185 x 99 + 15 x 49 + 185 x 1 + 15 x 51 =

185 x ( 99 + 1 ) + 15  x (51 + 49) =

185 x 100 + 15 x 100 = 

100 x  (185 + 15) = 

100 x 200 = 20 000

=185x(99+1)+15x(49+51)

=185x100+15x100

=(185+15)x100

=200x100

=20000

185 x 99 + 15 x 49 + 185 x 1 + 15 x 51 =

185 x ( 99 + 1 ) + 15  x (51 + 49) =

185 x 100 + 15 x 100 = 

100 x  (185 + 15) = 

100 x 200 = 20 000

Ai nhanh nhất k nhiều nhất nhé

Bài này đề bài là tìm x

Bài 1L

a) \(\left(x-7\right)\left(x+3\right)< 0\)

TH1:

\(\hept{\begin{cases}x-7>0\\x+3< 0\end{cases}\Leftrightarrow\hept{\begin{cases}x>7\\x< -3\end{cases}}}\)( loại )

TH2:

\(\hept{\begin{cases}x-7< 0\\x+3>0\end{cases}\Leftrightarrow\hept{\begin{cases}x< 7\\x>-3\end{cases}\Leftrightarrow}-3< x< 7}\)( chọn )

Vậy \(-3< x< 7\)

Bài 2:

a) \(\left(5x+8\right)-\left(2x-15\right)+21=2x-5\)

\(\Leftrightarrow5x+8-2x+15+21=2x-5\)

\(\Leftrightarrow5x-2x-2x=-5-21-8-15\)

\(\Leftrightarrow x=-49\)

Vậy ...

Bài 1:

b) \(\left(2x+6\right)\left(x-5\right)\le0\)

TH1:

\(\hept{\begin{cases}2x+6\le0\\x-5\ge0\end{cases}\Leftrightarrow\hept{\begin{cases}x\le-3\\x\ge5\end{cases}}}\)( loại )

TH2:

\(\hept{\begin{cases}2x+6\ge0\\x-5\le0\end{cases}\Leftrightarrow\hept{\begin{cases}x\ge-3\\x\le5\end{cases}\Leftrightarrow}-3\le x\le5}\)

Vậy \(-3\le x\le5\)

* \(20+65.4=\left(x+75\right):5+30\)

\(\Leftrightarrow20+260-30=\frac{x}{5}+\frac{75}{5}\)

\(\Leftrightarrow20+260-30-\frac{75}{5}=\frac{x}{5}\)

\(\Leftrightarrow235=\frac{x}{5}\Rightarrow x=235.5=1175\)

* \(2248:\left[119-\left(x-6\right)\right]=24\)

\(\Leftrightarrow2248:\left(119-x+6\right)=24\)

\(\Leftrightarrow2248:\left(125-x\right)=24\)

A mình lỡ tay, để mình tính tiếp nhá!

\(\Leftrightarrow125-x=2248:24\Leftrightarrow125-x=\frac{281}{3}\Rightarrow-x=\frac{94}{3}\Rightarrow x=-\frac{94}{3}\)(bài này mình thấy sai sai sao á, nếu mình làm sai thì thông cảm cho mình nhé!

* \(\left(x+70\right):14-40=\left(32.15\right):2\)

\(\Leftrightarrow\left(x+70\right):14=480:2+40\)

\(\Leftrightarrow\frac{x}{14}+5=280\Leftrightarrow\frac{x}{14}=275\Rightarrow x=3850\)

* \(x-4867=\left(175.2050.70\right):25+23\)

\(\Leftrightarrow x-4867-23=\left(175:25\right).\left(2050:25\right).\left(70:25\right)\)

\(\Leftrightarrow x-4890=7.82.\frac{14}{5}\)

\(\Leftrightarrow x-4890=\frac{8036}{5}\Rightarrow x=\frac{8036}{5}+4890=\frac{32486}{5}\)(bài này mình thấy hình như cũng có cái gì đó sai sai luôn hihi!)

