\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)

           \(\frac{1}{4}:x=\frac{3}{5}-\frac{25}{100}\)

             \(\frac{1}{4}:x=\frac{7}{20}\)

                    \(x=\frac{1}{4}:\frac{7}{20}\)

                     \(x=\frac{5}{7}\)

Vậy : \(x=\frac{5}{7}\)

k mik nha bn

3/5-1/4:x=25/100

      1/4:x=3/5-25/100

       1/4:x=7/20

             x=1/4:7/20

             x=5/7

3/5-1/4:x=25/100

1/4:x=25/100+3/5

1/4:x=17/20

      x=17/20x1/4

      x=17/80

Vậy x=17/80

cam on ban nhieu nhe 

sai roi

\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)

\(\frac{3}{5}-\frac{1}{4}:x=\frac{1}{4}\)

\(\frac{1}{4}:x=\frac{3}{5}-\frac{1}{4}\)

\(\frac{1}{4}:x=\frac{7}{20}\)

\(x=\frac{1}{4}:\frac{7}{20}\)

\(x=\frac{5}{7}\)

\(x=\frac{5}{7}\)

3/5-1/4:x =1/4

1/4:x=3/5-14

        =7/20

      x=1/4:7/20

       x=5/7

bg:

3/5-1/4:x =25/100

1/4:x =3/5-25/100

1/4:x =7/20

x = 1/4:7/20

x =5/7

3/5-1/4:x=25/100

      1/4:x=3/5-25/100

      1/4:x=7/20

            x=1/4:7/20

            x=5/7

chuc bn hoc gioi nha!

e  mình hỏi bạn câu kia sao bạn là hỏi mình lại

\(=\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{13}{4}+\dfrac{3}{4}-\dfrac{1}{20}=4+\left(\dfrac{1}{4}-\dfrac{1}{5}-\dfrac{1}{20}\right)=4+0=4\)

=4

\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)

\(\frac{3}{5}-\frac{1}{4}:x=\frac{1}{4}\)

\(\frac{1}{4}:x=\frac{3}{5}-\frac{1}{4}\)

\(\frac{1}{4}:x=\frac{7}{20}\)

\(x=\frac{1}{4}:\frac{7}{20}\)

\(x=\frac{1}{4}.\frac{20}{7}\)

\(x=\frac{5}{7}\)

\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)

\(\frac{3}{5}-\frac{1}{4}:x=\frac{1}{4}\)

            \(\frac{1}{4}:x=\frac{3}{5}-\frac{1}{4}\)

             \(\frac{1}{4}:x=\frac{7}{20}\)

                   \(x=\frac{1}{4}:\frac{7}{20}\)

                   \(x=\frac{5}{7}\)

1*2*3*4*5*6*7*8*...*1000

b: \(\Leftrightarrow\left(\dfrac{29-x}{21}+1\right)+\left(\dfrac{27-x}{23}+1\right)+\left(\dfrac{25-x}{25}+1\right)+\left(\dfrac{23-x}{27}+1\right)+\left(\dfrac{21-x}{29}+1\right)=0\)

=>50-x=0

hay x=50

c: \(\Leftrightarrow\dfrac{x-2}{2001}+1=\dfrac{x-1}{2002}+\dfrac{x}{2003}\)

\(\Leftrightarrow\left(\dfrac{x-2}{2001}-1\right)=\left(\dfrac{x-1}{2002}-1\right)+\left(\dfrac{x}{2003}-1\right)\)

=>x-2003=0

hay x=2003

\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)

\(\frac{1}{4}:x=\frac{3}{5}-\frac{25}{100}\)

\(\frac{1}{4}:x=\frac{7}{20}\)

\(x=\frac{5}{7}\)

        Vậy \(x=\frac{5}{7}\)

3/5-1/4:x=25/100

7/20:x=25/100

x=7/20:25/100

x=7/5