\(y:0,1-y:4-y\times\dfrac{3}{4}=2,25\)

\(y\times10-y\times\dfrac{1}{4}-y\times\dfrac{3}{4}=2,25\)

\(y\times(10-\dfrac{1}{4}-\dfrac{3}{4})=2,25\)

\(y\times9=2,25\)

\(y=2,25:9=0,25\)

y x 10 - y x \(\frac{1}{4}\)- y x\(\frac{3}{4}\)= 1,25

y x (10 - \(\frac{1}{4}\)- \(\frac{3}{4}\)) = 1,25

y x 9 = 1,25

y = 1,25 : 9

y = \(\frac{5}{36}\)

=>10y-4y-3/4y=42

=>21/4y=42

hay y=8

-786/5

786/5

\(y=-\dfrac{786}{5}\)

Ta có : \(y:\frac{1}{10}-y:4-y:\frac{3}{4}=2,25\)

        \(\Leftrightarrow y.10-y.\frac{1}{4}-y.\frac{4}{3}=2,25\)

        \(\Leftrightarrow y\left(10-\frac{1}{4}-\frac{4}{3}\right)=2,25\)

        \(\Leftrightarrow y.\frac{101}{12}=\frac{27}{12}\)

        \(y=\frac{27}{12}:\frac{101}{12}=\frac{27}{101}\)

Vậy y=\(\frac{27}{101}\)