Lời giải:

a. PT $\Leftrightarrow (3-2x-3-2x)(3-2x+3+2x)=8$

$\Leftrightarrow -4x.6=8$

$\Leftrightarrow -24x=8\Leftrightarrow x=\frac{-1}{3}$

b.

$9x^5-72x^2=0$

$\Leftrightarrow 9x^2(x^3-8)=0$

$\Leftrightarrow x^2=0$ hoặc $x^3=8$

$\Leftrightarrow x=0$ hoặc $x=2$

c.

$5x^4-8x^2-4=0$

$\Leftrightarrow 5x^4-10x^2+2x^2-4=0$

$\Leftrightarrow 5x^2(x^2-2)+2(x^2-2)=0$

$\Leftrightarrow (5x^2+2)(x^2-2)=0$

$\Leftrightarrow 5x^2+2=0$ (loại) hoặc $x^2-2=0$ (chọn)

$\Leftrightarrow x=\pm \sqrt{2}$

d.

PT $\Leftrightarrow [x^2(x+1)-4(x+1)]:(x-2)=0$

$\Leftrightarrow (x^2-4)(x+1):(x-2)=0$

$\Leftrightarrow (x-2)(x+2)(x+1):(x-2)=0$
$\Leftrightarrow (x+2)(x+1)=0$

$\Leftrightarrow x+2=0$ hoặc $x+1=0$

$\Leftrightarrow x=-2$ hoặc $x=-1$

a: Ta có: \(\left(3-2x\right)^2-\left(3+2x\right)^2=8\)

\(\Leftrightarrow9-12x+4x^2-9-12x-4x^2=8\)

\(\Leftrightarrow-24x=8\)

hay \(x=-\dfrac{1}{3}\)

b: Ta có: \(9x^5-72x^2=0\)

\(\Leftrightarrow9x^2\left(x^3-8\right)=0\)

\(\Leftrightarrow x^2\left(x-2\right)\left(x^2+2x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

c: Ta có: \(5x^4-8x^2-4=0\)

\(\Leftrightarrow5x^4-10x^2+2x^2-4=0\)

\(\Leftrightarrow x^2-2=0\)

hay \(x\in\left\{\sqrt{2};-\sqrt{2}\right\}\)

vvvvvvvvvvvvvvvv

8/13+4/9+1/3+5/13+3=

(8/13+5/13)+(4/9+3/9)+3=

1+7/9+3=4 7/9

8/5x4/7+4/7x2/5=

4/7x(8/5+2/5)

=4/7x2=8/7

a) kết quả bằng  43/9

b) hiện tại chưa tính ra

\(a,\dfrac{7}{9}\times\dfrac{3}{14}:\dfrac{5}{8}=\dfrac{7}{9}\times\dfrac{3}{14}\times\dfrac{8}{5}=\dfrac{4}{15}\)

\(b,\dfrac{3}{5}\times\dfrac{4}{21}\times\dfrac{25}{3}=\dfrac{20}{21}\)

\(c,\dfrac{15}{16}:\dfrac{5}{8}\times\dfrac{3}{4}=\dfrac{15}{16}\times\dfrac{8}{5}\times\dfrac{3}{4}=\dfrac{9}{8}\)

\(d,\dfrac{21}{4}\times\dfrac{16}{14}\times\dfrac{1}{2}\times\dfrac{8}{3}=8\)

Lời giải:

\(\frac{4}{9}\times \frac{3}{7}\times \frac{7}{4}=\frac{1}{3}\)

\(\frac{6}{5}\times \frac{4}{5}\times \frac{25}{16}=\frac{3}{2}\)

\(\frac{7}{8}\times \frac{16}{9}\times \frac{3}{14}=\frac{1}{3}\)

= 16/25 x 3,14

=2,0096

\(\dfrac{4}{5}x\dfrac{4}{5}x3,14\)

= \(\dfrac{16}{25}x3,14\)

= \(2,0096\)

ĐÁP ÁN :

= 2,0096

HT 

a) \(3x4^{x+1}-5.4^x=448\)

\(\Leftrightarrow4^x\left(3x4-5\right)=448\)

\(\Leftrightarrow4^x.7=448\)

\(\Leftrightarrow4^x=64=4^3\)

\(\Leftrightarrow x=3\)

b) \(5.\left(x-2\right)^3=4^3+71\left(x>1\right)\)

\(\Leftrightarrow5.\left(x-2\right)^3=64+71\)

\(\Leftrightarrow5.\left(x-2\right)^3=135\)

\(\Leftrightarrow\left(x-2\right)^3=27=3^3\)

\(\Leftrightarrow x-2=3\)

\(\Leftrightarrow x=5\)