\(a,\dfrac{2}{3}.x=\dfrac{2}{7}\\ x=\dfrac{2}{7}:\dfrac{2}{3}=\dfrac{3}{7}\\ ---\\ b,x.\dfrac{3}{5}=\dfrac{2}{5}\\ x=\dfrac{2}{5}:\dfrac{3}{5}=\dfrac{2}{3}\\ ---\\ c,x:\dfrac{8}{13}=\dfrac{13}{7}\\x=\dfrac{13}{7}.\dfrac{8}{13}=\dfrac{8}{7}\\ ----\\ d,\dfrac{3}{2}:x=\dfrac{7}{4}\\ x=\dfrac{3}{2}:\dfrac{7}{4}=\dfrac{3}{2}.\dfrac{4}{7}=\dfrac{6}{7}\)

a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)

\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)

\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)

\(\Rightarrow x=\dfrac{-5}{12}\)

b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)

\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)

\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{2}{5}\)

c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)

\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)

\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)

\(\Rightarrow x=\dfrac{-77}{120}\)

d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)

\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)

\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)

\(\Rightarrow x=\dfrac{-7}{20}\)

e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)

\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)

\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)

\(\Rightarrow x=\dfrac{-59}{105}\)

g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)

\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{-13}{12}\)

a,sửa đề : đk x khác -2;  2 

 \(x^2+x-2+5x-10=12+x^2-4\)

\(\Leftrightarrow6x-20=0\Leftrightarrow x=\dfrac{10}{3}\left(tm\right)\)

b, \(3x-12+5+5x=105\Leftrightarrow8x=112\Leftrightarrow x=14\)

c, \(3x^2+14x-49=-\left(x^2+2x-15\right)\)

\(\Leftrightarrow4x^2+16x-34=0\Leftrightarrow x=\dfrac{-4\pm5\sqrt{2}}{2}\)

a. ko hỉu đề lắm :v

b.\(\dfrac{x-4}{5}+\dfrac{1+x}{3}=7\)

\(\Leftrightarrow\dfrac{3\left(x-4\right)+5\left(1+x\right)}{15}=\dfrac{105}{15}\)

\(\Leftrightarrow3\left(x-4\right)+5\left(1+x\right)=105\)

\(\Leftrightarrow3x-12+5+5x-105=0\)

\(\Leftrightarrow8x-112=0\)

\(\Leftrightarrow8x=112\)

\(\Leftrightarrow x=14\)

c.\(\left(3x-7\right)\left(x+7\right)=\left(5+x\right)\left(3-x\right)\)

\(\Leftrightarrow3x^2+21x-7x-49=15-5x+3x-x^2\)

\(\Leftrightarrow4x^2+16x-64=0\)

Nghiệm xấu lắm bạn

a: \(-\dfrac{2}{5}+\dfrac{4}{5}x=\dfrac{3}{5}\)

=>\(\dfrac{4}{5}x=\dfrac{3}{5}+\dfrac{2}{5}=1\)

=>\(x=1:\dfrac{4}{5}=\dfrac{5}{4}\)

b; \(-\dfrac{3}{7}-\dfrac{4}{7}:x=-2\)

=>\(\dfrac{4}{7}:x+\dfrac{3}{7}=2\)

=>\(\dfrac{4}{7}:x=2-\dfrac{3}{7}=\dfrac{11}{7}\)

=>\(x=\dfrac{4}{7}:\dfrac{11}{7}=\dfrac{4}{11}\)

a: =>4/3x=7/9-4/9=1/3

=>x=1/4

b: =>5/2-x=9/14:(-4/7)=-9/8

=>x=5/2+9/8=29/8

c: =>3x+3/4=8/3

=>3x=23/12

hay x=23/36

d: =>-5/6-x=7/12-4/12=3/12=1/4

=>x=-5/6-1/4=-10/12-3/12=-13/12

em moi lop 4 mà

\(d,-\dfrac{5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)

\(\Leftrightarrow-\dfrac{5}{6}-x=\dfrac{7}{12}+\dfrac{-4}{12}\)

\(\Leftrightarrow-\dfrac{5}{6}-x=\dfrac{1}{4}\)

\(\Leftrightarrow-x=-\dfrac{5}{6}-\dfrac{1}{4}\)

\(\Leftrightarrow-x=-\dfrac{13}{12}\)

\(\Leftrightarrow x=\dfrac{13}{12}\)

\(c,3x+\dfrac{3}{4}=2\dfrac{2}{3}\)

\(\Leftrightarrow3x+\dfrac{3}{4}=\dfrac{8}{3}\)

\(\Leftrightarrow3x=\dfrac{8}{3}-\dfrac{3}{4}\)

\(\Leftrightarrow3x=\dfrac{23}{12}\)

