Làm ơn ai đó giúp mình đi mình còn 7 phút hà TvT

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Bài 5. a) \(A=1+2+2^2+2^3+...+2^{2021}\)

\(\Rightarrow2A=2+2^2+2^3+2^4+...+2^{2022}\)

\(\Rightarrow A=2A-A=\left(2+2^2+2^3+2^4+...+2^{2022}\right)-\left(1+2+2^2+2^3+...+2^{2021}\right)\)

\(=2^{2022}-1\)

\(\Rightarrow2A=2.\left(2^{2022}-1\right)=2^{2023}-2\)

b) Đề sai, phải là A = 2²⁰²² - 1

A

A

A

KHÓC HẾT NƯỚC MẮT...

\(a,\dfrac{5}{4}+\dfrac{3}{8}=\dfrac{10}{8}+\dfrac{3}{8}=\dfrac{13}{8}\)

\(b,\dfrac{2}{3}-\dfrac{3}{8}=\dfrac{16}{24}-\dfrac{9}{24}=\dfrac{7}{24}\)

\(c,\dfrac{5}{7}\times4=\dfrac{20}{7}\)

\(d,\dfrac{9}{11}:\dfrac{2}{7}=\dfrac{9}{11}\times\dfrac{7}{2}=\dfrac{63}{22}\)

\(a,\dfrac{13}{8}b,\dfrac{7}{24}c,\dfrac{20}{7}d,\dfrac{63}{22}\)

a)\(\dfrac{5}{4}+\dfrac{3}{8}=\dfrac{10}{8}+\dfrac{3}{8}=\dfrac{13}{8}\)

b) \(\dfrac{2}{3}-\dfrac{3}{8}=\dfrac{16}{24}-\dfrac{9}{24}=\dfrac{7}{24}\)

c) \(\dfrac{5}{7}\times4=\dfrac{20}{7}\)

d) \(\dfrac{9}{11}\div\dfrac{2}{7}=\dfrac{9}{11}\times\dfrac{7}{2}=\dfrac{63}{22}\)

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