\(5^x.5^{x+2}=625\)

\(\Leftrightarrow5^{2x+2}=5^4\)

\(\Leftrightarrow2x+2=4\)

\(\Leftrightarrow x=1\)

Vậy ..

5^x.5^x+2 =625

5^x.5^x.5² =625

5^x+x.25 =625

5^2x.25 =625

5^2x =625:25

5^2x =25

5^2x = 5²

⇒2x =2

x =2:2

x =1

Vậy x=1

\(\left(2x-5\right)^2=625\)

\(\left(2x-5\right)^2=25^2=\left(-25\right)^2\)

TH1: \(2x-5=25\)

\(2x=30\)

\(x=15\)

TH2 : \(2x-5=-25\)

\(2x=-20\)

\(x=-10\)

Vậy \(x\in\left\{-10,15\right\}\)

=.= hok tốt!!

\(\left(2.x-5\right)^2=625\)

\(\left(2.x-5\right)^2=25^2\) hoặc \(\left(2.x-5\right)^2=\left(-25\right)^2\)

\(\Rightarrow\)\(2.x-5=25\) \(\Rightarrow\) \(2.x-5=-25\)

\(2.x=25+5\) \(2.x=-25+5\)

\(2.x=30\) \(2.x=-20\)

\(x=30\div2\) \(x=-20\div2\)

\(x=15\) \(x=-10\)

Vậy \(x=15\) ; \(x=-10\)

\(\left(2x-5\right)^2=625\)

\(\left(2x-5\right)^2=25^2\)

=> \(\left[{}\begin{matrix}2x-5=25\\2x-5=-25\end{matrix}\right.\) \(\) <=> \(\left[{}\begin{matrix}2x=30\\2x=-20\end{matrix}\right.\) <=> \(\left[{}\begin{matrix}x=15\\x=-10\end{matrix}\right.\)

_Vậy x = 15 hoặc x = -10

a) \(3^{x-1}+3x+3^{x+1}=1053\)

\(=3^x:3+3^x+3^x.3=1053\)

\(=3^x.\dfrac{1}{3}+1+3=1053\)

\(=3^x.\dfrac{13}{5}=1053\)

\(=3^x=243\)

\(\Rightarrow x=5\)

Vậy \(x=5\)

5^x . (5³)² = 625

5^x . 5⁶ = 5⁴

5^x+6  = 5⁴

=> x + 6 = 4

=> x = 4 - 6

x = -2

Vậy x = -2

Ủng hộ mk nha !!!! ^_^

5^x . (5³)² = 625

5^x . 5⁶ = 5⁴

5^x = 5⁴ : 5⁶

5^x =

5^x . ( 5³ )²  =625

5^x . 5⁶ = 5⁴

5^{x + 6}  = 5⁴

x + 6 = 4

x = 4 - 6

x = -2