ko viết mỗi kq
ko đc viết mỗi kq
\(d,\left(1-\dfrac{4}{7}\right)\left(\dfrac{-3}{8}-\dfrac{-5}{7}\right)=\dfrac{3}{7}.\dfrac{19}{56}=\dfrac{57}{392}\\ e,\left(-\dfrac{5}{6}\right)^2=\dfrac{25}{36}\\ c,\dfrac{4}{3}-\dfrac{1}{3}:5+\dfrac{3}{4}=\dfrac{4}{3}-\dfrac{1}{15}+\dfrac{3}{4}=\dfrac{19}{15}+\dfrac{3}{4}=\dfrac{121}{60}\)
ko dc viết mỗi kq
Lời giải:
a.
$\frac{x}{-2}=\frac{-8}{x}$
$\Rightarrow x^2=(-2)(-8)=16=4^2=(-4)^2$
$\Rightarrow x=4$ hoặc $x=-4$
b.
$\frac{-5}{-14}=\frac{20}{6-5x}$
$\frac{5}{14}=\frac{20}{6-5x}$
$\Rightarrow 6-5x=20.14:5=56$
$x=-10$
ko dc viết mỗi kq
c: 7/17=x/119=-35/y
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{119\cdot7}{17}=49\\y=\dfrac{-35\cdot17}{7}=-85\end{matrix}\right.\)
d: =>x/27-1/9=1/9
=>x/27=2/9
=>x=6
ko đc viết mỗi kq =))
a: \(=\dfrac{3}{11}+\dfrac{18}{66}=\dfrac{18}{66}+\dfrac{18}{66}=\dfrac{36}{66}=\dfrac{6}{11}\)
b: \(=\dfrac{2}{9}-\dfrac{5}{12}+\dfrac{3}{4}\)
\(=\dfrac{8}{36}-\dfrac{15}{36}+\dfrac{27}{36}=\dfrac{20}{36}=\dfrac{5}{9}\)
c: \(=\dfrac{3\cdot7-5}{35}\cdot\dfrac{-40-30}{16}\)
\(=\dfrac{16}{35}\cdot\dfrac{-70}{16}=-2\)
d: \(=\dfrac{1}{5}\cdot\dfrac{2-7}{4}-\dfrac{3}{4}\cdot\dfrac{4-11}{12}\)
\(=\dfrac{1}{5}\cdot\dfrac{-5}{4}-\dfrac{3}{4}\cdot\dfrac{-7}{12}\)
\(=\dfrac{-1}{4}+\dfrac{21}{48}=\dfrac{-12+21}{48}=\dfrac{9}{48}=\dfrac{3}{16}\)
ko đc viết mỗi kq
a: \(\Leftrightarrow x^2=16\)
hay \(x\in\left\{4;-4\right\}\)
b: \(\Leftrightarrow\dfrac{20}{6-5x}=\dfrac{5}{14}\)
=>6-5x=56
=>5x=-50
hay x=-10
c: =>7/17=x/119=-35/y
=>x=49; y=-85
d: =>x/27=1/9+1/9=2/9
hay x=6
\(a,\dfrac{x}{-2}=\dfrac{-8}{x}\)
\(\Leftrightarrow x^2=16\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
\(b,\dfrac{5}{14}=\dfrac{20}{6-5x}\)
\(\Leftrightarrow30-25x=280\)
\(\Leftrightarrow25x=30-280=-250\)
\(\Leftrightarrow x=-10\)
\(c,\dfrac{7}{17}=\dfrac{x}{119}=\dfrac{-35}{y}\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{119.7}{17}=49\\y=\dfrac{-35.17}{7}=-85\end{matrix}\right.\)
\(d,\dfrac{x}{27}+\dfrac{-3}{27}=\dfrac{1}{9}\)
\(\dfrac{x-3}{27}=\dfrac{1}{9}\)
\(9x-27=27\)
\(9x=54\Rightarrow x=6\)
a)\(\dfrac{x}{-2}=-\dfrac{8}{x}\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x=-4\) hoặc x=4
b)\(-\dfrac{5}{-14}=\dfrac{20}{6-5x}\)
\(\Rightarrow-5\left(6-5x\right)=-280\)
\(-30+25x=-280\)
25x=-250
x=-10
c)\(\dfrac{7}{17}=\dfrac{x}{119}=-\dfrac{35}{y}\)
\(\Rightarrow\dfrac{x}{119}=\dfrac{7}{17}\Rightarrow x=49\)
\(-\dfrac{35}{y}=\dfrac{7}{17}\Rightarrow y=-85\)
d)\(\dfrac{x}{27}+\dfrac{-3}{27}=\dfrac{1}{9}\)
\(\dfrac{x-3}{27}=\dfrac{1}{9}\)
\(x-3=3\)
x=6
GIẢI HỘ MIK BÀI NÀY NHA , ( TÍNH HẾT CÂU RA NHA , KO PHẢI TÍNH MỖI KQ THÔI ĐÂUN)
\(a,\dfrac{8}{35}\)
\(b,\dfrac{15}{8}\)
\(c,\dfrac{30}{21}\)
\(d,\dfrac{72}{175}\)
const fi='inp.inp'
fo='out.inp'
var f1,f2:text;
st:array[1..100]of string;
i,n:integer;
begin
assign(f1,fi); reset(f1);
assign(f2,fo); rewrite(f2);
n:=0;
while not eof(f1) do
begin
n:=n+1;
readln(f1,st[n]);
end;
for i:=1 to n do
writeln(f2,length(st[i]));
close(f1);
close(f2);
end.
GIẢI HỘ MIK NHA , MIK XIN CÁC BN GIẢI HỘ MK NHA ( RÕ RÀNG RA NHA ** CHỨ KO PHẢI VIẾT MỘT ĐA ĐÂU ** VIẾT PT XG KQ NHA )
25/9-2=25/9-18/9=7/9
4-5/7=28/7-2/7=26/7
189/45-2=189/45-90/45=99/45
6-1515/1818=6-15/18=6-5/6=36/6-5/6=31/6
viết gọn kq mỗi phép tính sau dưới dạng lũy thừa:
a. 25 mũ 2 : 100 mũ 0
b. 30 mũ 3 . 30 mũ 0
\(25^2:100^0=\left(5^2\right)^2:1=5^4\\ 30^3:30^0=2^3.3^3.5^3:1=2^3.3^3.5^3\)