-8+...+2006-2008+2010
c)C =1+2-3-4+5+6-7+-8+...-111-112+113+114+115
A=2+2+...+2-2013
=2x1006+2013
=4025
Tính hợp lí:
a. A= -1 + 3 - 5 + 7 - 9 +....- 2017 + 2019
b. B= 2 - 4 + 6 - 8 +...+ 2018 - 2020
c. C= 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8+...-111 - 112 + 113 + 114 + 115
c) C= 1+2-3-4+5+6-7-8+...-111-112+113+114+115
ta thấy : 114 chia 4 dư 2 ; 115 chia 4 dư 3
=> C=1+(2-3-4+5)+(6-7-8+9)+...+((110-111-112+113)+114+115
=> C=1+0+0+...+0+229
=> C=300
HỘ MÌNH VỚI Ạ
Bài 1: Tính
a, A= -1+3-5+7-9+... -2013+2015-2017
b, B= 2-4+6-8+...+2014-2016+2018
c. C= 1+2-3-4+5+6-7-8+...-111-112+113+114
Bài 2
a, ( x+1)+ (x+2)+ (x+3)+...+(x+100)= 5750
b, (2x-1)+(4x-2)+...+(400x-200)= 5+10+15+...+1000
c, ( x+2)+(4x+4)+(7x+6)+...+(25x+18)+ (28x+20)= 1560
Bài 3
a, 1*3+2*4+3*5+4*6+...99*101+100*102
b, 1*100+2*99+3*98+...+99*2+100*1
\(a,A=-1+3-5+7-9+...-2013+2015-2017=\left(-1+3\right)+\left(-5+7\right)+...+\left(-2013+2015\right)-2017\)\(=2+2+..+2-2017\)
\(=2.504-2017=-1009\)
\(b,B=2-4+6-8+...+2014-2016+2018\)\(=2+\left(-4+6\right)+\left(-8+10\right)+...+\left(-2016+2018\right)==2+2+...+2\)\(=2+503.2=1008\)
C = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + . . . - 111 - 112 + 113 + 114 - 115
C = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + ... - 111 - 112 + 113 + 114 - 115 ( có 115 số; 115 chia 4 dư 2)
C = 1 + (2 - 3 - 4 + 5) + (6 - 7 - 8 + 9) + ... + (110 - 111 - 112 + 113) + 114 - 115
C = 1 + 0 + 0 + ... + 0 + 114 - 115
C = 1 + 114 - 115
C = 115 - 115
C = 0