=24 nha

a, \(2x+3=15\Leftrightarrow x=6\)

b, \(2\left(42-x\right)=23\Leftrightarrow84-2x=23\Leftrightarrow x=\frac{61}{2}\)

c, \(2,5x+2,3x=144\Leftrightarrow x\left(2,5+2,3\right)=144\Leftrightarrow x=30\)

a,2 x  X+3=15                  b,

2 x X =15-3

2 x X=12

X=12 : 2

X=6

2×x+3=15

2×x=15-3

2×x=12

x=12:2

x=6

vậy x=6

2×(42-x)=23

(42-x)=23×2

(42-x)=46

x=42-46

x=-4

vậy x=-4

2,5×x+2,3×x=144

x×(2,5+2,3)=144

x×4,8=144

x=144:4,8

x=30

vậy x=30

=> 72 - 20x - 36x - 84 = 30x - 240 - 6x + 84

=> (72 - 84 )  - (20x + 36x ) = (30x - 6x ) - 240 + 84

=> -12 - 56x = 24x - 156

=> -12 + 156 = 24x + 56x 

=> 144 = 80x

=> x = 144  : 80

=> x = 9/5

=> 72 - 20x - 36x - 84 = 30x - 240 - 6x + 84

=> (72 - 84 )  - (20x + 36x ) = (30x - 6x ) - 240 + 84

=> -12 - 56x = 24x - 156

=> -12 + 156 = 24x + 56x 

=> 144 = 80x

=> x = 144  : 80

=> x = 9/5

a: \(x+6\dfrac{1}{8}=8\)

=>\(x+\dfrac{49}{8}=\dfrac{64}{8}\)

=>\(x=\dfrac{64}{8}-\dfrac{49}{8}=\dfrac{15}{8}\)

b: \(\dfrac{11}{2}\cdot x=\dfrac{1}{5}:\dfrac{1}{3}\)

=>\(x\cdot\dfrac{11}{2}=\dfrac{1}{5}\cdot3=\dfrac{3}{5}\)

=>\(x=\dfrac{3}{5}:\dfrac{11}{2}=\dfrac{3}{5}\cdot\dfrac{2}{11}=\dfrac{6}{55}\)

c: \(x\cdot\dfrac{3}{5}+\dfrac{2}{5}\cdot x=\dfrac{4}{9}+\dfrac{1}{3}\)

=>\(x\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{4}{9}+\dfrac{3}{9}\)

=>\(x\cdot1=\dfrac{7}{9}\)

=>\(x=\dfrac{7}{9}\)

a: \(\dfrac{5}{3}\cdot\dfrac{7}{10}=\dfrac{5}{10}\cdot\dfrac{7}{3}=\dfrac{14}{3}>2\)

\(\dfrac{5}{7}:\dfrac{7}{10}=\dfrac{5}{7}\cdot\dfrac{10}{7}=\dfrac{50}{49}< 2\)

=>\(\dfrac{5}{3}\cdot\dfrac{7}{10}>\dfrac{5}{7}:\dfrac{7}{10}\)

b: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)

\(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{8}{4}\cdot\dfrac{3}{9}=\dfrac{2}{3}\)

Do đó: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{8}{9}:\dfrac{4}{3}\)

c: \(\dfrac{5}{11}\cdot\dfrac{33}{15}=\dfrac{5}{15}\cdot\dfrac{33}{11}=\dfrac{3}{3}=1\)

\(\dfrac{6}{17}\cdot\dfrac{34}{25}=\dfrac{34}{17}\cdot\dfrac{6}{25}=2\cdot\dfrac{6}{25}=\dfrac{12}{25}< 1\)

=>\(\dfrac{5}{11}\cdot\dfrac{33}{15}>\dfrac{6}{17}\cdot\dfrac{34}{25}\)

d: \(\dfrac{15}{19}\cdot\dfrac{38}{5}=\dfrac{15}{5}\cdot\dfrac{38}{19}=3\cdot2=6\)

\(\dfrac{15}{16}:\dfrac{3}{8}=\dfrac{15}{16}\cdot\dfrac{8}{3}=\dfrac{15}{3}\cdot\dfrac{8}{16}=\dfrac{5}{2}\)<6

=>\(\dfrac{15}{19}\cdot\dfrac{38}{5}>\dfrac{15}{16}:\dfrac{3}{8}\)