a) | 5/4x -7/2| - | 5/8x + 3/5| = 0

|5/4x - 7/2| = | 5/8x + 3/5|

TH1: 5/4x - 7/2 = 5/8x + 3/5

=> 5/4x - 5/8x = 3/5 +7/2

5/8x = 41/10

x = 41/10:5/8

x = 164/25

TH2: 5/4x - 7/2 = -5/8x - 3/5

=> 5/4x + 5/8x  = -3/5 +7/2

15/8x  = 29/10

x = 29/10 : 15/8

x = 116/75

KL: x = 164/25 hoặc x = 116/75

các bài cn lại b lm tương tự nha! h lm dài lắm!

a: =>|5/4x-7/2|=|5/8x+3/5|

=>5/4x-7/2=5/8x+3/5 hoặc 5/4x-7/2=-5/8x-3/5

=>5/8x=41/10 hoặc 15/8x=29/10

=>x=164/25 hoặc x=116/75

b: =>3:|x/4-2/3|=6-21/5=9/5

=>|1/4x-2/3|=5/3

=>1/4x-2/3=5/3 hoặc 1/4x-2/3=-5/3

=>1/4x=7/3 hoặc 1/4x=-1

=>x=28/3 hoặc x=-4

c: \(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\\left(2x-x-9\right)\left(2x+x+9\right)=0\end{matrix}\right.\Leftrightarrow x=9\)

e: =>|2x-7|=2x-7

=>2x-7>=0

=>x>=7/2

a: \(\Leftrightarrow x^2+10x+25-x^2+4x=55\)

=>14x=30

hay x=15/7

b: \(\Leftrightarrow\left(x-7\right)\left(x-3\right)=0\)

hay \(x\in\left\{7;3\right\}\)

a) (x-17)/33 + (x-21)/29 + x/25 = 4 <=> [(x-17)/33-1] + [(x-21)/29-1] + x/25-2] = 0 <=> (x-50)/33 + (x-50)/29 + (x-50)/25 = 0 <=> (x-50)(1/33+1/29+1/25) = 0 Mà 1/33+1/29+1/25 khác 0. <=> x- 50 = 0 <=> x=50 b) (3x−5)(7−5x)+(5x+2)(3x−2)=2 <=> 21x−15x2−35+25x+15x2−10x+6x−4−2=0 <=> (15x2−15x2)+(25x+21x−10x+6x)−(35+4+2)=0 <=> 42x=41 <=> x=41/42

\(\dfrac{19}{21}< \dfrac{x}{y}< \dfrac{7}{6}\Rightarrow\dfrac{38}{42}< \dfrac{x}{y}< \dfrac{49}{42}\Rightarrow\dfrac{x}{y}\in\left\{\dfrac{13}{14};\dfrac{20}{21};\dfrac{41}{42}\right\}\)

Xét \(\dfrac{x}{y}=\dfrac{13}{14}\Rightarrow\dfrac{x}{13}=\dfrac{y}{14}=\dfrac{3x-2y}{39-28}=\dfrac{5}{11}\Rightarrow\left\{{}\begin{matrix}x=\dfrac{65}{11}\\y=\dfrac{70}{11}\end{matrix}\right.\)

Xét \(\dfrac{x}{y}=\dfrac{20}{21}\Rightarrow\dfrac{x}{20}=\dfrac{y}{21}=\dfrac{3x-2y}{60-42}=\dfrac{5}{18}\Rightarrow\left\{{}\begin{matrix}x=\dfrac{50}{9}\\y=\dfrac{35}{6}\end{matrix}\right.\)

Xét \(\dfrac{x}{y}=\dfrac{41}{42}\Rightarrow\dfrac{x}{41}=\dfrac{y}{42}=\dfrac{3x-2y}{123-84}=\dfrac{5}{39}\Rightarrow\left\{{}\begin{matrix}x=\dfrac{205}{39}\\y=\dfrac{70}{13}\end{matrix}\right.\)

(3/5x-2/3x-x).1/7=-5/21

<=> 3/35x-2/21x-1/7x=-5/21

<=> x(3/35-2/21-1/7)=-5/21

<=> -16/105x=-5/21

<=> x=(-5/21).(-105/16)

<=> x=25/16

vậy x= 25/16

\(a,2.\left(x+3\right)-3x=-2x+7\)

\(\Leftrightarrow2x+6-3x=-2x-7\)

\(\Leftrightarrow-x+6=-2x+7\)

\(\Leftrightarrow x=-6+7\)

\(\Leftrightarrow x=1\)

\(b,5.\left(x-3\right)-29=-2.\left(7-x\right)-23\)

\(\Leftrightarrow5x-15-29+23=14-2x\)

\(\Leftrightarrow5x-21=14-2x\)

\(\Leftrightarrow5x+2x=35\)

\(\Leftrightarrow x=5\)

\(c,-17+\left|5-x\right|=-2.7\)

\(\Leftrightarrow-17+\left|5-x\right|=-14\)

\(\Leftrightarrow\left|5-x\right|=3\)

\(\Leftrightarrow\orbr{\begin{cases}5-x=3\\5-x=-3\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=8\end{cases}}\)

\(d,21-\left|x+7\right|=-42:\left(-2\right)\)

\(\Leftrightarrow21-\left|x+7\right|=21\)

\(\Leftrightarrow\left|x+7\right|=0\)

\(\Leftrightarrow x+7=0\)

\(\Leftrightarrow x=7\)

\(f,\left|3x-5\right|-\left(-15\right)=5\)

\(\Leftrightarrow\left|3x-5\right|+15=5\)

\(\Leftrightarrow\left|3x-5\right|=-10\)

Vì \(\left|a\right|\ge0\)mà \(-10< 0\)nên \(x\in\Phi\)

Đã giải quyết xong!!!

giúp mình với: so sánh -37/56 với -377/567 ai giải đc mình cho

cho gì

Ta có: \(VT=\sqrt{3x^2+6x+7}+\sqrt{5x^2+10x+21}\)

\(=\sqrt{3x^2+6x+3+4}+\sqrt{5x^2+10x+5+16}\)

\(=\sqrt{3\left(x+1\right)^2+4}+\sqrt{5\left(x+1\right)^2+16}\ge2+4=6\)

Ta có: \(VP=5-x^2-2x\)

\(=-\left(x^2+2x+1\right)+6\)

\(=-\left(x+1\right)^2+6\le6\)

VP=VT khi x+1=0

hay x=-1

Vậy: x=-1