\(\sqrt{4x^2-4x+9}=3\\ \Rightarrow4x^2-4x+9=9\\ \Rightarrow4x\left(x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}4x=0\\x-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Ta có: \(\sqrt{4x^2-4x+9}=3\)

\(\Leftrightarrow4x^2-4x=0\)

\(\Leftrightarrow4x\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

x=-70

hh

h1) Ta có : ^A + ^B + ^C = 180⁰

=> 75⁰ + 66⁰ + x = 180⁰

<=> x = 180⁰ - 75⁰ - 66⁰ = 39⁰

h2) Ta có : ^E + ^D + ^F = 180⁰

=> 63⁰ + 37⁰ + x = 180⁰

<=> x = 180⁰ - 100⁰ = 80⁰

h3) Ta có : ^N + ^M + ^P = 180⁰

=> 136⁰ + x + x = 180⁰ <=> 2x = 44⁰ <=> x = 22⁰ 

=> ^N = ^P = x = 22⁰ 

h4) Ta có : ^A + ^B + ^C = 180⁰

=> 100⁰ + 55⁰ + x = 180⁰

<=> x = 180⁰ - 100⁰ - 55⁰ = 25⁰

éo

Vì ΔABC=ΔDEI⇒EI=BC

⇒chu vi của ΔABC là: \(8+7+9=24\left(cm\right)\)

⇒chu vi của ΔBEI là: \(24\left(cm\right)\)

giúp mik đi mà!!!

ΔBEI=ΔABC=24cm

P=.....xem thêm

=(x-2-y)(x+2-y)

2S=2/1.2.3+2/2.3.4+...+2/8.9.10

2S=1/1.2+1/2.3+1/3.4+1/4.5+....+1/8.9+1/9.10

2S=1-1/2+1/2-1/3+1/3-1/4+...+1/9-1/10

2S=1-1/10

2S=9/10

S=9/10:2

S=9/10.2

S=9/20

\(150-5\left(x-2\right)^2=25\)

\(5\left(x-2\right)^2=150-25=125\)

\(\left(x-2\right)^2=125:5=25\)

\(\Rightarrow\orbr{\begin{cases}x-2=5\\x-2=-5\end{cases}\Rightarrow\orbr{\begin{cases}x=7\\x=-3\end{cases}}}\)

1824 : 32 = 57

15 622 : 73 = 214

1824 : 32 = 57

15622 : 73 = 214

tick