tìm a biết:
(1-1/3)x(1-1/6)x(1-1/10)x(1-1/15)x...x(1-1/780)xa=1
tìm a biết:
( 1-1/3 ) x ( 1-1/6 ) x ( 1-1/10 ) x......x ( 1-1/780 ) x a =1
C=(1-1/3)x(1-1/6)x(1-1/10)x(1-1/15)x...x(1-1/780)
Tim C
A =8/9 x 15/16 x 24/25 x.......x 2499/2500
B=( 1 -1/3) x (1-1/6)x (1- 1/10)x .....x ( 1- 1/780)
Tính nhanh nha các bạn ơi
Tính nhanh:
A=10 - 1/72 - 1/50 - 1/42- .... - 1/6 - 1/2
Tìm x:
a.(x+1) + (x+1/3) +(x+1/6) +...+(x+1/55)= 130/11
b. 2/3.x - 780/11 :(13/15 +13/3535+13/63+1313/9999) +5=0
c. 2012/77 +20112/165 +2012/258 +2012/437=16/161 .x
Cảm ơn nhiều!!!!!!!!!!!
Tính nhanh A=(1-1/3)x(1-1/6)x(1-1/10)x...x(1-1/780)
Ta có A = \(\left(1-\frac{1}{3}\right).\left(1-\frac{1}{6}\right).\left(1-\frac{1}{10}\right)...\left(1-\frac{1}{780}\right)\)
= \(\frac{2}{3}.\frac{5}{6}.\frac{9}{10}...\frac{779}{780}=\frac{4}{6}.\frac{10}{12}.\frac{18}{20}...\frac{1558}{1560}=\frac{1.4}{2.3}.\frac{2.5}{3.4}.\frac{3.6}{4.5}...\frac{38.41}{39.40}=\frac{\left(1.2.3...38\right).\left(4.5.6...41\right)}{\left(2.3.4...39\right).\left(3.4.5...40\right)}\)
= \(\frac{1.41}{39.3}=\frac{41}{117}\)
(1-1/3)x(1-1/6)x(1-1/10)x...x(1-1/780)
giúp mình nha
(1-1/3).(1-1/6).(1-1/10)...(1-1/780) (ko có dấu "...")
Giải: (1-1/3).(1-1/6).(1-1/10)...(1-1/780)
= 2/3 . 5/6....779/780
= 4/6 . 10/12.....1558/1560
= 1.4 . 2.5 .... 38.41/ 2.3 . 3. 4. .....39.40
= ( 1.2.3....38).(4.5....41)/(2.3.4....39)(3...
triệt tiêu xong còn 41/39.3= 41/117
ĐS = 41/117
Tìm x biết : X x (1+1/3+1/6+1/10+1/15+...+1/190)=2013x19/10
\(\left(1-\dfrac{1}{3}\right)x\left(1-\dfrac{1}{6}\right)x\left(1-\dfrac{1}{15}\right)x.....x\left(1-\dfrac{1}{1225}\right)xa=1\\\)
tìm a ghi chú(\(x\)) = nhân
Bài 1) Tìm x
A) x ⋮ 10, x ⋮ 15 và x < 100.
B) 24 ⋮ x, 36 ⋮ x, x lớn nhất
C) x ⋮ 4, x ⋮ 7, x ⋮ 8, x nhỏ nhất
Bài 2) Tìm x ∈ N
A) 6 ⋮ (x - 1)
B) 15 ⋮ (x + 3)
C) 12 ⋮ (x + 3)
D) (x + 16) ⋮ (x + 1)
Cần gấp ạ
Bài 2:
a: \(\Leftrightarrow x-1\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
=>\(x\in\left\{2;0;3;-1;4;-2;7;-5\right\}\)
b: \(\Leftrightarrow x+3\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{-2;-4;0;-6;2;-8;12;-18\right\}\)
c: \(\Leftrightarrow x+3\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
=>\(x\in\left\{-2;-4;-1;-5;0;-6;1;-7;3;-9;9;-15\right\}\)
d: =>x+1+15 chia hết cho x+1
=>\(x+1\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{0;-2;2;-4;4;-6;14;-16\right\}\)