(12 Div 5÷4)
Trừ hai phân số khác mẫu số:
a) 6/5 - 2/3 b) 1 - 4/5 c) 5/12-1/4d) 7/8-1/6a) \(\frac{6}{5}\)- \(\frac{2}{3}\)= \(\frac{18}{15}\)- \(\frac{10}{15}\)= \(\frac{8}{15}\)
b) 1 - \(\frac{4}{5}\)= \(\frac{5}{5}\)- \(\frac{4}{5}\)= \(\frac{1}{5}\)
c) \(\frac{5}{12}\)- \(\frac{1}{4}\)= \(\frac{5}{12}\)- \(\frac{3}{12}\)= \(\frac{2}{12}\)= \(\frac{1}{6}\)
d) \(\frac{7}{8}\) - \(\frac{1}{6}\) = \(\frac{21}{24}\) - \(\frac{4}{24}\)= \(\frac{17}{24}\)
~HT~
a) 6/5 - 2/3 = 8/15
b) 1 - 4/5 = 1/5
c) 5/12 - 1/4 = 1/6
d) 7/8 - 1/6 = 17/24
HT~
B = \(\frac{\left(-12\right)^5\times27^4-32^2\times81^4}{729^4\div\left(-9\right)^4\times16^5\div\left(-8\right)^3}\)
\(12:\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
12 : ( \(\frac{3}{4}-\frac{5}{6}\))2 = \(12:\left(\frac{-1}{12}\right)^2=12:\frac{1}{144}=1728\)
Trl :
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Tính giá trị của biểu thức sau:
B = \(\dfrac{\left(-12\right)^5\times27^4-32^2\times81^4}{729^4\div\left(-9\right)^4\times16^5\div\left(-8\right)^3}\)
Ta có:\(B=\dfrac{\left(-12\right)^5.27^4-32^2.81^4}{729^4:\left(-9\right)^4.16^5:\left(-8\right)^3}=\dfrac{\left(-3\right)^5.2^{10}.3^{12}-2^{10}.3^{16}}{3^{24}:3^8.2^{20}:\left(-2\right)^9}\\ =\dfrac{2^{10}.3^{16}.\left[-3-1\right]}{\left(-2\right)^{11}.3^{16}}=2\)
Vậy B = 2
Biểu thức 5*b + a div 4*3 với a =12, b = 4 có giá trị là:
A. 20
B. 21
C. 29
D. 9
Tìm số nguyên a sao cho
a. -3/8 < a/10 < -3/5
b. -5/12 < a/5 < 1/4
Tìm x . \(\frac{3}{5}\div\frac{7}{x}\div\frac{3}{4}=\frac{12}{105}\)
Thực hiện phép tính:
A =\(\frac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
B= \(81.\frac{12-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}5+\frac{5}{13}+\frac{5}{169}+\frac{5}{91}}{4-\frac{4}{7}-\frac{4}{289}-\frac{4}{85}6+\frac{6}{13}+\frac{6}{169}+\frac{6}{91}}.\frac{158158158}{711711711}\)
\(Tìm\)\(x\)\(\in\)\(ℤ\)biết :a) -1\(1\frac{4}{12}-1\frac{3}{12}\le x\le\frac{4}{3}.\frac{13}{4}\)
b)\(\left(\frac{x}{-5}+\frac{2}{3}\right):2\frac{1}{5}-1,4.\frac{15}{49}=|\frac{-5}{21}|\)
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