đây mà là toán lớp 1 á bọn chị họ lớp 3 mà còn chưa học đây này

a) (x: 8 - l).2 = 1.14 nên x : 8 - 1 = 7. Do đó x =  64.

b) (2x + 3).30 = 25.6 nên 2x + 3 = 5. Do đó x = 1.

c) 6.(2x - 7) = 9.(x - 3) nên 12x - 42 = 9x - 27.

Do đó 3x = 15. Vậy x =  5.

d) -7.(x + 27) = 6.(x + l) nên -7x - 189 = 6x + 6.

Do đó 13x = -195. Vậy x = -15.

=7+7x9 +7x90

=7x(1+9+90)

= 7 x 100

=700

=7+(7x9+7)x90

=7+70x90

=7+6300

=6307

a: =>7x=42

hay x=6

b: =>5x=35

hay x=7

c: =>x-14=16

hay x=30

d: =>36-4x=4

=>4x=32

hay x=8

e: =>x-12=144

hay x=156

f: =>3x-16=14

hay x=10

g: =>x+33=45

hay x=12

h: =>(x+9):2=39

=>x+9=78

hay x=69

a: =>7x=42

hay x=6

b: =>5x=35

hay x=7

c: =>x-14=16

hay x=30

d: =>36-4x=4

=>4x=32

a/ x + 2x + 3x = 36

=> 6x = 36

=> x = 6

Vậy ..

b/ 7x - 2x - x = 24

=> 4x = 24

=> x = 6

Vậy ...

c/ (x : 5) - 10 = 5

=> x : 5 = 15

=> x = 75

Vậy ...

d/ 7. (x+3) = 49

=> x + 3 = 7

=> x = 4

Vậy ....

e/ (x - 5) . 4 = 32

=> x - 5 = 8

=> x = 13

Vậy. ..

g/ 7x - 3 = 25

=> 7x = 28

=> x = 4

Vậy ...

h/ 17 - (x :3) = 10

=> x : 3 = 17 - 10

=>x : 3 = 7

=> x = 21

Vậy ..

a) x + 2x + 3x = 36 

=> 6x = 36

=> x = 6

b)7x - 2x - x = 24

=> 4x = 24 

=> x = 6

c) (x : 5 ) - 10 = 5

=> x : 5 = 15

=> x = 3

d) 7 . ( x + 3 ) = 49

=> x + 3 = 7

=> x = 4

e) ( x - 5 ) .  4 =32 

=> x - 5 = 8

=> x = 3

g) 7x - 3 = 25 

=> 7x = 28

=> x = 4

h) 17 - ( x : 3 ) = 10

=> x : 3 = 7

=> x = 21

a) x + 2x + 3x = 36

=> 6x = 36 =>  x = 36 : 6 = 6.

b) 7x - 2x -x = 24

=> 4x = 24 => x = 24 : 4 = 6.

c)(x : 5) - 10 = 5

=> x : 5 = 5 + 10 = 15

=> x  = 15 x 5 = 75.

d) 7. (x + 3) = 49

=> x + 3 = 49 : 7 = 7

=> x = 7 - 3 = 4.

e)(x - 5) . 4 = 32

=> x - 5 = 32 : 4 = 8

=> x = 8 + 5 = 13.

g) 7x - 3 = 25

=> 7x = 25 + 3 = 28 => x = 28 : 7 = 4

h) 17 - ( x : 3 ) = 10

=> x : 3 = 17 - 10 = 7

=> x = 7.3 = 21

chuyển đổi lại : (7x - 3) : 12 = 13

=> (7x - 3) = 13 * 12

=> 7x - 3 = 156

=> 7x = 159

=> x=  159/7

[(7x - 31) : 5] * 36 = 7236

=> [(7x - 31) : 5] = 7236 : 36 = 201

=> (7x - 31) : 5 = 201

=> 7x - 31 = 1005

=> 7x = 1036

=> x = 148

1 + 2 + 3 + 4 + 5 +... + 100 + x = 5350

SSH : \(\left(100-1\right):1+1=100\)

=> tổng : \(\frac{\left(1+100\right)\cdot100}{2}=5050\)

=> 5050 + x = 5350

=> x = 5350 - 5050 = 300

80 - 9(x - 4) = 35

=> 9(x - 4) = 80 - 35 = 45

=> x - 4 = 45 : 9

=> x - 4 = 5

=> x = 9

(3x - 21) : 4 + 108 = 114

=> (3x - 21) : 4 = 114 - 108 = 6

=> 3x - 21 = 24

=> 3x = 45

=> x = 15

[(6x - 72) : 2 - 84]*14 = 2814

=> [(6x - 72) : 2 - 84] = 201

=> (6x - 72) : 2 - 84 = 201

=> (6x - 72) : 2 = 285

=> 6x - 72 = 570

=> 6x = 642

=> x = 107

28x + 12x = 80

=> 40x = 80

=> x = 2

249 - 7(1 + x) = 200

=> 7(1 + x) = 49

=> 1 + x = 7

=> x = 6

20 - [(x - 5) * 7 + 4] = 2

=> [(x - 5) * 7 + 4] = 18

=> (x - 5)*7 + 4 = 18

=> (x - 5) * 7 = 14

=> x - 5 = 2

=> x = 7

\(\frac{7x-33}{12}=13\)

\(7x-33=13\cdot12\)

\(7x-33=156\)

\(7x=156+33\)

\(7x=189\)

\(x=\frac{189}{7}=27\)

\(\frac{7x-31}{5}\cdot36=7236\)

\(\frac{7x-31}{5}=\frac{7236}{36}\)

\(\frac{7x-31}{5}=201\)

\(7x-31=201\cdot5\)

