Bài 2: 

Ta có: MH//NK(gt)

nên \(\widehat{xKH}+\widehat{yHK}=180^0\)(hai góc trong cùng phía)

\(\Leftrightarrow\widehat{yHK}=65^0\)

 B D A D

a: \(\left\{{}\begin{matrix}3x-2y=5\\-2x+y=3\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}3x-2y=5\\-4x+2y=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-x=11\\-2x+y=3\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=-11\\y=2x+3=-22+3=-19\end{matrix}\right.\)

b: \(\left\{{}\begin{matrix}2x-y=4\\x-\dfrac{y}{2}=2\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}2x-y=4\\2x-y=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}0y=0\left(luônđúng\right)\\2x-y=4\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}y\in R\\2x=y+4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y\in R\\x=\dfrac{1}{2}y+2\end{matrix}\right.\)

Vậy: \(\left\{{}\begin{matrix}y\in R\\x=\dfrac{y+4}{2}\end{matrix}\right.\)

c: \(\left\{{}\begin{matrix}3x+2y=-2\\5x+4y=1\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}6x+4y=-4\\5x+4y=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}6x-5x=-4-1=-5\\5x+4y=1\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=-5\\4y=1-5x=1+25=26\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-5\\y=\dfrac{26}{4}=\dfrac{13}{2}\end{matrix}\right.\)

d: \(\left\{{}\begin{matrix}2x-y=6\\3x+5y=22\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}10x-5y=30\\3x+5y=22\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}13x=52\\2x-y=6\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=4\\2x-y=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=2x-6=2\cdot4-6=2\end{matrix}\right.\)

e: \(\left\{{}\begin{matrix}-x+2y-6=0\\5x-3y-5=0\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}-x+2y=6\\5x-3y=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-5x+10y=30\\5x-3y=5\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}7y=35\\x-2y=-6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=5\\x=2y-6=10-6=4\end{matrix}\right.\)

g: \(\left\{{}\begin{matrix}2x-3y=8\\5x+2y=1\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}4x-6y=16\\15x+6y=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}19x=19\\2x-3y=8\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=1\\3y=2x-8=2-8=-6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=-2\end{matrix}\right.\)

giúp mik với

đề khó nhìn quá

I.

1A

2C

3A

4C

5B

6B

7C

8B

9B

10C

II. 

1T

2F

3F

4T

5F

6T

7F

8T

9F

10F

Bài 1: 

a: =34,59

b: =56,13

c: =47,31

d: =58,30

Câu 2: 

a: =380

b: =483

c: =7540

d: =4920

If I had bought more milk, I would have had enough for breakfast
Have you ever visited South Africa?
We will have stopped working by 9p.m

B