a) 3 x 5 < 3 x 6

3 x 5 > 3x 4

b) 3 x 5 = 5 x 3

4 x 6 = 6 x 4

c) 20 : 4 > 20 : 5

20 : 4 < 20 : 2

a, 3 x 5  < 3 x 6

b, 3 x 5  > 3 x 4

c, 

a) 3 x 5 < 3 x 6; 3 x 5 > 3 x 4.
b) 3 x 5 = 5 x 3; 4 x 6 = 6 x 4.
c) 20 : 4 > 20 : 5; 20 : 4 < 20 : 2
 Mong em làm bài được điểm 10
 

1) \(2^3\times x-5^2\times x=2\times\left(5^2+2^2\right)-33\)

\(x\times\left(2^3-5^2\right)=2\times\left(25+4\right)-33\)

\(x\times\left(8-25\right)=2\times29-33\)

\(x\times-17=25\)

\(x=-\dfrac{25}{17}\)

2) \(15\div\left(x+2\right)=\left(3^3+3\right)\div1\)

\(15\div\left(x+2\right)=\left(27+3\right)\div1\)

\(15\div\left(x+2\right)=30\div1\)

\(15\div\left(x+2\right)=30\)

\(x+2=\dfrac{1}{2}\)

\(x=-\dfrac{3}{2}\)

3) \(20\div\left(x+1\right)=\left(5^2+1\right)\div13\)

\(20\div\left(x+1\right)=\left(25+1\right)\div13\)

\(20\div\left(x+1\right)=26\div13\)

\(20\div\left(x+1\right)=2\)

\(x+1=20\div2\)

\(x+1=10\)

\(x=9\)

4) \(320\div\left(x-1\right)=\left(5^3-5^2\right)\div4+15\)

\(320\div\left(x-1\right)=\left(125-25\right)\div4+15\)

\(320\div\left(x-1\right)=100\div4+15\)

\(320\div\left(x-1\right)=25+15\)

\(320\div\left(x-1\right)=40\)

\(x-1=8\)

\(x=9\)

5) \(240\div\left(x-5\right)=2^2\times5^2-20\)

\(240\div\left(x-5\right)=4\times25-20\)

\(240\div\left(x-5\right)=100-20\)

\(240\div\left(x-5\right)=80\)

\(x-5=30\)

\(x=35\)

6) \(70\div\left(x-3\right)=\left(3^4-1\right)\div4-10\)

\(70\div\left(x-3\right)=\left(81-1\right)\div4-10\)

\(70\div\left(x-3\right)=80\div4-10\)

\(70\div\left(x-3\right)=20-10\)

\(70\div\left(x-3\right)=10\)

\(x-3=7\)

\(x=10\)

20x1+20x2+20x3+20x4+20x5+20x6= 20x(1+2+3+4+5+6)= 20 x 21 = 420

Còn câu 2 mik thấy khó quá cho mik xin lỗi nha

=20+40+60+80+100+120

=420

Con thứ nhất: = 20.(1+2+3+4+5+6)

                      =420

Con 2 để mình nghĩ nhé!

x^2=16

Suy ra x^2=4^2

Vậy x^2=4^2

[1/(x+2)-1/(x+5)]+[1/(x+5)-1/(x+10)]+[1/(x+10)-1/(x+17)]=x/15.[1/(x+2)-1/(x+17)]
1/(x+2)-1/(x+17)=x/15.[1/(x+2)-1/(x+17)]
1=x/15
x=15

sdsdxc

a: \(\Leftrightarrow\dfrac{1}{x+2}-\dfrac{1}{x+5}+\dfrac{1}{x+5}-\dfrac{1}{x+10}+\dfrac{1}{x+10}-\dfrac{1}{x+17}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)

=>\(\dfrac{x+17-x-2}{\left(x+2\right)\left(x+17\right)}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)

=>x=15

b: \(\Leftrightarrow-\dfrac{1}{x-1}+\dfrac{1}{x-3}-\dfrac{1}{x-3}+\dfrac{1}{x-8}-\dfrac{1}{x-8}+\dfrac{1}{x-20}-\dfrac{1}{x-20}=\dfrac{-3}{4}\)

=>1/x-1=3/4

=>x-1=4/3

=>x=7/3

`1/2 : x-5/6 =-2/3`

`=> 1/2 : x=-2/3 +5/6`

`=> 1/2 : x= -4/6 +5/6`

`=> 1/2 : x=1/6`

`=>x=1/2:1/6`

`=>x= 1/2 xx 6`

`=>x= 6/2`

`=>x=3`

Vậy `x=3`

__

`20% . x +5/8 -x . 0,5 =11/20`

`=> 20/100 . x + 5/8 - x . 5/10=11/20`

`=> 1/5 . x+5/8 - x. 1/2 =11/20`

`=> (1/5 -1/2) . x+5/8=11/20`

`=>-3/10 . x+ 5/8 =11/20`

`=> -3/10 . x=11/20 -5/8`

`=>-3/10 .x=-3/40`

`=> x= -3/40 : (-3/10)`

`=> x=-3/40 xx (-10/3)`

`=>x= 1/4`

Vậy `x=1/4`

` @ ` \(\text{Nguyễn Hoàng Duy Khánh}\)

mình vừa giải câu ở dưới r nhe