\(m+\left(2022+n\right)=725+\left(2022+n\right)\)

\(\Rightarrow m+2022+n=725+2022+n\)

\(\Rightarrow m+n-n=725+2022-2022\)

\(\Rightarrow m=725\)

725

m + (2022 + n) = 725 + (2022 + n)

Ta có: m + (2022 + n) = 725 + (2022 + n)

                    2022 + n = 2022 + n

Vậy m = 725

tham khảo câu hỏi tương tự nha nguyễn hải bình

\(\left(m+2\right)\left(n+3\right)=7\)

\(\Rightarrow m+2,n+3\inƯ\left(7\right)=\left\{1;-1;7;-7\right\}\)

Do \(m,n\in N\) nên không có m và n thỏa mãn 

7 là số nguyên tố

=>m;n ko có giá trị

M(1) = N(-2)

<=> 1^3 + (m+1).1 + m^2 -3 = (-2)^2 -2m. (-2) + m^2 + 1

<=> 1 + m+1 + m^2 -3 = 4 +4m + m^2 + 1

<=> -6 = 3m

<=> m = -2

a)lim\(\dfrac{4-3^n}{2.3^n+2}\)=lim\(\dfrac{4.\dfrac{1^n}{3^n}-\dfrac{3^n}{3^n}}{2.\dfrac{3^n}{3^n}+2\dfrac{1^n}{3^n}}=\)\(lim\dfrac{4.(\dfrac{1}{3})^n-1}{2.1+2.(\dfrac{1}{3})^n}=\dfrac{4.0-1}{\dfrac{2+2.0}{ }}=\dfrac{-1}{2}\)

b) lim\(\dfrac{3^{n+1}-2^n}{2-2.3^n}=lim\dfrac{3^n.3-2^n}{2-2.3^n}=lim\dfrac{3.\dfrac{3^n}{3^n}-\left(\dfrac{2}{3}\right)^n}{2.\left(\dfrac{1}{3}\right)^n-2.\dfrac{3^n}{3^n}}=\dfrac{3.1-0}{2.0-2.1}=\dfrac{-3}{2}\)

m = 4

n = 9 

\(\frac{3}{4}\frac{-}{-}\frac{5}{9}=\frac{7}{36}=\frac{14}{72}\)

2)

a)Ta có: 2m+5=n.(m-1)

=> 2m+5=nm-n

=>2m+5-nm+n=0

=>(2-n).m+5+n=0

=>(2-n).m-(2-n)+5+2=0

=>(2-n).(m-1)+7=0

=>(2-n).(m-1)=-7=-1.7=-7.1

Ta có bảng sau:

Vậy (n,m)=(1,-6),(9,2),(3,8),(-5,0)