Ai trả lời đc mình sẽ 👍 nha 

a. 9/7 < 11/13

b. 12/17 > 5/36

Mik trả lời nek, bn nhớ 👍 nha.
a) 9/7 > 1        ;          11/13 <1
Nên 9/7 > 11/13
b) 12/17=432/612 ;      5/36=85/612
mà 432/612>85/612
12/17>5/36

a. 9/7 < 11/13

b. 12/17 > 5/36

A. 13/5 = 2 + 3/5   ;  15/7 = 2 + 1/7

    3/5 > 1/7 =>  13/5 > 15/7

B. 2012/1999 = 1 + 13/1999  ;  1999/1986 = 1 + 13/1986

13/1999 < 13/1986 => 2012/1999 < 1999/1986

C. 33/17 = 1 + 16/17

    37/18 = 2 + 1/18

=> 33/17 < 37/18 =>  17/33 > 18/37

D. 405/203 = 1 + 202/203

    203/101 = 2 + 1/101

=> 405/203 < 203/101 => 203/405 > 101/203

a/46/9 và 36/7

Vì 46/9-36/7<0

Nên 46/9<36/7

b/17/18 và 2014/2015

Vì 17/18-2014/2015<0

Nên 17/18<2014/2015

Ta có:\(\frac{12}{17}>\frac{12}{24}=\frac{1}{2}=\frac{7}{14}>\frac{7}{15}\)

Vậy \(\frac{12}{17}>\frac{7}{15}\)

Hoặc bạn quy đồng

a: 6/7=1-1/7

5/6=1-1/6

mà -1/7>-1/6

nên 6/7>5/6

b: 11/10>1>10/11

c: 18/36=3/6<7/6

6/7 bé hơn 5/6

11/10 lớn hơn 10/11

18/36 bé hơn 7/6

Ta có: \(\dfrac{6}{7}=\dfrac{6\times6}{7\times6}=\dfrac{36}{42};\dfrac{5}{6}=\dfrac{5\times7}{6\times7}=\dfrac{35}{42}\)

\(\Rightarrow\dfrac{36}{42}>\dfrac{35}{42}\)

\(\Rightarrow\dfrac{6}{7}>\dfrac{5}{6}\)

Ta có: \(\dfrac{11}{10}=\dfrac{11\times11}{10\times11}=\dfrac{121}{110};\dfrac{10}{11}=\dfrac{10\times10}{11\times10}=\dfrac{100}{110}\)

\(\Rightarrow\dfrac{121}{110}>\dfrac{100}{110}\)

\(\Rightarrow\dfrac{11}{10}>\dfrac{10}{11}\)

Ta có: \(\dfrac{18}{36}\) giữ nguyên ; \(\dfrac{7}{6}=\dfrac{7\times6}{6\times6}=\dfrac{42}{36}\)

\(\Rightarrow\dfrac{18}{36}< \dfrac{42}{36}\)

\(\Rightarrow\dfrac{18}{36}< \dfrac{7}{6}\)

a) Ta có :

1912 / 1917 =0,997..

3035/3040  = 0,998...

Vì 0,997...<0,998... nên 1912/1917 < 3035/3040

b)Ta có: 20/18:40/38 = 760/720

Vì 760/720 > 1 nên 20/18 > 40/38

c) Ta có :

Vì 3/7 < 1 ; 7/4 > 1

nên 3/7 < 7/4

d) Ta có : 1/2 = 20/40 ; 2/5 = 16/40 ; 4/8 = 20/40 

Vì 10/40 < 16/40 < 20/40 = 20/40

Nên 10/40 < 2/5 < 1/2 = 4/8

e) 8/2 = 4 ; 5/3 = 1,66... ; 6/5 = 1,2 ; 1/6 = 0,16...

Vì 0,16...< 1, 2 < 1,66...< 4

Nên 1/6 < 6/5 < 5/3 / 8/2

5/4 > 2021/2022

vì 5/4 >1

2021/2022<1

ta có: \(\dfrac{2021}{2022}< 1\)

          \(\dfrac{5}{4}>1\)

\(\Rightarrow\dfrac{2021}{2022}< 1< \dfrac{5}{4}\)

vậy \(\dfrac{2021}{2022}< \dfrac{5}{4}\)

\(\dfrac{2021}{2022}< 1< \dfrac{5}{4}\)