7/3x1/2+1/7
2 1/3x1/5+7/3=,,,
cho em câu trả lời cuối cùng
TL
37/15
HT
a, 1/2 x 1/3 + 1/3x1/4 +1/4 x 1/5 + 1/5 x 1/6 + 1/6 x 1/7 + 1/7 x 1/8 + 1/8 x 1/9 = ?
\(\frac{1}{2}\times\frac{1}{3}+\frac{1}{3}\times\frac{1}{4}+...+\frac{1}{8}\times\frac{1}{9}=\frac{1}{2\times3}+\frac{1}{3\times4}+....+\frac{1}{8\times9}\)
\(=\frac{1}{2}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-....-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}=\frac{1}{2}-\frac{1}{9}=\frac{7}{18}\)
Tính:
a) 11/3-2/3x5/6. b) 13/2+7/6:2/3
c) 28/9-3/4+1/3. d) 5/8:2/3x1/5
a) \(\dfrac{11}{3}-\dfrac{2}{3}\times\dfrac{5}{6}\)
\(=\dfrac{11}{3}-\dfrac{10}{18}\)
\(=\dfrac{11}{3}-\dfrac{5}{9}\)
\(=\dfrac{33}{9}-\dfrac{5}{9}\)
\(=\dfrac{28}{9}\)
b) \(\dfrac{13}{2}+\dfrac{7}{6}:\dfrac{2}{3}\)
\(=\dfrac{13}{2}+\dfrac{7}{6}\cdot\dfrac{3}{2}\)
\(=\dfrac{13}{2}+\dfrac{7}{4}\)
\(=\dfrac{26}{4}+\dfrac{7}{4}\)
\(=\dfrac{33}{4}\)
c) \(\dfrac{28}{9}-\dfrac{3}{4}+\dfrac{1}{3}\)
\(=\dfrac{28}{9}+\dfrac{3}{9}-\dfrac{3}{4}\)
\(=\dfrac{31}{9}-\dfrac{3}{4}\)
\(=\dfrac{124}{36}-\dfrac{27}{36}\)
\(=\dfrac{97}{36}\)
d) \(\dfrac{5}{8}:\dfrac{2}{3}\times\dfrac{1}{5}\)
\(=\dfrac{5}{8}\times\dfrac{3}{2}\times\dfrac{1}{5}\)
\(=\dfrac{15}{80}\)
\(=\dfrac{3}{16}\)
a) \(\dfrac{11}{3}-\dfrac{2}{3}\times\dfrac{5}{6}=\dfrac{11}{3}-\dfrac{5}{9}=\dfrac{28}{9}\)
b) \(\dfrac{13}{2}+\dfrac{7}{6}:\dfrac{2}{3}=\dfrac{13}{2}+\dfrac{7}{6}\times\dfrac{3}{2}=\dfrac{13}{2}+\dfrac{7}{4}=\dfrac{33}{4}\)
c) \(\dfrac{28}{9}-\dfrac{3}{4}+\dfrac{1}{3}=\dfrac{97}{36}\)
d) \(\dfrac{5}{8}:\dfrac{2}{3}\times\dfrac{1}{5}=\dfrac{5}{8}\times\dfrac{3}{2}\times\dfrac{1}{5}=\dfrac{3}{16}\)
a) \(\dfrac{11}{3}-\dfrac{2}{3}\times\dfrac{5}{6}\)
\(=\dfrac{11}{3}-\dfrac{5}{9}\)
\(=\dfrac{33}{9}-\dfrac{5}{9}\)
\(=\dfrac{28}{9}\)
b) \(\dfrac{13}{2}+\dfrac{7}{6}:\dfrac{2}{3}\)
\(=\dfrac{13}{2}+\dfrac{7}{6}\times\dfrac{3}{2}\)
\(=\dfrac{13}{2}+\dfrac{7}{4}\)
\(=\dfrac{26}{4}+\dfrac{7}{4}\)
\(=\dfrac{33}{4}\)
c) \(\dfrac{28}{9}-\dfrac{3}{4}+\dfrac{1}{3}\)
\(=\dfrac{28}{9}+\dfrac{3}{9}-\dfrac{3}{4}\)
\(=\dfrac{31}{9}-\dfrac{3}{4}\)
\(=\dfrac{124}{36}-\dfrac{27}{36}\)
\(=\dfrac{97}{36}\)
d) \(\dfrac{5}{8}:\dfrac{2}{3}\times\dfrac{1}{5}\)
\(=\dfrac{5}{8}\times\dfrac{3}{2}\times\dfrac{1}{5}\)
\(=\dfrac{3}{16}\)
Bài 1:Tính
a.1/5x1/2:1/3 b.2/9:2/3x1/2
c.1/2x1/3+1/4 c.2/7:2/3-1/7
Giúp mình nhé :)
\(a)\frac{1}{5}\times\frac{1}{2}:\frac{1}{3}=\frac{1}{5}\times\frac{1}{2}\times\frac{3}{1}=\frac{1\times1\times3}{5\times2\times1}=\frac{1\times3}{5\times2}=\frac{3}{10}\)
\(b)\frac{2}{9}:\frac{2}{3}\times\frac{1}{2}=\frac{2}{9}\times\frac{3}{2}\times\frac{1}{2}=\frac{2\times3\times1}{9\times2\times2}=\frac{1\times1\times1}{3\times1\times2}=\frac{1}{6}\)
\(c)\frac{1}{2}\times\frac{1}{3}+\frac{1}{4}=\frac{1}{6}+\frac{1}{4}=\frac{2}{12}+\frac{3}{12}=\frac{2+3}{12}=\frac{5}{12}\)
d, Tương tự như câu c
P/S : Bất phương trình????
