35-{12-[-14+(-2)]}
35-{12-[-14-(-2)]}
9/14 × 35/12 - 3/2
Bỏ ngoạc rồi tính
a) -( -35 + 7 -13 ) + (2 - 35) - (13 - 7)
b) (70 + 8 - 35) - (8 - 37 - 10) - 70
c) 5 - (14 + 4 - 52) - (52 - 14) + 4
d) (-24) + (19 + 12) - (15 - 12 + 4)
a) -( -35 + 7 - 13 ) + ( 2 - 35 ) - ( 13 - 7 )
= 35 - 7 + 13 + 2 - 35 - 13 + 7
= ( 35 - 35 ) + ( -7 + 7 ) + ( 13 - 13 ) + 2
= 0 + 0 + 0 + 2
= 2
b) ( 70 + 8 - 35 ) - ( 8 - 37 - 10 ) - 70
= 70 + 8 - 35 - 8 + 37 + 10 - 70
= ( 70 - 70 ) + ( 8 - 8 ) + ( -35 + 37 ) + 10
= 0 + 0 + 2 + 10
= 12
c) 5 - ( 14 + 4 - 52 ) - ( 52 - 14 ) + 4
= 5 - 14 - 4 + 52 - 52 + 14 + 4
= 5 - ( 14 + 14 ) + ( 52 - 52 ) + ( -14 + 14 )
= 5 - 14 - 14 + 0 + 0
= 5 - ( 14 - 14 )
= 5 - 0
= 5
kinh day ban oi
giúp em với ạ
\(\sqrt{5
+2\sqrt{ }6}\)
\(\sqrt{12+2\sqrt{ }35}-\sqrt{12-2\sqrt{ }35}\)
\(\sqrt{16+6\sqrt{ }7}\)
\(\sqrt{31-12\sqrt{ }3}\)
\(\sqrt{27+10\sqrt{ }2}\)
\(\sqrt{14+6\sqrt{ }5}\)
a: \(\sqrt{5+2\sqrt{6}}=\sqrt{3}+\sqrt{2}\)
b: \(\sqrt{12+2\sqrt{35}}-\sqrt{12-2\sqrt{35}}=\sqrt{7}+\sqrt{5}-\sqrt{7}+\sqrt{5}=2\sqrt{5}\)
c: \(\sqrt{16+6\sqrt{7}}=4+\sqrt{7}\)
d: \(\sqrt{31-12\sqrt{3}}=3\sqrt{3}-2\)
e: \(\sqrt{27+10\sqrt{2}}=5+\sqrt{2}\)
f: \(\sqrt{14+6\sqrt{5}}=3+\sqrt{5}\)
b)Thực hiện phép tính: 35 – {12 – [-14 +(-2)]}
a/ 1/2 + 5/6 + 11/12 + 19/20
b/ 1/2 + 5/6 + 11/12 + 19/20 + 29/30 + 41/42
c/ (1-1/3) + (1-1/15) + (1-1/35) + (1-1/63)
d/ 1/2 + 5/6 + 11/12 + ... + 9899/9900
e/ 2/3 + 14/15 + 34/35 +62/63
f/ 2/3 + 14/15 + 34/35 + ... + 9998/9999
cái này tính cái gì thế
ko hiểu
A = 12^7. 3^35 . 14^21 / 9^21 . 7^21 . 2^35 = ?
thanks <3
Mình làm câu này các câu khác tương tự
Mấu chốt làm bài này là đưa về thừa số nguyên tố
\(\frac{12^7.3^{35}.14^{21}}{9^{21}.7^{21}.2^{35}}=\frac{3^7.4^7.3^{35}.2^{21}.7^{21}}{3^{2.21}.7^{21}.2^{35}}=\frac{3^7.2^{2.7}.3^{35}.2^{21}.7^{21}}{3^{2.21}.7^{21}.2^{35}}=\frac{3^7.2^{14}.3^{35}.2^{21}.7^{21}}{3^{42}.7^{21}.2^{35}}=\frac{3^{42}.2^{35}.7^{21}}{3^{42}.7^{21}.2^{35}}=1\)
2/ Tìm y:
y + \(\dfrac{1}{3}\) x 4 = 12 \(\dfrac{2}{5}\) + y = \(\dfrac{12}{35}\) x \(\dfrac{14}{9}\)
\(y=12-\left(\dfrac{1}{3}\times4\right)=12-\dfrac{4}{3}=\dfrac{32}{3}\)
\(y=\left(\dfrac{12}{35}\times\dfrac{14}{9}\right)-\dfrac{2}{5}=\dfrac{8}{15}-\dfrac{2}{5}=\dfrac{2}{15}\)
a) \(y+\dfrac{1}{3}\times4=12\)
\(y+\dfrac{1}{3}=12:4\)
\(y+\dfrac{1}{3}=3\)
\(y=3-\dfrac{1}{3}\)
\(y=\dfrac{8}{3}\)
b) \(\dfrac{2}{5}+y=\dfrac{12}{35}\times\dfrac{14}{9}\)
\(\dfrac{2}{5}+y=\dfrac{8}{15}\)
\(y=\dfrac{8}{15}-\dfrac{2}{5}\)
\(y=\dfrac{2}{15}\)
c=(12/35--6/7+18/14:6/7_-2/5_1
\(C=\dfrac{12}{35}-\dfrac{-6}{7}+\dfrac{18}{14}:\dfrac{6}{7}-\dfrac{-2}{5}-1\)
\(=\dfrac{12}{35}+\dfrac{30}{35}+\dfrac{9}{7}\cdot\dfrac{7}{6}+\dfrac{2}{5}-1\)
\(=\dfrac{6}{5}+\dfrac{2}{5}-1+\dfrac{3}{2}\)
\(=\dfrac{3}{5}+\dfrac{3}{2}=\dfrac{21}{10}\)