1440:[89-(2x-5)=24.3
1440:[41-(2x-5)]=24.3
1440:[41-(2x-5)]=24.3
1440 : [41 - (2x - 5 ) ] = 48
41 - (2x - 5 ) = 1440 : 48
41 - ( 2x - 5 ) = 30
2x - 5 = 41 - 30
2x - 5 = 11
2x = 11 + 5
2x = 16
x= 16 : 2
x = 8
Tìm X
1440 : [ 41 - ( 2x - 5 ) ] = 48
\(1440:\left(41-\left(2x-5\right)\right)=48\)
<=> 41 - 2x + 5 = 1440:48
<=> 46 - 2x = 30
<=> 16 = 2x
<=> x = 8
Vậy x cần tìm là 8
4(x-5)-23=24.3
\(4\left(x-5\right)-2^3=2^4.3\)
\(\Rightarrow4x-20-8=48\)
\(\Rightarrow4x=76\Rightarrow x=19\)
4(x-5) - 2^3 =2^4.3
4(x-5)-2^3=16.3
4(x-5)-2^3=48
4(x-5)=48+2^3
4(x-5)=56
x-5=56:4
x-5=14
x=14+5
x=19
sai mong mn thông cảm nha
4.( 5 - x ) - 23 = 24.3
\(4\cdot\left(5-x\right)-2^3=2^4\cdot3\)
\(\Rightarrow4\cdot\left(5-x\right)-2^3=16\cdot3\)
\(\Rightarrow4\cdot\left(5-x\right)-2^3=48\)
\(\Rightarrow4\cdot\left(5-x\right)=48+8\)
\(\Rightarrow4\cdot\left(5-x\right)=56\)
\(\Rightarrow5-x=56:4\)
\(\Rightarrow5-x=14\)
\(\Rightarrow x=5-14\)
\(\Rightarrow x=-9\)
4(x-5)-16=24.3
\(4\left(x-5\right)-16=24\cdot3\)
\(\Rightarrow4\left(x-5\right)-16=72\)
\(\Rightarrow4\left(x-5\right)=72+16\)
\(\Rightarrow4\left(x-5\right)=88\)
\(\Rightarrow x-5=\dfrac{88}{4}\)
\(\Rightarrow x-5=22\)
\(\Rightarrow x=22+5\)
\(\Rightarrow x=27\)
\(4.\left(x-5\right)-16=24.3\)
\(4.\left(x-5\right)-16=72\)
\(4.\left(x-5\right)=72+16\)
\(4.x-5=88\)
\(x-5=88:4\)
\(x-5=22\)
\(x=22+5\)
\(x=27\)
4(x–5)–23=24.3
\(4\left(x-5\right)-23=24\cdot3\)
\(4\left(x-5\right)-23=72\)
\(4\left(x-5\right)=72+23\)
\(4\left(x-5\right)=95\)
\(x-5=\dfrac{95}{4}\)
\(x=\dfrac{95}{4}+5\)
\(x=\dfrac{115}{4}\)
\(4(x–5)-23=24.3\)
\(4(x–5)-23=72\)
\(4(x–5)=72+23\)
\(4(x-5)=95\)
\(x-5=95:4\)
\(x-5=23,75\)
\(x=23,75+5\)
\(x=28,75\)
4 ( x - 5 ) - 23 = 24 . 3
=> 4(x-5)-23=72
=> 4(x-5)=72+23
=> 4(x-5)=95
=> x-5=95/4
=> x-5 = 23,75
=> x = 23,75 + 5
=>x = 28,75
ai giúp mình bài này với
t) 1440:[ 41 - ( 2x -5)] = 2^4 .3
\(1440:\left[41-\left(2x-5\right)\right]=2^4.3\)
\(\Rightarrow1440:\left[41-\left(2x-5\right)\right]=48\)
\(\Rightarrow41-\left(2x-5\right)=30\)
\(\Rightarrow2x-5=11\)
\(\Rightarrow2x=16\)
\(\Rightarrow x=8\)
Vậy \(x=8\)
\(1440:\left[41-\left(2x-5\right)\right]=2^4\cdot3\)
\(1440:\left[41-\left(2x-5\right)\right]=48\)
\(41-\left(2x-5\right)=\frac{1440}{48}=30\)
\(2x-5=41-30=11\)
\(2x=16\)
\(x=8\)
t) \(1440:\left[41-\left(2x-5\right)\right]=2^4.3\)
\(1440:\left[41-\left(2x-5\right)\right]=16.3\)
\(1440:\left[41-\left(2x-5\right)\right]=48\)
\(41-\left(2x-5\right)=1440:48\)
\(41-\left(2x-5\right)=30\)
\(2x-5=41-30\)
\(2x-5=11\)
\(2x\) \(=11+5\)
\(2x\) \(=16\)
\(x=16:2\)
\(x=8\)
Vậy \(x=8\)
Tim x : 1440:[41-(2x-5)]=24.3 ;5.[225-(x-10)]-125=0
Câu hỏi của một bn
Tim x thuộc N để: 1440 : (41 - (2x - 5)) =2^4.3
Đây chỉ là ý kiến đóng góp thôi nha
1440 : [ 41 - ( 2x-5 ) ] = 2^4.3
1440 : [ 41 - ( 2x-5 ) ] = 16.3
1440 : [ 41 - ( 2x-5 ) ] = 48
[ 41 - ( 2x-5 ) ] = 1440 : 48
[ 41 - ( 2x-5 ) ] = 30
2x-5 = 41-30
2x-5 = 11
2x = 11+5
2x = 16
x = 16:2
x = 8
1440 : [ 41 - ( 2x - 5 ) ] = 2^4 . 3
1440 : [ 41 - ( 2x - 5 ) ] = 16 . 3
1440 : [ 41 - ( 2x - 5 ) ] = 48
41 - ( 2x - 5 ) = 1440 : 48
41 - ( 2x - 5 ) = 30
2x - 5 = 41 - 30
2x - 5 = 11
2x = 11 + 5
2x = 16
x = 16 : 2
x = 8