\(C_2H_4+H_2O\underrightarrow{^{170^0C,H_2SO_4}}C_2H_5OH\)

\(C_2H_5OH+O_2\underrightarrow{^{\text{men giấm}}}CH_3COOH+H_2O\)

\(CH_3COOH+C_2H_5OH⇌CH_3COOC_2H_5+H_2O\left(Đk:H_2SO_{4\left(đ\right)},t^0\right)\)

\(2CH_3COOC_2H_5+Ca\left(OH\right)_2\underrightarrow{^{t^0}}\left(CH_3COO\right)_2Ca+2C_2H_5OH\)

\(\left(CH_3COO\right)_2Ca+Na_2CO_3\rightarrow2CH_3COONa+CaCO_3\downarrow\)

\(C_2H_4 + H_2O \xrightarrow{t^o,xt} C_2H_5OH\\ C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ CH_3COOH + C_2H_5 \rightleftharpoons CH_3COOC_2H_5 + H_2O\\ 2CH_3COOC_2H_5 + Ca(OH)_2 \to (CH_3COO)_2Ca + 2C_2H_5OH\\ (CH_3COO)_2Ca + Na_2CO_3 \to CaCO_3 + 2CH_3COONa\)

\(C_6H_{12}O_6 \xrightarrow{t^o,xt} 2CO_2 + 2C_2H_5OH\\ C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ CH_3COOH + C_2H_5OH \buildrel{{H_2SO_4,t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O\\ CH_3COOC_2H_5 + H_2O \buildrel{{H_2SO_4}}\over\rightleftharpoons CH_3COOH + C_2H_5OH\\ 2CH_3COOH + Ca(OH)_2 \to (CH_3COO)_2Ca + 2H_2O\)

C6H12O6 => C2H5OH + 2CO2

C2H5OH+O2  CH3-COOH+H2O

CH3COOH+C2H5OH->CH3COOC2H5+H2O(môi trường H2SO4 đặc , nhiệt độ)

CH3COOC2H5+H2O->CH3COOH+C2H5OH(môi trường H2SO4 đặc , nhiệt độ)

2CH3COOH + Ca(OH)2 → (CH3COO)2Ca + 2H2O

\(\left(C_6H_{10}O_5\right)_n+nH_2O\underrightarrow{H^+,t^o}nC_6H_{12}O_6\)

\(C_6H_{12}O_6\underrightarrow{men.rượu}2C_2H_5OH+2CO_2\)

\(C_2H_5OH+O_2\underrightarrow{men.giấm}CH_3COOH+H_2O\)

\(2CH_3COOH+CaO\rightarrow\left(CH_3COO\right)_2Ca+H_2O\)

Help me mn ơi giúp e với

A/ C6H12O6 => (men rượu,t^o) 2C2H5OH + 2CO2

C2H5OH + O2 => (men giấm) CH3COOH + H2O

2CH3COOH + CaCO3 => (CH3COO)2Ca + CO2 + H2O

(CH3COO)2Ca + H2SO4 => CaSO4 + 2CH3COOH

B/ NaOH + CH3COOH =>(t^o) CH3COONa + H2O

CH3COONa + HCl => (t^o) CH3COOH + NaCl

CH3COOH + C2H5OH => (pứ hai chiều, xt:H2SO4đ,t^o) CH3COOC2H5 + H2O

CH3COOC2H5 + H2O =>(pứ hai chiều, xt: to,H2SO4đ) CH3COOH + C2H5OH

A/

1) C₆H₁₂O₆ \(\xrightarrow[to]{menruou}\) 2C₂H₅OH + 2CO₂

2) C₂H₅OH + O₂ \(\underrightarrow{mengiam}\) CH₃COOH + H₂O

3) 2CH₃COOH + Ca(OH)₂ \(\rightarrow\) (CH₃COO)₂Ca + 2H₂O

4) (CH₃COO)₂Ca + H₂SO₄ \(\rightarrow\) CaSO₄ + 2CH₃COOH

B/

1) NaOH + CH₃COOH \(\underrightarrow{to}\) CH₃COONa + H₂O

2) CH₃COONa + HCl \(\rightarrow\) CH₃COOH + NaCl

3) CH₃COOH + C₂H₅OH \(\Leftrightarrow\) CH₃COOC₂H₅ + H₂O

( điều kiện : H2SO4 đặc , to)

4) CH₃COOC₂H₅ + H₂O \(\Leftrightarrow\) CH₃COOH + C₂H₅OH

( điều kiện : H2SO4 đặc, to)

A) C6H12O6----->2C2H5OH+2CO2 (BAY LÊN)

C2H5OH+O2----->CH3COOH+H2O

CH3COOH+Ca(OH)2----->(CH3COO)2Ca+2H2O

(CH3COO)2Ca+H2SO4----->CaSO4+2CH3COOH

TÔI GIẢI CHO CẬU RỒI ĐÓ

CỐ LÊN NHA ^^

A/ C6H12O6 => (men rượu,t^o) 2C2H5OH + 2CO2

C2H5OH + O2 => (men giấm) CH3COOH + H2O

2CH3COOH + CaCO3 => (CH3COO)2Ca + CO2 + H2O

(CH3COO)2Ca + H2SO4 => CaSO4 + 2CH3COOH

B/ NaOH + CH3COOH => CH3COONa + H2O

CH3COONa + HCl => CH3COOH + NaCl

CH3COOH + C2H5OH => (pứ hai chiều, xt:H2SO4đ,t^o) CH3COOC2H5 + H2O

CH3COOC2H5 + H2O => CH3COOH + C2H5OH (pứ hai chiều, xt: t^o,H2SO4đ)

B) NaOH +CH3COOH----->CH3COONa+H2O

CH3COONa+HCl----->CH3COOH+NaCl

CH3COOH+C2H5OH----->CH3COOC2H5+H2O

CH3COOC2H5+H2O------->C2H5OH+CH3COOH

XONG A,B RỒI ĐÓ

$C_2H_2Br_4+Zn\rightarrow C_2H_2+ZnBr_2$ (Điều kiện: nhiệt độ)

$C_2H_2+H_2O\rightarrow CH_3CHO$ (Điều kiện: Xúc tác HgSO4, nhiệt độ)

$CH_3CHO+O_2\rightarrow CH_3COOH$ (Điều kiện: Mn2+)

$CH_3COOH+C_2H_2\rightarrow CH_3COOC_2H_3$

\(C_2H_2Br_4 + 2Zn \to C_2H_2 + 2ZnBr_2\\ C_2H_2 + H_2O \xrightarrow{t^o,xt} CH_3CHO\\ CH_3CHO + \dfrac{1}{2}O_2 \xrightarrow{t^o,xt} CH_3COOH\\ CH_3COOH + C_2H_2 \xrightarrow{t^o,xt,p} CH_3COOCH=CH_2\)

(1) 2C₂H₅OH + O₂ \(\underrightarrow{mengiam}\) 2CH₃COOH + 2H₂O

(2) CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H_{5 +} H₂O (xt: axit, t^o )

(3) CH₃COOC₂H₅ + NaOH → CH₃COONa + C₂H₅OH

CH₃COONa + HCl → CH₃COOH + NaCl