theo tớ la cậu tự làm thì hơn vì k ai giúp được cậu đâu

\(2^1+2^2+2^3+...+2^{2016}\)

\(=\left(2^1+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{2015}+2^{2016}\right)\)

\(=2\left(1+2\right)+2^3\left(1+2\right)+...+2^{2015}\left(1+2\right)\)

\(=3\left(2+2^3+...+2^{2015}\right)⋮3\)

\(2^1+2^2+2^3+...+2^{2016}\)

\(=\left(2^1+2^2+2^3\right)+\left(2^4+2^5+2^6\right)+...+\left(2^{2014}+2^{2015}+2^{2016}\right)\)

\(=2\left(1+2+2^2\right)+2^4\left(1+2+2^2\right)+...+2^{2014}\left(1+2+2^2\right)\)

\(=7\left(2+2^4+...+2^{2014}\right)⋮7\)

\(S=2+2^2+...+2^{2016}\)

\(\Rightarrow2S=2.\left(2+2^2+...+2^{2016}\right)\)

\(\Rightarrow2S=2^2+2^3+...+2^{2017}\)

\(\Rightarrow2S-S=2^2+2^3+...+2^{2017}-\left(2+2^2+...+2^{2016}\right)\)

\(\Rightarrow S=2^2+2^3+...+2^{2017}-2-2^2-...-2^{2016}\)

\(\Rightarrow S=2^{2017-2}\)

2^1+2^2+2^3+2^4+2^2016

=2^1+2+3+4+2016

=2^2026

S=2 + 2² + 2³+...+2²⁰¹⁶

2.S= 2²+2³+2⁴+......+2²⁰¹⁷

2.S - S = (2²+2³+2⁴+......+2²⁰¹⁷) - (2 + 2² + 2³+...+2²⁰¹⁶)

S = 2²⁰¹⁷-2

a: \(3^x-2=2^7\)

\(\Leftrightarrow3^x=128+2=130\)(vô lý)

b: \(4^{x+1}=64\)

=>x+1=3

hay x=2

c: \(\left(5x+1\right)^2=1^{2016}=1\)

=>5x+1=1 hoặc 5x+1=-1

=>x=0 hoặc x=-2/5

d: \(2^{2\left(x-1\right)}=8\)

=>2(x-1)=3

=>x-1=3/2

hay x=5/2

Đặt A=2+2²+2³+2⁴+...+2²⁰¹⁶

A=2(1+3)+2³(1+2)+...2²⁰¹⁵(1+2)

A=2.3+2³.3+...+2²⁰¹⁵.3 

A=3.(2+2³+...+2²⁰¹⁵)chia hết cho 3

A=(2+2²+2³)+(2⁴+2⁵+2⁶)+...+(2²⁰¹⁴+2²⁰¹⁵+2²⁰¹⁶⁾​

A=2(1+2+2²)+2⁴(1+2+2²)+...+2²⁰¹⁴(1+2+2²)

A=2.7+2⁴.7+...+2²⁰¹⁴.7

A=7.(2+2⁴+...+2²⁰¹⁶)chia hết cho 7

1)Số các số hạng:

(2016-3):3+1=672 số

Tổng dãy số:

672x(2016+3):2=678384

\(2016^0+1^{2016}\cdot\left(3^2\cdot3-2^4:8\right)\)

=1+1.(9.3-16:8)

=1+27-2

=26

a tk

mik gủi 1 ý 1 lần nha

c.tk

thay c = a thôi