tính nhanh : 2022 +2022 : 1/3 +2022+2022:1/5 =
tính C=a^2022+3^2022/b^2022+5^2022 biết a,b khác 0 thõa mãn 3a-b=1/2(a+b)
mình cần gấp, mọi người làm nhanh giúp mình
Tính nhanh : 2022 : 0,25 + 2022 : 0,1 - 2022 : 0,5 + 2022 : 1/6
`2022 : 0,25 + 2022 : 0,1 - 2022 : 0,5 + 2022 : 1/6`
`=2022 xx 4 +2022 xx 10 - 2022 xx 2 + 2022 xx 6`
`= 2022 xx(4+10-2+6)`
`=2022 xx 18`
`=36396`
\(3a-b=\dfrac{1}{2}\left(a+b\right)\) tính \(\dfrac{a^{2022}+3^{2022}}{b^{2022}+5^{2022}}\)
3a-b=1/2(a+b)
=>6a-2b=a+b
=>5a=3b
=>a/3=b/5=k
=>a=3k; b=5k
\(A=\dfrac{a^{2022}+3^{2022}}{b^{2022}+5^{2022}}\)
\(=\dfrac{3^{2022}\left(k^{2022}+1\right)}{5^{2022}\left(k^{2022}+1\right)}=\left(\dfrac{3}{5}\right)^{2022}\)
\(\dfrac{1}{2022}\)+\(\dfrac{3}{2022}\)+\(\dfrac{5}{2022}\)+...+\(\dfrac{2021}{2022}\)+1=?
Giúp tớ bài này với nhé.
Tính bằng cách thuận tiện nhất:
2022 + 2022 + 2022 + 2022 + 2022 + 2022 x 5 - 2022 x 7
\(=2022\times\left(1+1+1+1+1+5-7\right)\)
= 2022 x 3
= 6066
2022 + 2022 + 2022 + 2022 + 2022 + 2022 x 5 - 2022 x 7
= 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 5 - 2022 x 7
= 2022 x ( 1 + 1 + 1 + 1 + 1 + 5 - 7 )
= 2022 x 3
= 6066
Tính nhanh: A= \(\dfrac{2022}{1.2}+\dfrac{2022}{2.3}+\dfrac{2022}{3.4}+...+\dfrac{2022}{2021.2022}\)
A=2022(1/1-1/2+1/2-1/3+...+1/2021-1/2022)
=2022(1/1-1/2022)
=2022.2021/2022
ket qua tu tinh nha
A = \(\dfrac{2022}{1.2}+\dfrac{2022}{2.3}+\dfrac{2022}{3.4}+...+\dfrac{2022}{2021.2022}\)
= \(\dfrac{2022}{1}-\dfrac{2022}{2}+\dfrac{2022}{2}-\dfrac{2022}{3}+\dfrac{2022}{3}-\dfrac{2022}{4}+...+\dfrac{2022}{2021}-\dfrac{2022}{2022}\)
= \(\dfrac{2022}{1}-\dfrac{2022}{2022}\)
= \(2021\)
Chúc bạn học tốt!! ^^
2022.( 1/1.2+ 1/2.3+...+ 1/2021+2022)
2022. ( 1-1/2+1/2-1/3+......+1/2021-1/2022)
2022.( 1-1/2022)
2022.2021/2022
2021
Tính nhanh:
2022 x 2023 - 1/2023 x 2021 + 2022
\(\dfrac{2022\times2023-1}{2023\times2021+2022}\)
= \(\dfrac{\left(2021+1\right)\times2023-1}{2023\times2021+2022}\)
= \(\dfrac{2023\times2021+2023-1}{2023\times2021+2022}\)
= \(\dfrac{2023\times2021+2022}{2023\times2021+2022}\)
= 1
A=\(\dfrac{2022^{2022}+1}{2022^{2023}+1}\) ; B= \(\dfrac{2022^{2023}+1}{2022^{2024}+1}\) So sánh A và B
SOS! Mình đang cần giúp nhanh ạ vì mai thi rồi cảm ơn nhiều
nếu cần mik chụp cho bạn 1 đề tương tự
cho A=1+2022+2022^2+2022^3 +2022^4+...+2022^2016 + 2022^2017
và B= 2022^2018-1 . so sánh A và B
\(2022A=2022+2022^2+2022^3+2022^4+...+2022^{2018}\)
\(2021A=2022A-A=2022^{2018}-1\Rightarrow A=\dfrac{2022^{2018}-1}{2021}\)
\(\Rightarrow A< B\)