tim x biet /x^2+/3x-1//=x^2+7
tim x biet -3x/4.(1/x+2/7)=0
tim x biet: (5x-2)(3x+1)+(7-15x)(x+3)=-20 Merci
(5x-2)(3x+1)+(7-15x)(x+3)=-20
<=> 15x2+5x-6x-2+7x+21-15x2-45x+20=0
<=>39-39x=0
<=>39(1-x)=0
<=>1-x=0
=>x=1
(5x-2)(3x+1)+(7-15x)(x+3)=-20
=>\(15x^2-6x+5x-2+7x-15^2+21-45x=-20\)
=>\(-39x+19=-20\)
=>\(-39x=-39\)
=>\(x=1\)
vậy x=1
(5x-2)(3x+1)+(7-15x)(x+3)=-20
<=>\(15x^2+5x-6x-2+7x-15x^2+21-45x=-20\)
<=>\(-39x+19=0\)
<=>\(-39x=-19\)
<=>\(x=\dfrac{19}{39}\)
Vậy \(x=\dfrac{19}{39}\)
tim x biet
(2x=1)^2 - 4(x=2)^2=9
3(x-1)^2 -3x(x-5)=1
3(x+2)^2+ (2x-1)^2 =7
7(x+3)(x-3)=36
tim x biet |3x-2|-x=7
tim x biet |3x-2|-x=7
\(\Rightarrow x=4,5\)
chúc năm mới vui vẻ
bai1.tim x biet:
a,(x+2).(x+3)-(x-2).(x+5)=0
b,(2x+3).(x-4)+(x-5).(x-2)=(3x-5).(x-4)
c,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)=33
,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)-33 đúng không bạn
giup mik voi tim x biet
1, 5-(3x+6)>-2x+1
2, -7.(x+2)-3x<6-11x
3, (x+1).(x+2)-x.(x+3)<4-x
4, 6-2x>17+(4-x)
Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
Tim x thuoc z, biet :(3x+7) chia het cho (x+2)