\(10+2\cdot x=4^5:4^3\)

\(\Rightarrow10+2\cdot x=4^{5-3}\)

\(\Rightarrow10+2\cdot x=4^2\)

\(\Rightarrow10+2\cdot x=16\)

\(\Rightarrow2\cdot x=16-10\)

\(\Rightarrow2\cdot x=6\)

\(\Rightarrow x=\dfrac{6}{2}=3\)

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\(2\cdot x-6^2:18=3\cdot2^2\)

\(\Rightarrow2\cdot x-36:18=12\)

\(\Rightarrow2\cdot x-2=12\)

\(\Rightarrow2\cdot x=12+2\)

\(\Rightarrow2\cdot x=14\)

\(\Rightarrow x=\dfrac{14}{2}=7\)

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\(70-5\cdot\left(x-3\right)=3\cdot2\)

\(\Rightarrow70-5\cdot\left(x-3\right)=6\)

\(\Rightarrow70-5x+15=6\)

\(\Rightarrow-5x+15=6-70\)

\(\Rightarrow-5x+15=64\)

\(\Rightarrow-5x=64-15\)

\(\Rightarrow-5x=49\)

\(\Rightarrow x=-\dfrac{49}{5}\)

giup mink ai nhanh tick 3 lan nghia la 1 lan tra loi mot lan noi lam rui mot lan noi cam on

\(x\)(\(x\) - 2) = 16

\(x^2\) - 2\(x\) - 16 = 0

(\(x^2\) - \(x\)) - (\(x\) - 1) - 17 = 0

\(x\)(\(x\) - 1) - (\(x-1\)) = 17

(\(x\) - 1)(\(x\) - 1) = 17

(\(x-1\))² = 17

\(\left[{}\begin{matrix}x-1=\sqrt{17}\\x-1=-\sqrt{17}\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=1+\sqrt{17}\\x=1-\sqrt{17}\end{matrix}\right.\)

Vậy: \(\in\) {1 - \(\sqrt{17}\); 1 + \(\sqrt{17}\)}

Bài 2:

2^\(x\) + 3.2^\(x\) = 144

2^\(x\).(1 + 3) = 144

2^\(x\).4 = 144

2^\(x\) = 144 : 4

2^\(x\) = 36

2\(^x\) = 36

Nếu \(x\) = 6 ⇒ 2\(^x\) = 64 > 36 (loại)

Nếu \(x\) ≤ 5 ⇒2\(^x\) ≤ 2⁵ = 32 < 36 (loại)

Vậy \(x\in\) \(\varnothing\) 

`=40`

\(=\dfrac{3\cdot2^{x+1}}{2^{x+3}}=\dfrac{3}{2^2}=\dfrac{3}{4}\)

\(2^{x-3}-3.2^x=-92\)

\(\Rightarrow2^x\left(2^{-3}-3\right)=-92\)

\(\Rightarrow2^x.\dfrac{-23}{8}=-92\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\Rightarrow x=5\)

dễ tích mình rồi mình giải cho

a, 10 . 27 - 27 : 9 

= 270 - 3

= 263

b, 7² . 33 + 7² . 67

= 7² ( 33 + 67 )

= 7² . 100

= 49 . 100

= 4900

c, 490 - [ ( 128 + 22 ) : 3 . 2² ] - 7 

= 490 - ( 150 : 3 . 4 ) - 7 

= 490 - ( 50 . 4 ) - 7 

= 490 - 200 - 7

= 290 - 7

= 283

ngoctram sai 

vì 2^x ko pải 2.x nên k đc lấy 36:2

đúng nha

\(\Leftrightarrow\dfrac{3\cdot2^{x+1}}{2^{x+3}}=40\\ \Leftrightarrow\dfrac{3}{2^2}=40\left(vô.lí\right)\Leftrightarrow x\in\varnothing\)