14)

\(\left(27.45+27.55\right):\left(2+4+6+...+18\right)\)

\(=\left[27\left(45+55\right)\right]:\left[\frac{\left(18+2\right)9}{2}\right]\)

\(=\left(27.100\right):90\)

\(=2700:90\)

\(=30\)

15)

\(\left(26.180-26.12\right):\left(32-18+....+8-4\right)\) 

\(=26\left(180-12\right):\left(14+4+4+4+4+4+4+4\right)\)

\(=26.168:42\)

\(=84\)

\(\dfrac{-8}{18}+\dfrac{-15}{27}\\ =\dfrac{-4}{9}+\dfrac{-5}{9}\\ =\dfrac{-4+\left(-5\right)}{9}\\ =\dfrac{-9}{9}\\ =-1\)

15 - (-15 + 2) = 15 + 13 = 28

(-14) - (17 - 8) = -14 - 9 = -23

15 - (21- 7) = 15 - 14 = 1

34 + (-15) - 17 = 19 - 17 = 2

(-34) + (-12) + 18 = -46 + 18 = -28

27 - 15 - 19 = 12 - 19 = -7

34 - (-15) + 8 = 49 + 8 = 57

-37 + 13 - 25 = -24 - 25 = -49

40 - 17 + (-25) = 23 + (-25) = -2

16 + (-15) - 18 = 1 - 18 = -17

15 - 14 - 13 = 1 - 13 = -12

-27 + 15 - 17 = -12 - 17 = -29

34 - 71 = -37

28 - 125 = -97

13 + (-27) = -14

14 - (-34) = 48

28 - (-16) = 44

-15 - 8 = -23

-27 - 34 = -61

-25 - (-18) = -7

46 - 25 - (-25) = 21 + 25 = 46

-37 - (-24) = -13

46 - (-15) = 61

-26 - 6 + 7 = -32 + 7 = -25

@linhcute

4/16 = 5/..20.

9/18 = 15/...30

.12../8 = 27/18

4/16 = 5/20

9/18 = 15/30

12/8 = 27/18

a, \(-\dfrac{8}{18}-\dfrac{15}{27}=-\dfrac{4}{9}-\dfrac{5}{9}=\dfrac{-4-5}{9}=-\dfrac{9}{9}=-1\)

\(b,\Leftrightarrow x=\dfrac{3}{4}-\dfrac{1}{3}=\dfrac{9}{12}-\dfrac{4}{12}=\dfrac{5}{12}\)

Vậy ...

\(-\dfrac{8}{18}-\dfrac{15}{27}=-1\)

\(x+\dfrac{1}{3}=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}-\dfrac{1}{3}\)

\(x=\dfrac{9}{12}-\dfrac{4}{12}\)

\(x=\dfrac{5}{12}\)

Bài 1:

a: \(=\dfrac{21}{7}\cdot\dfrac{15}{45}\cdot\dfrac{9}{18}=3\cdot\dfrac{1}{3}\cdot\dfrac{1}{2}=\dfrac{1}{2}\)

b: \(=\dfrac{11}{33}\cdot\dfrac{24}{8\cdot12}\cdot\dfrac{27}{9}=\dfrac{24}{96}=\dfrac{1}{4}\)

Lời giải:
a.

$\frac{6}{13}+\frac{-15}{39}=\frac{6}{13}+\frac{-5}{13}=\frac{6+(-5)}{13}=\frac{1}{13}$

b.

$\frac{-8}{18}+\frac{-15}{27}=\frac{-4}{9}+\frac{-5}{9}=\frac{-4-5}{9}=\frac{-9}{9}=-1$

27/15 + 6/8 =51/20
19/24 + 7/18 = 85/72
2/9 - 1/6 = 1/18
8/15 -1/3 = 1/5

Bài 1:

a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\)  + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)

=  \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)

= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)

= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)

= 0 + 1 - \(\dfrac{5}{8}\)

= \(\dfrac{3}{8}\)

b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))

= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)

= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)

= 0 + 0 + 0 - \(\dfrac{7}{5}\)

= - \(\dfrac{7}{5}\)

Bài 1 c;

   \(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))

=  \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)

= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)

= 0 + 0 - 1 + \(\dfrac{80}{87}\)

= - \(\dfrac{7}{87}\)

Bài 1 d; 

   \(\dfrac{1}{25}\) - \(\dfrac{4}{27}\) + (-\(\dfrac{23}{27}\) + \(\dfrac{-1}{25}\) - \(\dfrac{5}{43}\)) + \(\dfrac{5}{43}\) - \(\dfrac{4}{7}\)

= \(\dfrac{1}{25}\) - \(\dfrac{4}{27}\) - \(\dfrac{23}{27}\) - \(\dfrac{1}{25}\) - \(\dfrac{5}{43}\) + \(\dfrac{5}{43}\) - \(\dfrac{4}{7}\)

= (\(\dfrac{1}{25}\) - \(\dfrac{1}{25}\)) - (\(\dfrac{4}{27}\) + \(\dfrac{23}{27}\)) - (\(\dfrac{5}{43}\) - \(\dfrac{5}{43}\)) - \(\dfrac{4}{7}\)

= 0 - 1 - 0 - \(\dfrac{4}{7}\)

= \(\dfrac{-11}{7}\)

a, => x-12-15=x-19

=> x-27=x-19

=> x-x=-19+27

=> 0x=8

=> ko tốn tại x tm

b, => x-18+x=x-8

=> 2x-18=x-8

=> 2x-x=-8+18 

=> x=10

k mk nha