\(a,ƯC\left(40,24\right)=Ư\left(8\right)=\left\{...\right\}\\ b,ƯC\left(12,52\right)=Ư\left(4\right)=\left\{...\right\}\\ c,ƯC\left(36,990\right)=Ư\left(18\right)=\left\{...\right\}\\ d,ƯC\left(54,36\right)=Ư\left(9\right)=\left\{...\right\}\\ e,ƯC\left(10,20,70\right)=Ư\left(10\right)=\left\{...\right\}\\ f,ƯC\left(25,55,75\right)=Ư\left(5\right)=\left\{...\right\}\\ g,ƯC\left(80,144\right)=Ư\left(16\right)=\left\{...\right\}\\ h,ƯC\left(63,2970\right)=Ư\left(9\right)=\left\{...\right\}\\ i,ƯC\left(65,125\right)=Ư\left(5\right)=\left\{...\right\}\\ j,ƯC\left(9,18,72\right)=Ư\left(9\right)=\left\{...\right\}\\ k,ƯC\left(24,36,60\right)=Ư\left(12\right)=\left\{...\right\}\\ l,ƯC\left(16,42,86\right)=Ư\left(2\right)=\left\{..\right\}\)

a:UC(40;24)=Ư(8)

b: UC(12;52)=Ư(4)

3:

a: \(40=2^3\cdot5;24=2^3\cdot3\)

=>\(ƯCLN\left(40;24\right)=2^3=8\)

=>\(ƯC\left(40;24\right)=Ư\left(8\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)

b: \(12=2^2\cdot3;52=2^2\cdot13\)

=>\(ƯCLN\left(12;52\right)=2^2=4\)

=>\(ƯC\left(12;52\right)=\left\{1;-1;2;-2;4;-4\right\}\)

c: \(36=2^2\cdot3^2;990=2\cdot3^2\cdot5\cdot11\)

=>\(ƯCLN\left(36;990\right)=3^2\cdot2=18\)

=>\(ƯC\left(36;990\right)=\left\{1;-1;2;-2;3;-3;6;-6;9;-9;18;-18\right\}\)

2:

a: \(12=2^2\cdot3;18=3^2\cdot2\)

=>\(ƯCLN\left(12;18\right)=2\cdot3=6\)

b: \(12=2^2\cdot3;10=2\cdot5\)

=>\(ƯCLN\left(12;10\right)=2\)

c: \(24=2^3\cdot3;48=2^4\cdot3\)

=>\(ƯCLN\left(24;48\right)=2^3\cdot3=24\)

d: \(300=2^2\cdot3\cdot5^2;280=2^3\cdot5\cdot7\)

=>\(ƯCLN\left(300;280\right)=2^2\cdot5=20\)

g) Ta có: 54 = 2 . 3³

            36 = 2².3²

=>ƯCLN(54; 36) = 2.3² = 18

=> ƯC(54;36) = Ư(18) = {1; 2; 3; 6; 9; 18}

j) Ta có: 9 = 3²

          18 = 2.3²

        72 = 2³ . 3²

=> ƯCLN(9; 18; 72) = 3² = 9

=> ƯC(9; 18; 72) = Ư(9) = {1; 3; 9}

h) Ta có: 10 = 2.5

          20 = 2² . 5

        60 = 2² . 3.5

=> ƯCLN(10; 20; 60) = 2.5 = 10

=> ƯC(10; 20; 60) = Ư(10) = {1; 2; 5; 10}

g) Ta có : 54 = 2.3³

             36 = 2².3²

=> ƯCLN ( 54; 36 ) = 2.3² = 18

=> ƯC ( 54;36 ) = Ư(18) = ( 1; 2; 3; 6; 9; 18 )

j) Ta có : 9 = 3²

18 = 2.3²

72 = 2³.3²

=> ƯCLN ( 9; 18; 72 ) = 3² = 9

h) Ta có : 10 = 2.5

20 = 2².5

60 = 2².3.5

=> ƯCLN ( 10; 20; 60 ) = 2.5 = 10

=> ƯC ( 10; 20; 60 ) = Ư ( 10 ) - { 1; 2; 5; 10 }

a) ƯCLN (12 ; 18 ; 54) = 6   => ƯC(12 ; 18 ; 54) = Ư (6) = {1 ; 2 ; 3 ; 6 ; -1 ; -2 ; -3 ; -6 }

b) ƯCLN (144 ; 120 ; 170 ) = 2  => ƯC ( 140 ; 120 ; 144 ) = {1 ; 2 ; -1 ; -2}

c) ƯCLN (150 ; 350 ) = 50   => ƯC ( 150 ; 350 ) = {1 ; 2 ; 5 ; 10 ; 25 ; 50 ; -1 ; -2 ; -5 ; -10 ; -25 ; -50}

d) ƯCLN ( 1800 ; 190 ) = 10  => ƯC ( 1800 ; 190) = {1 ; 2 ; 5 ; 10 ; -1 ;-2 ; -5 ; -10}

ƯC(12;18 và 54) = {1;2;3;6}

ƯC(144;120 và 170) = {1;2}

ƯC (150 và 350) = {1;2;5;10}

a)ƯC(12,18,54) = Ư(6) = {1;2;3;6}

b)ƯC(120,144,170)= {1;2}

c)ƯC(190,1800)= {1;2;5;10}

a= 4

b = 4

c= 6

d=6

tick đuê!!!!

câu b,c bài này thì sao

12 vs 52

12=2^2.3

⁵

12=2^2x3

52=2^2x13

=>ƯCLN(12,52)=2^2=4

=>ƯC(12,52)=Ư(4)={1;2;4}hết

bạn sai rồi đồ học dốt

a) 40 và 24

Ta có: 40 = 2³ . 5

          24 = 2³ . 3

=> ƯCLN(40; 24) = 2³ = 8

=> ƯC(40; 24) \(\in\) Ư(8)

=> ƯC(40; 24) \(\in\) Ư(8) = { 1; 2; 4; 8 }

   Các câu còn lại tương tự nha bạn

ƯCLN(24,40)=8

=>ƯC(24,40)=Ư(8)=(1,2,4,8)

các cau khac tuong tu nhe ban

tìm ƯC(24, 40)

a) Ta có :

40 = 2³ . 5

24 = 2³ . 3

=> ƯCLN ( 40 ; 24 ) = 2³ = 8

=> ƯC ( 40 ; 24 ) = Ư ( 8 ) = { 1 ; 2 ; 4 ; 8 }

b) Ta có :

12 = 2² . 3

52 = 2² . 13

=> ƯCLN ( 12 ; 52 ) = 2² = 4

=> ƯCLN ( 12 ; 52 ) = Ư ( 4 ) = { 1 ; 2 ; 4 }

c) Ta có :

36 = 2² . 3²

990 = 2 . 3² . 5 . 11

=> ƯCLN ( 36 ; 990 ) = 2 . 3² = 18

=> ƯC ( 36 ; 990 ) = Ư ( 18 ) = { 1 ; 2 ; 3 ; 6 ; 9 ; 18 }

d) Ta có :

54 = 2 . 3³

36 = 2² . 3²

=> ƯCLN ( 54 ; 36 ) = 2² . 3³ = 18

=> ƯC ( 54 ; 36 ) = Ư ( 18 ) = { 1 ; 2 ; 3 ; 6 ; 9 ; 18 }

a)40 và 24

ta có:

40=2^3*5

24=2^3*3

=> ƯCLN(40;24) =2^3=8

=>ƯC(40;24)=Ư(8)={1;2;4;8}

những câu còn lại tương tự bn nhé