Bổ túc sơ đồ phản ứng: Al(OH)3 ⎯⎯(1)→ Al2O3 ⎯⎯(2)→ Al2(SO4)3 ⎯⎯(3)→ AlCl3
Câu 37: Bổ túc sơ đồ phản ứng: Al(OH)3 ⎯⎯(1)→ Al2O3 ⎯⎯(2)→ Al2(SO4)3 ⎯⎯(3)→ AlCl3 A. (1) nhiệt phân, (2) dung dịch H2SO4, (3) dung dịch BaCl2 B. (1) nhiệt phân, (2) dung dịch H2SO4, (3) dung dịch NaCl C. (1) nhiệt phân, (2) dung dịch Na2SO4, (3) dung dịch HCl D. (1) nhiệt phân, (2) dung dịch Na2SO4, (3) dung dịch BaCl2
Câu 37:
\((1)2Al(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O\\ (2)Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\\ (3)Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\)
Chọn A
Bài 3: Hoàn thành chuỗi phản ứng sau:
a. Al → Al2O3→Al2(SO4)3→Al(OH)3 →Al2O3→Al →NaAlO2
b.Al→AlCl3→Al(NO3)3→Al(OH)3→Al2(SO4)3→AlCl3→Al
c. Fe→FeCl2→Fe(OH)2→FeSO4→Fe(NO3)2→Fe→Fe3O4→Fe
d.Fe→FeCl3→Fe→Fe3O4→FeSO4.
Bài 3: Hoàn thành chuỗi phản ứng sau:
a. Al → Al2O3→Al2(SO4)3→Al(OH)3 →Al2O3→Al →NaAlO2
b.Al→AlCl3→Al(NO3)3→Al(OH)3→Al2(SO4)3→AlCl3→Al
c. Fe→FeCl2→Fe(OH)2→FeSO4→Fe(NO3)2→Fe→Fe3O4→Fe
d.Fe→FeCl3→Fe→Fe3O4→FeSO4.
Hoàn thành Sơ đồ Phản ứng sau:
A) Cu-> CuSO4-> CuCl2-> CuO-> CuCl2-> Cu
B) Al-> AlCl3-> Al (OH)3-8> AlCl3-> Al-> Al2(SO4)3->AL(OH)3-> AlCl3
C) Fe-> FeSO4-> FeCl2-> Fe(OH)2-> FeO-> Fe-> FeCl2-> Fe-> Fe3O4
a: \(Cu+H_2SO_4->CuSO_4+H_2\)
\(CuSO_4+BaCl_2->CuCl_2+BaSO_4\)
\(2CuCl_2+O_2->2CuO+2Cl_2\)
Cho các sơ đồ phản ứng sau:
X (dư) + Ba(OH)2 → Y + Z; X + Ba(OH)2 (dư) → Y + T + H2O
Biết chất Y tác dụng được với dung dịch H2SO4 loãng.
Cho các chất sau: Al2O3, Al(OH)3, AlCl3, Al2(SO4)3, Al(NO3)3. Số chất thỏa mãn với tính chất của X là
A. 1.
B. 2.
C. 3.
D. 4.
hoàn thành sơ đồ sau :
AL ---> Al2O3 ---> AlCl3 ---> Al(OH)3 ---> Al2(SO4)3
4Al+3O2\(\overset{t^0}{\rightarrow}\)2Al2O3
Al2O3+6HCl\(\rightarrow\)2AlCl3+3H2
AlCl3+3NaOH\(\rightarrow\)Al(OH)3+3NaCl
2Al(OH)3+3H2SO4\(\rightarrow\)Al2(SO4)3+6H2O
Al+O2→Al2O3( có nhiệt độ)
Al2O3+HCl→AlCl3+H2O
AlCl3+ NaOH→Al(OH)3+NaCl
Al(OH)3+H2SO4→Al2(SO4)3+H2O
(bạn tự cân bằng nhé)
4Al+3O2-t0->2Al2O3.
Al2O3+6HCl->2AlCl3+3H2O.
AlCl3+3NaOH->Al(OH)3+3NaCl.
2Al(OH)3+3BaSO4->Al2(SO4)3+3Ba(OH)2.
al → al2o3 → al2(so4)3 → alcl3 → al(oh)3 → al(no3)3 → al → al2(so4)3 → al(oh)3 → al2o3 → al →naalo2
4Al+3O2----to--->2Al2O3
Al2O3 +3H2SO4----->Al2(SO4)3+3H2O
Al2(SO4)3+3BaCl2------>2AlCl3+3BaSO4
2AlCl3+3Ca(OH)2---->2Al(OH)3+3CaCl2
Al(OH)3+3HNO3---->Al(NO3)3+3H2O
2Al(NO3)3+3Mg----->3Mg(NO3)2+2Al
2Al+3H2SO4------->Al2(SO4)3+3H2
Al2(SO4)3+3Ca(OH)2------>2Al(OH)3+3CaSO4
2Al(OH)3-----to----->Al2O3+3H2O
2Al2O3----\(\dfrac{t^o}{criolit}\)---->4Al+3O2
2Al+2H2O+2NaOH------>2NaAlO2+3H2
4Al+3O2\(\underrightarrow{t^o}\) 2Al2O3
Al2O3+H2SO4 —> Al2(SO4)3+3H2O
Al2(SO4)3+3BaCl2–>3BaSO4\(\downarrow\)+2AlCl3
AlCl3+3NaOH—>Al(OH)3\(\downarrow\)+3NaCl
Al(OH)3+HNO3 —>Al(NO3)3+NO2\(\uparrow\)+H2O
2Al(NO3)3+3Mg—>3Mg(NO3)2+2Al\(\downarrow\)
2Al+3H2SO4–>Al2(SO4)3+3H2\(\uparrow\)
Al2(SO4)3+6NaOH—>2Al(OH)3+3Na2SO4
2Al(OH)3\(\underrightarrow{t^o}\)Al2O3+3H2O
2Al2O3\(\xrightarrow[criolit]{đien.phan.nong.chay}\)
4Al+3O2
2Al+2NaOH+2H2O—>2NaAlO2+3H2
\(\begin{array}{l} 4Al+3O_2\xrightarrow{t^o} 2Al_2O_3\\ Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\\ Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow+3NaCl\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\uparrow\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ 2Al(OH)_3\xrightarrow{t^o} Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow{\text{đpnc, Criolit}} 4Al+3O_2\uparrow\\ 2Al+2NaOH+2H_2O\to 2NaAlO_2+3H_2\uparrow\end{array}\)
a, Al=Al2O3= AlCl3=Al(OH)3=Al2O3=Al2S3
b, Al2O3=Al=Al2(SO4)3=AlCl3=Al(OH)3=Al2O3
Al->AlCl3->Al(OH)3->Al2(SO4)3->AlCl3->Al(NO3)3->Al(OH)3->Al2O3->Al(SO4)3
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
\(AlCl_3+3NaOH\rightarrow3NaCl+Al\left(OH\right)_3\)
\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)
\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)
\(AlCl_3+3AgNO_3\rightarrow3AgCl+Al\left(NO_3\right)_3\)
\(Al\left(NO_3\right)_3+3KOH\rightarrow3KNO_3+Al\left(OH\right)_3\)
\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Al+\dfrac{3}{2}Cl_2\rightarrow AlCl_3\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\\ Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)