1+2.( 1/2-1/3+1/3-1/4+....+1/(x-1)-1/x+1)=3/2

1+2.(1/2-1/x+1)=3/2

1-2/x+1=3/2-1

tự tính

khó vậy

Bài 2:

\(M=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{2008.2009}\)

\(\Rightarrow M=\frac{3-2}{2.3}+\frac{4-3}{3.4}+\frac{5-4}{4.5}+...+\frac{2009-2008}{2008.2009}\)

\(\Rightarrow M=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{2008}-\frac{1}{2009}=\frac{1}{2}-\frac{1}{2009}\)

Bài 1:

Ta có: \(\frac{x}{2}+\frac{x}{3}=x\left(\frac{1}{2}+\frac{1}{3}\right)=\frac{5}{6}x=\frac{1}{4}\Rightarrow x=\frac{3}{10}\)

ta phân tích thành

\(\frac{1}{1\cdot2}\)x\(\frac{2\cdot2}{2\cdot3}\)x\(\frac{3\cdot3}{3\cdot4}\)x......x\(\frac{5\cdot5}{5\cdot6}\)x\(\frac{6\cdot6}{6\cdot7}\)

Tử nhân tử mẫu nhân mẫu ta có

1x2x2x3x3x.........x5x5x6x6

1x2x2x3x3x4x....x5x6x6x7

Rút gọn ta có

\(\frac{1}{7}\)

Vậy A=\(\frac{1}{7}\)

\(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+...+\dfrac{1}{x\left(x+1\right)}=\dfrac{9}{20}\)

\(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...-\dfrac{1}{x}+\dfrac{1}{x}-\dfrac{1}{x+1}=\dfrac{9}{20}\)

\(\dfrac{1}{2}+0+0+0+...+0-\dfrac{1}{x+1}=\dfrac{9}{20}\)

\(\dfrac{1}{2}-\dfrac{1}{x+1}=\dfrac{9}{20}\)

\(\dfrac{1}{x+1}=\dfrac{1}{20}\)

\(x+1=20\)

\(x=20-1\)

\(x=19\)

Có: \(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{x\left(x+1\right)}=\dfrac{9}{20}\)

\(\Rightarrow\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{x-1}-\dfrac{1}{x}+\dfrac{1}{x}-\dfrac{1}{x+1}=\dfrac{9}{20}\)

\(\Rightarrow\dfrac{1}{2}-\dfrac{1}{x+1}=\dfrac{9}{20}\)

\(\Rightarrow\dfrac{1}{x+1}=\dfrac{1}{20}\)

\(\Rightarrow x+1=20\Leftrightarrow x=19\)