\(\left(3x-1\right)^3=125\)
ND
Những câu hỏi liên quan
Tìm số tự nhiên x , biết
\(2\cdot\left(x-1\right)^2=8\)
\(\left(2x+1\right)^3=125\)
\(\left(x-2\right)^5=243\)
\(5\left(x-4\right)^2-7=13\)
\(221-\left(3x+2\right)^3=96\)
Giải pt:
a, \(\dfrac{1}{27}.\left(x-3\right)^2-\dfrac{1}{125}.\left(x-5\right)^3=0\)
b, \(125x^3-\left(2x+1\right)^3-\left(3x-1\right)^3=0\)
c, \(\left(x-3\right)^3+\left(x+1\right)^3=8.\left(x-1\right)^3\)
a: \(\Leftrightarrow\left(\dfrac{1}{3}x-1\right)^3=\left(\dfrac{1}{5}x-1\right)^3\)
=>1/3x-1=1/5x-1
=>2/15x=0
hay x=0
b: Đặt 2x+1=a; 3x-1=b
Theo đề, ta có \(\left(a+b\right)^3-a^3-b^3=0\)
=>3ab(a+b)=0
=>5x(2x+1)(3x-1)=0
hay \(x\in\left\{0;-\dfrac{1}{2};\dfrac{1}{3}\right\}\)
c: Đặt x-3=a; x+1=b
Theo đề, ta có: \(\left(a+b\right)^3=a^3+b^3\)
=>3ab(a+b)=0
=>(x-3)(x+1)(2x-2)=0
hay \(x\in\left\{3;-1;1\right\}\)
Đúng 0
Bình luận (0)
Tính giá trị của biểu thức \(A=\left(\frac{1}{125}-\frac{1}{1^3}\right).\left(\frac{1}{125}-\frac{1}{2^3}\right).\left(\frac{1}{125}-\frac{1}{3^3}\right)...\left(\frac{1}{125}-\frac{1}{19^3}\right).\left(\frac{1}{125}-\frac{1}{20^3}\right)\)
Tính \(C=\left(\frac{1}{125}-\frac{1}{1^3}\right)\left(\frac{1}{125}-\frac{1}{2^3}\right)\left(\frac{1}{125}-\frac{1}{3^3}\right)...\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
Tính nhanh A=\(\left(\dfrac{1}{125}-\dfrac{1}{1^3}\right)\left(\dfrac{1}{125}-\dfrac{1}{2^3}\right)\left(\dfrac{1}{125}-\dfrac{1}{3^3}\right)...\left(\dfrac{1}{125}-\dfrac{1}{25^3}\right)\)
\(A=\left(\dfrac{1}{125}-\dfrac{1}{1^3}\right)\left(\dfrac{1}{125}-\dfrac{1}{2^3}\right)\left(\dfrac{1}{125}-\dfrac{1}{3^3}\right)....\left(\dfrac{1}{125}-\dfrac{1}{25^3}\right)\)
\(A=\left(\dfrac{1}{125}-\dfrac{1}{1^3}\right)\left(\dfrac{1}{125}-\dfrac{1}{2^3}\right)....\left(\dfrac{1}{125}-\dfrac{1}{5^3}\right).....\left(\dfrac{1}{125}-\dfrac{1}{25^3}\right)\)
\(A=\left(\dfrac{1}{125}-\dfrac{1}{1^3}\right)\left(\dfrac{1}{125}-\dfrac{1}{2^3}\right)....0......\left(\dfrac{1}{125}-\dfrac{1}{25^3}\right)\)
\(A=0\)
Đúng 0
Bình luận (0)
Tính nhanh : A= \(\left(\frac{1}{125}-\frac{1}{1^3}\right)\cdot\left(\frac{1}{125}-\frac{1}{2^3}\right)\cdot\left(\frac{1}{125}-\frac{1}{3^3}\right).....\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
\(=\)\(\left(\frac{1}{125}-\frac{1}{1^3}\right)\) \(.\) \(\left(\frac{1}{125}-\frac{1}{2^3}\right)\) \(.\) \(\left(\frac{1}{125}-\frac{1}{3^3}\right)\) \(.\) \(\left(\frac{1}{125}-\frac{1}{5^3}\right)\)\(...\) \(\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
\(=\) \(\left(\frac{1}{125}-\frac{1}{1^3}\right)\) \(.\) \(\left(\frac{1}{125}-\frac{1}{2^3}\right)\) \(.\) \(\left(\frac{1}{125}-\frac{1}{3^3}\right)\) \(.\) \(0\) \(....\) \(\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
\(=\) \(0\)
\(\frac{3}{14}:\frac{6x}{15}=\frac{7}{8}\)
\(\left(3x-\frac{2}{15}\right)^3=\frac{8}{125}\)
\(|1-3x|-\left(-\frac{1}{2}\right)=\frac{5}{3}\)
Giải phương trìnha. frac{1}{27}cdotleft(x-3right)^3-frac{1}{125}cdotleft(x-5right)^30b.125x^3-left(2x+1right)^3-left(3x-1right)^30c.left(x-3right)^3+left(x+1right)^38cdotleft(x-1right)^3d.left(x^2-3x+2right)cdotleft(x^2+15x+56right)+80e.left(2x^2-3x+1right)cdotleft(2x^2+5x+1right)-9x^20f.left(x+6right)^4+left(x+8right)^4272
Đọc tiếp
Giải phương trình
a. \(\frac{1}{27}\cdot\left(x-3\right)^3-\frac{1}{125}\cdot\left(x-5\right)^3=0\)
b.\(125x^3-\left(2x+1\right)^3-\left(3x-1\right)^3=0\)
c.\(\left(x-3\right)^3+\left(x+1\right)^3=8\cdot\left(x-1\right)^3\)
d.\(\left(x^2-3x+2\right)\cdot\left(x^2+15x+56\right)+8=0\)
e.\(\left(2x^2-3x+1\right)\cdot\left(2x^2+5x+1\right)-9x^2=0\)
f.\(\left(x+6\right)^4+\left(x+8\right)^4=272\)
TÍNH NHANH
\(\left(\frac{1}{125}-\frac{1}{1^3}\right)\cdot\left(\frac{1}{125}-\frac{1}{2^3}\right)\cdot\left(\frac{1}{125}-\frac{1}{3^3}\right)\cdot\cdot\cdot\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
\(\left(\frac{1}{125}-\frac{1}{1^3}\right)\left(\frac{1}{125}-\frac{1}{2^3}\right)...\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
\(=\left(\frac{1}{125}-\frac{1}{1^3}\right)\left(\frac{1}{125}-\frac{1}{2^3}\right)...\left(\frac{1}{125}-\frac{1}{5^3}\right)...\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
\(=\left(\frac{1}{125}-\frac{1}{1^3}\right)\left(\frac{1}{125}-\frac{1}{2^3}\right)...0...\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
\(=0\)
Đúng 0
Bình luận (0)