\(\Leftrightarrow x=\dfrac{23}{12}:3\)

\(\Leftrightarrow x=\dfrac{23}{36}\)

|2.x+4|=6

TH1: 2.x+4 = 6                

x = 1

TH2: 2.x+4 = - 6                

x = -5

Vậy x thuộc 1 và -5

|2-3.x|=5

Th1: 2-3.x=5

x = -1

Th2: 2-3.x= -5

x = 7/3

Vậy x thuộc -1 và 7/3

|7-x|=9

TH1: 7-x =9

x = -2

TH2: 7-x = -9

x = 16

Vậy.........

a) Ta có: \(\left|2x+4\right|=6\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+4=6\\2x+4=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6-4=2\\2x=-6-4=-10\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-5\end{matrix}\right.\)

Vậy: \(x\in\left\{1;-5\right\}\)

b) Ta có: \(\left|2-3x\right|=5\)

\(\Leftrightarrow\left[{}\begin{matrix}2-3x=5\\2-3x=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-3x=3\\-3x=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{7}{3}\end{matrix}\right.\)

Vậy: \(x\in\left\{-1;\dfrac{7}{3}\right\}\)

c) Ta có: \(\left|7-x\right|=9\)

\(\Leftrightarrow\left[{}\begin{matrix}7-x=9\\7-x=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-x=2\\-x=-16\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=16\end{matrix}\right.\)

Vậy: \(x\in\left\{-2;16\right\}\)

a. |2x + 4| = 6

2x + 4 = 6 hoặc 2x + 4 = -6

2x      = 6 - 4 hoặc 2x   = -6 - 4

2x    = 2 hoặc 2x   = -10 

x     = 2 : 2 hoặc x = -10 : 2

x = 1 hoặc x = -5

Vậy x = 1 hoặc x = -5

|2 - 3x| = 5

2 - 3x = 5 hoặc 2 - 3x = -5

3x  = 2 - 5 hoặc 3x   = -5 - 2

3x = -3 hoặc 3x = -7

x = -3 : 3 hoặc  x = -7 : 3 (ko tính được)

x = -1 

Vậy x = -1

c. |7 - x| = 9

7 - x = 9 hoặc 7 - x = -9

x   = 7 - 9 hoặc x  = 7 - (-9)

x = -2 hoặc x = 16 

Vậy x = -2 hoặc x = 16

`a) 3 / 5 x - 1 / 2 = 1 / 7`

`3 / 5 x = 1 / 7 + 1 / 2`

`3 / 5 x = 9 / 14`

`x = 9 / 14 : 3 / 5`

`x = 15 / 14`

______________________________

`b) 3 / 5 x + 2 / 7 = 4 / 5`

`3 / 5 x = 4 / 5 - 2 / 7`

`3 / 5 x = 18 / 35`

`x = 18 / 35 : 3 / 5`

`x = 6 / 7`

a) 3/5 x - 1/2 = 1/7

 3/5 x = 1/7 + 1/2 

 3/5 x = 9/14

x = 9/14 : 3/5

x = 15/14

b) 3/5 x + 2/7 = 4/5

3/5x = 4/5 - 2/7

3/5x = 18/35

x = 18/35: 3/5

x = 6/7

\(a.\dfrac{3}{5}x-\dfrac{1}{2}=\dfrac{1}{7}\\ \dfrac{3}{5}x=\dfrac{1}{7}+\dfrac{1}{2}\\ \dfrac{3}{5}x=\dfrac{9}{14}\\ x=\dfrac{9}{14}:\dfrac{3}{5}\\ x=\dfrac{15}{14}\\ --------\\ b.\dfrac{3}{5}x+\dfrac{2}{7}=\dfrac{4}{5}\\ \dfrac{3}{5}x=\dfrac{4}{5}-\dfrac{2}{7}\\ \dfrac{3}{5}x=\dfrac{18}{35}\\ x=\dfrac{18}{35}:\dfrac{3}{5}\\ x=\dfrac{6}{7}\)

X + 5/9 = 4/3   

X = 4/3 - 5/9

X = 7/9 

X - 4/9 = 1/2       

X = 1/2 + 4/9

X =  17/18 

6/13 + X = 7/6 

X = 7/6 - 6/13

X = 55/78

13/5 - X = 5/6   
X = 13/5 - 5/6

X= 53/30

X + 5/9 = 4/3 

x           = 4/3 - 5/9

x           =   7/9

  X - 4/9 = 1/2   

  x          = 1/2 + 4/9 

  x          =   17/18        

6/13 + X = 7/6     

            x = 7/6 - 6/13 

            x -  55/78

13/5 - X = 5/6 

          x  = 13/5 - 5/6

          x  =   53/30   

hc ngiu thế eim anh lười giải lắm =))))