18 x 7 + 18 x 6 - 18 x 14 + 18
giup minh nha
18 x 7 + 18 x 16 - 18 x 14 + 18
mik vẫn cần gấp nha!!!!!!!!!!!!!!!!!
\(18\cdot7+18\cdot16-18\cdot14+18\)
\(=18\cdot\left(7+16-14+1\right)\)
\(=18\cdot10=180\)
\(\text{18 x 7 + 18 x 16 - 18 x 14 + 18}\)
\(=18\times\left(7+16-14+1\right)\)
\(=18\times10=180\)
18 x 7 + 18 x 16 - 18 x 14 + 18
= 18 x ( 7 + 16 - 14 + 1 )
= 18 x 10
= 180
Tính nhanh:
18 x 7 + 18 x 16 – 18 x 14 + 18
18 x 7 + 18 x 16 – 18 x 14 + 18
= 18 x 7 + 18 x 16 – 18 x 14 + 18 x 1
= 18 x (7 + 16 – 14 + 1)
= 18 x 10
= 180
14/27 : 7/18 x 6/5 + 3/10
giúp mik câu này nữa nha
= 4/3 x 6/5 + 3/10
= 8/5 +3/10
= 19/10
3 tìm x
a)4/9.x=1/9
b)x:-1/12=7/12
c)-5/14:x=-3/10
d)7/18.x-2/3=5/18
e)4/9-7/8.x=-2/3
f)1/6+-5/7:x=-7/18
a.1/4
b.-7/144
c.25/21
d.17/7
e.80/63
f.9/7
a)1/4
b)-7/144
c)-25/21
d)17/7
e)16/63
f)9/7
Mọi người tk mình đi mình đang bị âm nè!!!!!!
Ai tk mình mình tk lại nha !!!
Tìm số nguyên x biết :
a,-14 - 7+x= - 12 b,x+(-15)-(-6)=11
c,x-[18+(-7)]=15 d,-84+(-18-6)=x+(-20)
6/7 x y + 14/36 + 1/7 x y = 7/18
\(\frac{6}{7}.y+\frac{7}{18}+\frac{1}{7}.y=\frac{7}{18}\)
\(\frac{6}{7}.y+\frac{1}{7}.y+\frac{7}{18}=\frac{7}{18}\)
\(\frac{6}{7}.y+\frac{1}{7}.y=\frac{7}{18}-\frac{7}{18}\)
\(y.\left(\frac{6}{7}+\frac{1}{7}\right)=0\)
\(y.1=0\)
\(y=0:1\)
\(y=0\)
tìm x
a) 7/18 . x - 2/3 = 5/18
b) 4/9 - 7/8 . x = -2/3
c) 1/6 + -5/7 : -7/18
/ là phần nha
a, \(\dfrac{7}{18}x-\dfrac{2}{3}=\dfrac{5}{18}\)
\(\dfrac{7}{18}x=\dfrac{5}{18}+\dfrac{2}{3}\)
\(\dfrac{7}{18}x=\dfrac{17}{18}\)
\(x=\dfrac{17}{18}\div\dfrac{7}{18}\)
\(x=\dfrac{17}{7}\)
a) \(\dfrac{7}{18}\).x-\(\dfrac{2}{3}\)=\(\dfrac{5}{18}\)
\(\dfrac{7}{18}\).x =\(\dfrac{5}{18}\)+\(\dfrac{2}{3}\)
\(\dfrac{7}{18}\).x = \(\dfrac{17}{18}\)
x = \(\dfrac{17}{18}\) :\(\dfrac{7}{18}\)
x =\(\dfrac{17}{7}\)
b)\(\dfrac{4}{9}\) - \(\dfrac{7}{8}\).x =\(\dfrac{-2}{3}\)
\(\dfrac{7}{8}\).x =\(\dfrac{4}{9}\)-\(\dfrac{-2}{3}\)
\(\dfrac{7}{8}\).x =\(\dfrac{10}{9}\)
x =\(\dfrac{10}{9}\) : \(\dfrac{7}{8}\)
x =\(\dfrac{80}{63}\)
c)\(\dfrac{1}{6}\)+\(\dfrac{-5}{7}\): \(\dfrac{-7}{18}\)
\(\dfrac{1}{6}\)+\(\dfrac{90}{49}\)
\(\dfrac{589}{294}\)
Nếu đúng mình xin 1 cái theo dõi nha bạn
Tìm x,y,z,t,u thuộc Z,biết
-7/6=x/18=-98/y=-14/zz=t/102=u/-18
\(\frac{-7}{6}=\frac{x}{18}=\frac{-98}{y}=\frac{-14}{z}=\frac{t}{102}=\frac{u}{-18}\)
\(\text{+) }\frac{-7}{6}=\frac{x}{18}\)
\(\Rightarrow\left(-7\right).18=6.x\)
\(\Rightarrow-126=6.x\)
\(\Rightarrow x=-21\)
\(\text{+) }\frac{-7}{6}=\frac{-98}{y}\)
\(\Rightarrow\left(-7\right).y=6.\left(-98\right)\)
\(\Rightarrow y=\frac{6.\left(-98\right)}{-7}\)
\(\Rightarrow y=-84\)
\(\text{+) }\frac{-7}{6}=\frac{-14}{z}\)
\(\Rightarrow\left(-7\right).z=\left(-14\right).6\)
\(\Rightarrow\left(-7\right).z=-84\)
\(\Rightarrow z=12\)
\(\frac{-7}{6}=\frac{t}{102}\)
\(\Rightarrow\left(-7\right).102=t.6\)
\(\Rightarrow t=\frac{\left(-7\right).102}{6}=\frac{\left(-7\right).17.6}{6}\)
\(\Rightarrow t=-119\)
\(\frac{-7}{6}=\frac{u}{-18}\)
\(\Rightarrow\frac{-7}{6}=\frac{-u}{18}\)
\(\Rightarrow\left(-7\right).18=\left(-u\right).6\)
\(\Rightarrow-126=\left(-u\right).6\)
\(\Rightarrow-u=-21\)
\(\Rightarrow u=21\)
Giúp tớ với tìm x : x- -18/54=7/9(âm 18) -14/42-x=-4/7
a: \(x-\dfrac{-18}{54}=\dfrac{7}{9}\cdot\left(-18\right)\)
=>x+1/3=7/9*(-18)=-7
=>x=-7-1/3=-22/3
b: -x-14/42=-4/7
=>x+1/3=4/7
=>x=4/7-1/3=12/21-7/21=5/21