d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)

\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)

hay \(x=\dfrac{25}{372}\)

Vậy: \(x=\dfrac{25}{372}\)

e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)

f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)

\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)

\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)

\(\Leftrightarrow3x=\dfrac{1}{9}\)

hay \(x=\dfrac{1}{27}\)

g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)

\(\Leftrightarrow\dfrac{4}{3}x=2\)

hay \(x=\dfrac{3}{2}\)

Vậy: \(x=\dfrac{3}{2}\)

h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)

  Vậy ...

i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)

  Vậy ...

Quy đồng \(\frac{37}{42}=\frac{37\times32}{42\times32}=\frac{1184}{1344};\frac{41-x}{32}=\frac{42\times\left(41-x\right)}{42\times32}=\frac{42\times\left(41-x\right)}{1344}\)

\(\frac{37}{42}=\frac{41-x}{32}\) nên  \(\frac{1184}{1344}=\frac{42\times\left(41-x\right)}{1344}\)

=>   42 x (41 - \(x\)) = 1184

    42 x 41 - 42 x \(x\) = 1184

    1722 - 42 x \(x\) = 1184

   42 x \(x\) = 1722 - 1184 

   42 x \(x\) = 538 

   \(x\) = 538 / 42 =  269 / 21

20+4(x-2)=32

4(x-2)=32-20=12

x-2=12:4=3

x=3+2=5

37-4x=2mũ0x3mũ2

37-4x=1x9=9

4x=37-9=28

x=28:4=7

a) \(20+4\left(x-2\right)=32\)

\(\Rightarrow20+4x-8=32\)

\(\Rightarrow20+4x=40\)

\(\Rightarrow4x=20\Leftrightarrow x=20:4=5\)

b)  \(37-4x=2^0.3^2\)

\(\Rightarrow37-4x=1.9\)

\(\Leftrightarrow37-4x=9\)

\(\Leftrightarrow4x=28\)

\(\Leftrightarrow x=7\)

_Chúc bạn học tốt _

32x62+32x37+32

=32x62+32x37+32x1

=32x(62+37+1)

=3200

32.62+32.37+32

=32.62+32.37+32.1

=32.(62+37+1)

=3200

tick mk nha

hok tốt

@Lâm

(1900 - 2x) : 35 - 32 = 16

=> (1900 - 2x)  : 35 = 48

=> 1900 - 2x = 1680

=> 2x = 220

=> x = 110

vậy_

111 + 1818 : (6x - 37) = 129

=> 1818 : (6x - 37) = 18

=> 6x - 37 = 101

=> 6x = 138

=> x = 23

vậy_

(x : 3 + 45) x 67 - 31 = 8880

=> (x : 3 + 45) x 67 = 8911

=> x : 3 + 45 = 133

=> x : 3 + = 88

=>x = 264

vậy_

1)\(x-105:21=15\)

\(x-5=15\)

\(x=15+5\)

\(x=20\)

Vậy \(x=20.\)

2)\(\left(x-105\right):21=15\)

\(\left(x-105\right)=15.21\)

\(x-105=315\)

\(x=315+105\)

\(x=420\)

Vậy \(x=412.\)

4)\(1818:\left(6x-37\right)=18\)

\(6x-37=1818:18\)

\(6x-37=101\)

\(6x=101+37\)

\(6x=138\)

\(x=138:6\)

\(x=23\)

Vậy \(x=23.\)

mk quên,còn phần 3) nữa:

3)\(\left(32+x\right):17=x\)

\(32+x=x.17\)

\(\Leftrightarrow x=2\)

Vậy \(x=2.\)

Bài làm :

\(a,23+x:2=37\)

\(x:2=14\)

\(x=14\times2\)

\(x=28\)

\(b,x-320:32=4\times16\)

\(x-10=64\)

\(x=64+10\)

\(x=74\)

\(c,3x-2018:2=23\)

\(3x-1009=23\)

\(3x=23+1009\)

\(3x=1032\)

\(x=344\)

\(d,\left(9x-21\right):3=2\)

\(9x-21=6\)

\(9x=6+21\)

\(9x=27\)

\(x=3\)

\(e,15:x+120:12=15\)

\(15:x+10=15\)

\(15:x=15-10\)

\(15:x=5\)

\(x=3\)

Học tốt nhé

\(\left|x+\frac{3}{4}\right|-\frac{1}{3}=0\)

\(\left|x+\frac{3}{4}\right|=\frac{1}{3}\)

\(\Rightarrow x+\frac{3}{4}=\pm\frac{1}{3}\)

\(\cdot x+\frac{3}{4}=\frac{1}{3}\)

\(x=-\frac{5}{12}\)

\(\cdot x+\frac{3}{4}=-\frac{1}{3}\)

\(x=-\frac{13}{12}\)

ảo ảo ảo