\(1,\left(\left(3\cdot\left(3x+2\right)\right)+4\cdot\left(x+2\right)\right)-90=0.\)

\(13x-76=0\)

\(13x=76\)

\(x=\frac{76}{13}\)

\(2,\left(\left(5\cdot\left(x+1\right)\right)+3\cdot\left(2x+1\right)\right)-65=0\)

\(11x-57=0\)

\(11x=57\)

\(x=\frac{57}{11}\)

\(3,\left(\left(3\cdot\left(3x+4\right)\right)+5\cdot\left(2x+1\right)\right)-100=0\)

\(19x-83=0\)

\(19x=83\)

\(x=\frac{83}{19}\)

mik ko chắc kết quả nhé

bn xem đúng ko nhé

học tốt

1) 3.(3x+2) + 2.(2x+4) = 90

9x + 6 + 4x + 8 = 90

13x + 14 = 90

13x = 76

x = 76/13

các bài còn lại làm tương tự nha bn!
 

\(\text{ 11x − 3x = 60 + 2x}\).

\(\Leftrightarrow\) \(8x-2x=60.\Leftrightarrow6x=60.\Leftrightarrow x=10.\)

\(2x+5=60-\left(3x-25\right)\\ \Leftrightarrow2x+5=60-3x+25\\ \Leftrightarrow2x+3x=60+25-5\\ \Leftrightarrow5x=80\\ \Leftrightarrow x=16\)

2x + 5 = 60 - 3x + 25

2x + 5 = 85 - 3x

2x + 3x = 85 - 5

5x = 80

 x = 80 : 5

 x = 16

2x+5=60−(3x−25)

⇔2x+5=60−3x+25

⇔2x+3x=60+25−5

⇔5x=80

⇔x=16

3x + ( 2x + 10 ) = 60

3x + 2x + 10     = 60

        5x             = 60 - 10

        5x             = 50

          x             = 10

3x+(2x+10)=60

=3x+2x+10=60

=x(3+2)+10=60

=x5=60-10

=x5=50

x=50:5

x=10

a/ => 2x - 4 = 2² = 4

=> 2x = 8

=> x = 4

b/ => 60 : 2x = 10

=> 2x = 6

=> x = 3

c/ => 5(2x - 3) = 25

=> 2x - 3 = 5

=> 2x = 8

=> x = 4

d/ => 3x - 6 = 3⁴ : 3 = 3³ = 27

=> 3x = 33

=> x = 11