\(\frac{1}{5}\times\frac{1}{2}:\frac{1}{3}\)
\(=\frac{1}{10}\times\frac{3}{1}\)
\(=\frac{3}{10}\)
\(\frac{2}{9}:\frac{2}{3}\times\frac{1}{2}\)
\(=\frac{2}{9}\times\frac{3}{2}\times\frac{1}{2}\)
\(=\frac{1}{3}\times\frac{1}{1}\times\frac{1}{2}\)
\(=\frac{1}{3}\times\frac{1}{2}\)
\(=\frac{1}{6}\)
1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9
1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9
=7/18
tính:
3/7x7/3
3/7:3/7
2/3x1/6x9/11
2x3x4 trên 2x3x4x5
3/7x7/3=1
3/7:7/3=1
2/3x1/6x9/11=2/3/54/11=36/11
2x3x4 trên 2x3x4x5=1/5
mk chắc chắn, cho mk nha, kb nhé
\(\frac{3}{7}x\frac{7}{3}=1\)
\(\frac{3}{7}:\frac{7}{3}=1\)
\(\frac{2}{3}x\frac{1}{6}x\frac{9}{11}=\frac{2x1x9}{3x6x11}=\frac{18}{198}=\frac{1}{11}\)
\(\frac{2x3x4}{2x3x4x5}=\frac{1}{5}\)
Cho phương trình x2-2(m+1)x+2m+7
a,Tìm m để phương trình có 2 nghiệm đều dương
b,Tìm m để phương trình có 2 nghiệm x1,x2 thỏa mãn x12+3x1-x2=7-2m
4/3x1/7+4/7x1/11+4/11x1/15+4/15x1/19=?
Cho phương trình:
a,mx2+2(m-4)x+m+7=0
Tìm m để x1-2x2=0
b, x2+(m-1)x+5m-6=0
Tìm m để 4x1+3x2=1
c,3x2-(3m-2)x-(3m+1)=0
TÌm m để 3x1-5x2=6
a) (*) m = 0 => x = \(\dfrac{7}{8}\) (loại)
(*) \(m\ne0\) Phương trình có nghiệm
\(\Delta=\left[2\left(m-4\right)\right]^2-4m\left(m+7\right)=-60m+64\ge0\Leftrightarrow m\le\dfrac{16}{15}\)
Hệ thức Viet kết hợp 4x1 + 3x2 = 1
\(\Leftrightarrow\left\{{}\begin{matrix}x_1x_2=\dfrac{m+7}{m}\\x_1+x_2=\dfrac{8-2m}{m}\\x_1=2x_2\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}x_1x_2=\dfrac{m+7}{m}\\x_1=\dfrac{16-4m}{3m}\\x_2=\dfrac{8-2m}{3m}\end{matrix}\right.\)
\(\Leftrightarrow\dfrac{16-4m}{3m}.\dfrac{8-2m}{3m}=\dfrac{m+7}{m}\)
\(\Leftrightarrow2\left(8-2m\right)^2=9m\left(m+7\right)\)
\(\Leftrightarrow8m^2-64m+128=9m^2+63m\)
\(\Leftrightarrow m^2+127m-128=0\Leftrightarrow\left[{}\begin{matrix}m=1\\m=128\left(\text{loại}\right)\end{matrix}\right.\)<=> m = 1