8/17+5/17<x/17>6/17+9/17
B= (151515/161616+17^9/17^10)-(1500/1600-176/187)
bài 1:
a,1/10*2/9*3/8*4/7*5/6*6/5*7/4*8/3*9/2
b,8/11+4/17-5/11-3/17-65/9-8/17-3/17-6/17
bài 1 Tính:
a) 5/17 * 8/-7+8/17*-7/3+-7/3*4/17
b) -10/13 + 5/17 - 3/13 + 12/17 - 11/20
giúp tớ vs ạ. Tớ CẢM ƠN
*tớ thêm một câu nữa ạ
c) 5/9 * 7/13 + 5/9 * 9/13 + 3/13 * -5/9
a) 5/17 * 8/-7+8/17*-7/3+-7/3*4/17
-40/119 + 12/17 × -7/3
-40/119 + -28/17 =-236/119
b) -10/13 + 5/17 - 3/13 + 12/17 - 11/20
(5/17+12/17)-(10/13+3/13)-11/20
-11/20
a) 5/17 * 8/-7+8/17*-7/3+-7/3*4/17
-40/119 + 12/17 × -7/3
-40/119 + -28/17 =-236/119
b) -10/13 + 5/17 - 3/13 + 12/17 - 11/20
(5/17+12/17)-(10/13+3/13)-11/20
-11/20
Điền dấu (>,<,=) thích hợp vào chỗ chấm:
7+8…8+7
17+4…17+7
7+8…7+9
17+6…6+17
7+5…7+3
17+28…28+17
7+8=8+7
17+4<17+7
7+8<7+9
17+6=6+17
7+5>7+3
17+28=28+17
5/9 × 8/17+ 3/17 : 9/7 - 5/9
\(\dfrac{5}{9}\times\dfrac{8}{17}+\dfrac{3}{17}:\dfrac{9}{7}-\dfrac{5}{9}\\ =\dfrac{40}{153}+\dfrac{7}{51}-\dfrac{5}{9}\\ =\dfrac{61}{153}-\dfrac{5}{9}\\ =\dfrac{-8}{51}\)
5/9 × 8/17+ 3/17 : 9/7 - 5/9
\(\dfrac{5}{9}\times\dfrac{8}{17}+\dfrac{3}{17}:\dfrac{9}{7}-\dfrac{5}{9}=\dfrac{40}{153}+\dfrac{3}{17}\times\dfrac{7}{9}-\dfrac{5}{9}=\dfrac{40}{153}+\dfrac{21}{153}-\dfrac{5}{9}=\dfrac{61}{153}-\dfrac{5}{9}\)
\(=\dfrac{61}{153}-\dfrac{85}{153}=\dfrac{-24}{153}=\dfrac{-8}{51}\)
Tìm x, biết a. 0,5x -2/3x=7/12 b. -8/17+5/17<x/17<-6/17+9/17 c. [x-5/12].9/29=-6/29
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\Rightarrow x\cdot\left(\frac{3}{6}-\frac{4}{6}\right)=\frac{7}{12}\)
\(\Rightarrow x\cdot\left(-1\right)=\frac{7}{12}\Rightarrow x=\frac{7}{12}:\left(-1\right)=\frac{7}{-12}\)
\(c,\frac{\left(x-5\right)}{12}\cdot\frac{9}{29}=\frac{-6}{29}\Rightarrow\frac{\left(x-5\right)}{12}=\frac{-6}{29}:\frac{9}{26}\)
\(\frac{\Rightarrow\left(x-5\right)}{12}=\frac{-6}{9}=\frac{-2}{3}\Rightarrow x-5=-\frac{2}{3}\cdot12\)
\(\Rightarrow x-5=\frac{-24}{3}=-8\Rightarrow x=-8+5=-3\)
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)
\(\Rightarrow x=-\frac{7}{2}\)
\(c,\frac{x-5}{12}\cdot\frac{9}{29}=-\frac{6}{29}\)
\(\Rightarrow\frac{x-5}{12}=-\frac{2}{3}\)
\(\Rightarrow x-5=12.\left(-\frac{2}{3}\right)\)
\(\Rightarrow x-5=-8\)
\(\Rightarrow x=-3\)
b)\(\frac{-8}{17}+\frac{5}{17}< \frac{x}{17}< \frac{-6}{17}+\frac{9}{17}\)\(\left(x\in Z\right)\)
\(\Rightarrow\frac{-3}{17}< \frac{x}{17}< \frac{3}{17}\)
\(\Rightarrow-3< x< 3\)
\(\Rightarrow x\in\left\{-2;-1;0;1;2\right\}\)
Vậy \(x\in\left\{-2;-1;0;1;2\right\}\)
Tìm x ∈ Z biết:
a, \(\dfrac{8}{17}+\dfrac{5}{17}< \dfrac{x}{17}< \dfrac{6}{17}+\dfrac{9}{17}\)
\(\dfrac{13}{17}< \dfrac{x}{17}< \dfrac{15}{17}\Rightarrow x=14\)
-3/5+8/17+(-5/8)-3/5+9/17
\(=-\dfrac{3}{5}+\dfrac{8}{17}-\dfrac{5}{8}-\dfrac{3}{5}+\dfrac{9}{17}\)
\(=1-\dfrac{6}{5}-\dfrac{5}{8}\)
\(=-\dfrac{1}{5}-\dfrac{5}{8}\)
\(=-\dfrac{33}{40}\)
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39