a: \(=\dfrac{5}{14}\left(\dfrac{2}{9}+\dfrac{7}{9}+1\right)=\dfrac{5}{14}\cdot2=\dfrac{5}{7}\)

b: \(=\dfrac{6}{8}\left(\dfrac{6}{7}-6\right)=\dfrac{6}{8}\cdot\dfrac{-36}{7}=\dfrac{-216}{56}=\dfrac{-27}{7}\)

Ta có: \(\frac{15}{14}\left(\frac{14}{9}-\frac{3}{7}\right)-\frac{15}{14}\left(\frac{14}{6}-\frac{3}{7}\right)\)

\(=\frac{15}{14}\left[\left(\frac{14}{9}-\frac{3}{7}\right)-\left(\frac{14}{6}-\frac{3}{7}\right)\right]\)

\(=\frac{15}{14}\left(\frac{14}{9}-\frac{3}{7}-\frac{14}{6}+\frac{3}{7}\right)\)

\(=\frac{15}{14}\left(\frac{14}{9}-\frac{14}{6}\right)\)

\(=\frac{15}{14}\cdot\left(\frac{28}{18}-\frac{42}{18}\right)\)

\(=\frac{15}{14}\cdot\frac{-14}{18}\)

\(=\frac{-15}{18}=-\frac{5}{6}\)

Phương pháp giải:

Trừ nhẩm các số rồi điền kết quả vào chỗ trống.

Lời giải chi tiết:

14 − 7 = 7                14 − 9 = 5

14 − 8 = 6                14 − 6 = 8

14 − 0 = 14              14 − 5 = 9

14 − 10 = 4              14 − 4 = 10

14 - 7 = 7           14 - 8 = 6       14 - 0 = 14               14 - 10 = 4          14 - 9 = 5       14 - 6 = 8      14 - 5 = 9              14 - 4 = 10

Phương pháp giải:

Trừ các số rồi điền kết quả vào chỗ trống.

Lời giải chi tiết:

14 - 8 = 6

14 - 6 = 8

14 - 7 = 7

14 - 9 = 5

14 - 5 = 9

8>7     8>6     5<8     8=8

7<8     6<8     8>5   8>4

C

C

C

A = \(\frac{1}{5\times6}+\frac{3}{6\times9}+\frac{5}{9\times14}+\frac{7}{14\times21}+\frac{9}{21\times30}\)

A = \(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+\frac{1}{14}-\frac{1}{21}+\frac{1}{21}-\frac{1}{30}\)

A = \(1-\frac{1}{30}\)

A = \(\frac{29}{30}\)

\(\frac{14}{6}+\frac{1}{3}+\frac{14}{14}+\frac{14}{9}+\frac{7}{15}+\frac{6}{4}\)

\(=\frac{14}{6}+\frac{1}{3}+\frac{14}{9}+\frac{7}{15}+\frac{14}{14}+\frac{6}{4}\)

\(=\frac{42+6+28}{18}+\frac{7}{15}+\frac{2}{2}+\frac{3}{2}\)

\(=\frac{76}{18}+\frac{7}{15}+\frac{5}{2}\)

\(=\frac{76}{18}+\frac{5}{2}+\frac{7}{15}\)

\(=\frac{76+45}{18}+\frac{7}{15}\)

\(=\frac{121}{18}+\frac{7}{15}\)

\(=\frac{605+42}{90}\)

\(=\frac{647}{90}\)

\(\frac{14}{6}+\frac{1}{3}+\frac{14}{14}+\frac{14}{9}+\frac{7}{15}+\frac{6}{4}\)

\(=(\frac{7}{3}+\frac{1}{3})+1+(\frac{14}{9}+\frac{7}{15})+\frac{3}{2}\)

\(=\frac{8}{3}+1+\frac{91}{45}+\frac{3}{2}\)

\(=2+\frac{2}{3}+1+2+\frac{1}{45}+1+\frac{1}{2}\)

\(=\left(\frac{2}{3}+\frac{1}{45}+\frac{1}{2}\right)+\left(2+1+2+1\right)\)

\(=1+\frac{17}{90}+6\)

\(=7+\frac{17}{90}\)

\(=7\frac{17}{90}\)