help me !

Câu 5:

\(\dfrac{x+y-2017z}{z}=\dfrac{y+z-2017x}{x}=\dfrac{x+z-2017y}{y}=\dfrac{x+y-2017z+y+z-2017x+x+z-2017y}{z+x+y}=\dfrac{-2015\left(x+y+z\right)}{x+y+z}=-2015\)

\(\Rightarrow\left\{{}\begin{matrix}x+y-2017z=-2015z\\y+z-2017x=-2015x\\x+z-2017y=-2015y\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}x+y=2z\\y+z=2x\\x+z=2y\end{matrix}\right.\)

\(P=\left(1+\dfrac{y}{x}\right)\left(1+\dfrac{x}{z}\right)\left(1+\dfrac{z}{y}\right)=\dfrac{x+y}{x}.\dfrac{x+z}{z}.\dfrac{y+z}{z}=\dfrac{2z.2y.2x}{xyz}=8\)

1: \(\left(416-7654\right)-\left(-584+19-654\right)\)

\(=416-7654+584-19+654\)

\(=416+584-7654+654-19\)

=1000-7000-19

=-6019

2: \(\left(214-4864\right)-\left(-192+4214-865\right)\)

\(=214-4864+192-4214+865\)

\(=\left(214-4214\right)+\left(-4864+865\right)+192\)

\(=-4000-4864+864+1+192\)

\(=-4000-4000+193=-8193\)

3: \(\left(-324+1756\right)-\left(2023-4324+756\right)\)

\(=-324+1756-2023+4324-756\)

\(=\left(-324+4324\right)+\left(1756-756\right)-2023\)

\(=4000+1000-2023=5000-2023=2977\)

4: \(\left(-214-248\right)-\left(-695+486-1248\right)\)

\(=-214-248+695-486+1248\)

\(=\left(1248-248\right)+\left(-486-214\right)+695\)

\(=1000-700+695=300+695=965\)

5: \(\left(-46+2198\right)-\left(-2023-146+198\right)\)

\(=-46+2198+2023+146-198\)

\(=\left(-46+146\right)+\left(2198-198\right)+2023\)

\(=2000+100+2023=2100+2023=4123\)

6: \(\left(-416+25\right)-\left(-1416+17-475\right)\)

\(=-416+25+1416-17+475\)

\(=\left(1416-416\right)+\left(475+25\right)-17\)

\(=1000+500-17=1500-17=1483\)

7: \(\left(-253+1976-41\right)-\left(447+976-241\right)\)

\(=-253+1976-41-447-976+241\)

\(=\left(-253-447\right)+\left(1976-976\right)+\left(241-41\right)\)

\(=-700+1000+200=500\)

8: \(-\left(-195+24-687\right)+\left(424-6195\right)\)

\(=195-24+687+424-6195\)

\(=\left(195-6195\right)+\left(424-24\right)+687\)

\(=-6000+400+687=-6000+1087=-4913\)

9: \(-\left(-241+95-148\right)-\left(6241+305\right)\)

\(=241-95+148-6241-305\)

\(=\left(241-6241\right)+\left(-95-305\right)+148\)

=-6000-400+148

=-6400+148=-6252

5 = 1 hoặc 5 = 25                    

5=1 hoặc 5=25 đùng kg. **** mk đi

5=1 nha

\(3-\left(\frac{1}{6}-x\right)\cdot\frac{2}{3}=\frac{2}{3}\)

\(3-\left(\frac{1}{6}-x\right)=\frac{\frac{2}{3}}{\frac{2}{3}}\)

\(3-\left(\frac{1}{6}-x\right)=1\)

\(\frac{1}{6}-x=3-1=2\)

\(x=\frac{1}{6}-2=-\frac{11}{6}\)

\(3-\left(\frac{1}{6}-x\right).\frac{2}{3}=\frac{2}{3}\)

\(\left(\frac{1}{6}-x\right).\frac{2}{3}=3-\frac{2}{3}\)

\(\left(\frac{1}{6}-x\right).\frac{2}{3}=\frac{9}{3}-\frac{2}{3}\)

\(\left(\frac{1}{6}-x\right).\frac{2}{3}=\frac{7}{3}\)

\(\frac{1}{6}-x=\frac{7}{3}:\frac{2}{3}\)

\(\frac{1}{6}-x=\frac{7}{3}:\frac{3}{2}\)

\(\frac{1}{6}-x=\frac{7}{2}\)

\(x=\frac{1}{6}-\frac{7}{2}\)

\(x=\frac{1}{6}-\frac{21}{6}\)

\(x=\frac{-20}{6}=\frac{-10}{3}\)

\(3-\left(\frac{1}{6}-x\right).\frac{2}{3}=\frac{2}{3}\)

\(3-\left(\frac{1}{6}-x\right)=1\)

\(\frac{1}{6}-x=2\)

\(x=\frac{-11}{6}\)

15B

16A

1. does => doesn't

2. isn't => doesn't

3. go => going

4. spending => spend

2/3/x=-7-1/3

2/3 / x=-22/3

x=2/3 /22/3

x=1/11

1/3+2/3:x=-7

       2/3:x=-7-1/3

       2/3:x =-22/3

             x=2/3:(-22/3)

             x=-1/11

CHÚC BN HỌC TỐT NHA!!!!!!!!!

bn lê đức anh làm sai rồi đáng nhẽ đến buóc x=2/3:(-22/3) ms đúng bn thiếu dấu trừ ở -22/3 trong khi bên trên bn có mà

\(\frac{9^2}{3^4-3^3}=\frac{3^4}{3^4-3^3}=\frac{3^4}{3^3\left(3-1\right)}=\frac{3}{2}\\ \)

Có:

\(\dfrac{3}{16}.\dfrac{12}{11}+\dfrac{3}{16}.\dfrac{7}{11}-\dfrac{3}{16}.\dfrac{8}{11}\)

\(=\dfrac{3}{16}.\left(\dfrac{12}{11}+\dfrac{7}{11}-\dfrac{8}{11}\right)\) (Áp dụng tính chất phân phối)

\(=\dfrac{3}{16}.\left(\dfrac{11}{11}\right)=\dfrac{3}{16}.1=\dfrac{3}{16}\) (đpcm)

Chúc bạn học tốt!

\(=>2^x-3=5\)
\(2^x=8\)
\(2^x=2^3\)
\(=>x=3\)

\(\left(2^x-3\right)7=35\\ 2^x-3=35:7\\ 2^x-3=5\\ 2^x=5+3\\ 2^x=8\\ 2^x=2^3\\ x=3\)