`x xx 3/4 =11/4`

`=> x=11/4 :3/4`

`=> x=11/4 xx 4/3`

`=> x= 44/12`

`=>x= 11/3`

Vậy `x=11/3`

Lời giải:

$x\times \frac{3}{4}=\frac{11}{4}$

$x=\frac{11}{4}: \frac{3}{4}=\frac{11}{3}$

=>4x-8=3x+3

=>4x-3x=8+3

=>x=11

\(\dfrac{4\left(x-2\right)}{12}=\dfrac{3\left(x+1\right)}{12}\\ 4x-8-3x-3=0\\ x-11=0\\ x=11\)

\(\dfrac{x-2}{3}=\dfrac{x+1}{4}\)

\(\Leftrightarrow\dfrac{x-2}{3}-\dfrac{x+1}{4}=0\)

\(\Leftrightarrow\dfrac{4\left(x-2\right)-3\left(x+1\right)}{12}=0\)

\(\Leftrightarrow4x-8-3x-3=0\)

\(\Leftrightarrow x-11=0\)

\(\Leftrightarrow x=11\)

\(\Rightarrow\dfrac{x+2}{4}< 0\Leftrightarrow x+2>0\Leftrightarrow x>-2\)

Để C<0 thì x+3<0

hay x<-3

\(C=\dfrac{1}{x}+\dfrac{x}{16}+\dfrac{15}{16}x\ge2\sqrt{\dfrac{1}{x}.\dfrac{x}{16}}+\dfrac{15}{16}.4=\dfrac{1}{2}+\dfrac{15}{4}=\dfrac{17}{4}\)

dấu = xảy ra khi x=4

\(x+\dfrac{1}{x}=\dfrac{1}{16}x+\dfrac{1}{x}+\dfrac{15}{16}x\ge2\sqrt{\dfrac{x}{16x}}+\dfrac{15}{16}.4=\dfrac{1}{2}+\dfrac{15}{4}=\dfrac{17}{4}\)

\(minC=\dfrac{17}{4}\Leftrightarrow x=4\)

\(C=x+\dfrac{1}{x}=\dfrac{x}{16}+\dfrac{1}{x}+\dfrac{15x}{16}\ge2\sqrt{\dfrac{1}{16}}+\dfrac{15.4}{16}=\dfrac{17}{4}\)

dấu"=" xảy ra<=>x=4

Để \(B< 0\) mà 30>0\(\Rightarrow x-2< 0\Rightarrow x< 2\)

x\(\le\)31 (\(\forall\)x)
và x\(\notin\left\{-4,4\right\}\) thì B<0

1/2 . x - 1/3 = 1/4 + 3/2

1/2 . x - 1/3 = 7/4

1/2 . x = 7/4 + 1/3

1/2 . x = 25/12

x = 25/12 : 1/2

x = 25/6

vậy x  = ...

\(1\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)-\dfrac{3}{2}=\dfrac{1}{4}\)

\(\Leftrightarrow1\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)=\dfrac{1}{4}+\dfrac{3}{2}\)

\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{7}{4}\)

\(\Leftrightarrow\dfrac{1}{2}x=\dfrac{25}{12}\)

\(\Leftrightarrow x=\dfrac{25}{6}\)