1-2-3+4+5-6-7+8+...+197-198-199+200

=(1-2-3+4)+(5-6-7+8)+...+(197-198-199+200)

=0+0+...+0

=0

gshegs

\(\frac{197}{198}< 1\)

\(\frac{2019}{2020}< 1< \frac{3}{2}\Rightarrow\frac{2019}{2020}< \frac{3}{2}\)

\(\frac{201}{301}< 1< \frac{199}{198}\Rightarrow\frac{201}{301}< \frac{199}{198}\)

196/197 + 197/198 > 198/199 + 199/197

a: 9/11=1-2/11

11/13=1-2/13

mà -2/11<-2/13

nên 9/11<11/13

b: 19/15=1+4/15

15/11=1+4/11

mà 4/15<4/11

nên 19/15<15/11

so sáng qua phân số trung gian: \(\dfrac{47}{73}\)

có

\(\dfrac{47}{70}>\dfrac{47}{73}\)

\(\dfrac{39}{73}< \dfrac{47}{73}\)

\(=>\dfrac{47}{70}>\dfrac{39}{73}\)

Ta có:
\(\dfrac{47}{70}>\dfrac{47}{73}\)
\(\dfrac{47}{73}>\dfrac{39}{73}\)
\(\Rightarrow\dfrac{47}{70}>\dfrac{39}{73}\)

a.\(\dfrac{12}{16}=\dfrac{3}{4}\)

\(V\text{ì}\dfrac{3}{4}< \dfrac{5}{4}=>\dfrac{12}{16}< \dfrac{5}{4}\)

b. \(\dfrac{4}{3}>1\) ; \(\dfrac{98}{99}< 1\)

\(=>\dfrac{98}{99}< 1< \dfrac{4}{3}\)

\(=>\dfrac{98}{99}< \dfrac{4}{3}\)

c. \(\dfrac{6}{7}< 1\) ; \(\dfrac{7}{6}>1\)

\(=>\dfrac{6}{7}< 1< \dfrac{7}{6}\)

\(=>\dfrac{6}{7}< \dfrac{7}{6}\)

a: 5/4>1>12/16

b: 4/3>1>98/99

c: 6/7<1<7/6

Trả lời giúp mình với

Ta có: 3/7=24/56>14/56=2/8>1/8

=>3/7>1/8

C1: Ta có: \(\frac{3}{7}=\frac{24}{56};\frac{1}{8}=\frac{7}{56}\)

Mà \(\frac{24}{56}>\frac{7}{56}\)

\(\Rightarrow\frac{3}{7}>\frac{1}{8}\)

C2: Ta có: \(\frac{3}{7}>\frac{1}{7}\)(so sánh 2 PS cùng mẫu)

                \(\frac{1}{8}<\frac{1}{7}\)(so sánh 2 PS cùng tử)

\(\Rightarrow\frac{3}{7}>\frac{1}{7}>\frac{1}{8}\)

\(\Rightarrow\frac{3}{7}>\frac{1}{8}\)

\(\dfrac{426}{800}>\dfrac{315}{815}\)

351/815 < 426/800

<