\(7x-31=1005\)

\(7x=1005+31\)

\(7x=1036\)

\(x=\frac{1036}{7}=148\)

\(1+2+3+4+5+..+100+x=5350\)

\(\left(1+2+3+4+5+...+100\right)+x=5350\)

Phần 1 + 2 + 3 + 4 + 5 + ... + 100 có số số hạng là :

             \(\frac{100-1}{1}+1=100\) ( số hạng )

\(\Rightarrow\frac{\left(100+1\right)\cdot100}{2}+x=5350\)

\(5050+x=5350\)

\(x=5350-5050=300\)

\(80-9\left(x-4\right)=35\)

\(9\left(x-4\right)=80-35\)

\(9\left(x-4\right)=45\)

\(x-4=\frac{45}{9}\)

\(x-4=5\)

\(x=5+4=9\)

\(\frac{3x-21}{4}+108=114\)

\(\frac{3x-21}{4}=114-108\)

\(\frac{3x-21}{4}=6\)

\(3x-21=6\cdot4\)

\(3x-21=24\)

\(3x=24+21\)

\(3x=45\)

\(x=\frac{45}{3}=15\)

\(14\left(\frac{6x-72}{2}-84\right)=2814\)

\(3x-36-84=\frac{2814}{14}\)

\(3x-120=201\)

\(3x=201+120\)

\(3x=321\)

\(x=\frac{321}{3}=107\)

\(28x+12x=80\)

\(x\left(28+12\right)=80\)

\(x\cdot40=80\)

\(x=\frac{80}{40}=2\)

\(249-7\left(1+x\right)=200\)

\(-7\left(1+x\right)=200-249\)

\(-7\left(1+x\right)=-49\)

\(1+x=\frac{-49}{-7}\)

\(1+x=7\)

\(x=7-1=6\)

\(20-7\left(x-5\right)+4=2\)

\(20-7\left(x-5\right)=2-4\)

\(20-7\left(x-5\right)=-2\)

\(-7\left(x-5\right)=-2-20\)

\(-7\left(x-5\right)=-22\)

\(x-5=\frac{-22}{-7}\)

\(x=\frac{22}{7}+5=\frac{57}{7}\)

\(a,\Leftrightarrow2x^2+10x-2x^2=12\Leftrightarrow x=\dfrac{12}{10}=\dfrac{6}{5}\\ b,\Leftrightarrow\left(5-2x-4\right)\left(5-2x+4\right)=0\\ \Leftrightarrow\left(1-2x\right)\left(9-2x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{9}{2}\end{matrix}\right.\\ c,\Leftrightarrow3x^2-3x^2+6x=36\Leftrightarrow x=6\\ d,\Leftrightarrow2\left(x+5\right)-x\left(x+5\right)=0\\ \Leftrightarrow\left(2-x\right)\left(x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\\ e,\Leftrightarrow4x^2-4x+1-4x^2+196=0\\ \Leftrightarrow-4x=-197\Leftrightarrow x=\dfrac{197}{4}\)

\(f,\Leftrightarrow x^2+8x+16-x^2+1=16\Leftrightarrow8x=-1\Leftrightarrow x=-\dfrac{1}{8}\\ g,Sửa:\left(3x+1\right)^2-\left(x+1\right)^2=0\\ \Leftrightarrow\left(3x+1-x-1\right)\left(3x+1+x+1\right)=0\\ \Leftrightarrow2x\left(4x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{2}\end{matrix}\right.\\ h,\Leftrightarrow x^2+8x-x-8=0\\ \Leftrightarrow\left(x+8\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-8\end{matrix}\right.\\ i,\Leftrightarrow2x^2-13x+15=0\\ \Leftrightarrow2x^2+2x-15x-15=0\\ \Leftrightarrow\left(x+1\right)\left(2x-15\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{15}{2}\end{matrix}\right.\)

a) \(58+7x=100\)

\(=>7x=100-58\)

\(=>7x=42\)

\(=>x=42:7\)

\(=>x=6\)

b) \(3x-7=28\)

\(=>3x=28+7\)

\(=>3x=35\)

\(=>x=35:3\)

\(=>x=\dfrac{35}{3}\)

c) \(x-56:4=16\)

\(=>x-14=16\)

\(=>x=16+14\)

\(=>x=30\)

d) \(101+\left(36-4x\right)=105\)

\(=>36-4x=105-101\)

\(=>36-4x=4\)

\(=>4x=36-4\)

\(=>4x=32\)

\(=>x=32:4\)

\(=>x=8\)

e) \(\left(x-12\right):12=12\)

\(=>x-12=12.12\)

\(=>x-12=144\)

\(=>x=144-12\)

\(=>x=132\)

f) \(\left(3x-2^4\right).7^3=2.7^4\)

\(=>3x-2^4=2.7^4:7^3\)

\(=>3x-16=2.7=14\)

\(=>3x=14+16\)

\(=>3x=30\)

\(=>x=30:3\)

\(=>x=10\)

i) \(\left(10+2x\right).4^{2011}=4^{2013}\)

\(=>10+2x=4^{2013}:4^{2011}\)

\(=>10+2x=4^2=16\)

\(=>2x=16-10\)

\(=>2x=6\)

\(=>x=6:2\)

\(=>x=3\)

\(#WendyDang\)

\(2A\left(x\right)-B\left(x\right)=2\left(-3x^4+3x^3+7x^2-6x-2\right)-\left(-5x^4+2x^3-x^2+7\right)\)

\(=-6x^4+6x^3+14x^2-12x-4+5x^4-2x^3+x^2-7\)

\(\Rightarrow2A\left(x\right)-B\left(x\right)=-x^4+4x^3+15x^2-12x-11\)