Ai giai minh cho 2 tick nha.Nhanh Len Nhe
\(\left(6x\right)^3:8\text{= }\left(2x-1\right)^3\)
LG
Những câu hỏi liên quan
\(3x^n\left\{6x^{n-3}+1\right\}-2x^n\left\{9x^{n-3}-1\right\}\)
em can giai luon nhe
ND
22 tháng 7 2018 lúc 16:40
Tính nhanh :
a) \(\left(x+2\right)^3-x\left(x^2+6x-5\right)-8\)
b) \(\left(x-1\right)^3-\left(x+2\right)\left(x^2-2x+4\right)+3x^2-2x\)
c) \(\left(2x+1\right)\left(4x^2+2x+1\right)-8x\left(x^2+1\right)-5\)
Nhanh nhé ! Ai nhanh và đúng nhất mình tick cho nhé ! Thank you !
các bn ơi , bn nào biến đổi đưa về dạng những hằng đẳng thức cũng được nữa nhá !
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a,\(x^3-\frac{4}{25}x=0\)
b,\(\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
c\(4.\left(\frac{-1}{2}\right)^3-2.\left(\frac{-1}{2}\right)^2+3.\left(\frac{-1}{2}\right)-1.\left(\frac{-1}{2}\right)^0\)
AI GIAI DUOC MINH CHO 10 TICK
a) \(x^3-\frac{4}{25}x=0\)
\(\Leftrightarrow x\left(x+\frac{2}{5}\right)\left(x-\frac{2}{5}\right)=0\)
<=> x = 0
Xét 2 trường hợp:
\(\Leftrightarrow x+\frac{2}{5}=0\)
\(x=0-\frac{2}{5}\)
\(x=-\frac{2}{5}\)
\(\Leftrightarrow x-\frac{2}{5}=0\)
\(x=0+\frac{2}{5}\)
\(x=\frac{2}{5}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=\pm\frac{2}{5}\end{cases}}\)
b) \(\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{4}{3}\)
\(=\frac{13}{40}:\frac{4}{3}\)
\(=\frac{39}{120}=\frac{13}{40}\)
c) \(4\left(\frac{-1}{2}\right)^3-2\left(\frac{-1}{2}\right)^2+3\left(\frac{-1}{2}\right)-1\left(\frac{-1}{2}\right)^0\)
\(=4\left(\frac{-1}{2}\right)^3-2\left(\frac{-1}{2}\right)^3+3\left(\frac{-1}{2}\right)-1.1\)
\(=-\frac{1}{2}-\frac{1}{2}-\frac{3}{2}-1.1\)
\(=-\frac{5}{2}-1\)
\(=-\frac{7}{2}\)
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\(\left(2x-1\right).\left(3x-2\right)-\left(6x-1\right).\left(x-3\right)=17\)
tìm X
ai nhanh mk tick nha thank
\(\left(2x-1\right)\left(3x-2\right)-\left(6x-1\right)\left(x-3\right)=17\)
\(\Rightarrow\left(6x^2-4x-3x+2\right)-\left(6x^2-18x-x+3\right)=17\)
\(\Rightarrow6x^2-4x-3x+2-6x^2+18x+x-3=17\)
\(\Rightarrow\left(6x^2-6x^2\right)+\left(18x-4x-3x+x\right)-\left(3+2\right)=17\)
\(\Rightarrow12x-1=17\)
\(\Rightarrow12x=18\)
\(\Rightarrow x=\frac{3}{2}\)
6x2 - 4x - 3x + 2 - 6x2 - 18x - x + 3 = 17
=>>> -27x + 5 = 17 =>>> -27x = 12 =>>> x = -4/7
Vậy: x = -4/7
Chứng minh biểu thức không phụ thuộc x :
1, \(\left(3x-1\right)^2-2\cdot\left(2x-3\right)\cdot\left(2x+3\right)-\left(x-3\right)^2\)
2, \(\left(3x+2\right)^3-\left(3x-2\right)^3-3\cdot\left(6x-1\right)\cdot\left(6x+1\right)\)
3, \(\left(3x-5\right)^2+3\cdot\left(x+1\right)\cdot\left(x-1\right)-\left(4x-3\right)^2+\left(2x+2\right)\cdot\left(2x+1\right)\)
Rut gon
a)\(\left(x-4\right)\left(x+4\right)x-\left(x^2+1\right)\left(x^2-1\right)\)
b)\(\left(y-3\right)\left(y+3\right)\left(y^2+9\right)-\left(y^2+2\right)\left(y^2-2\right)\)
c)\(x\left(x+\frac{1}{2}\right)-\left(2x-1\right)\left(x+\frac{3}{4}\right)\)
giai chi tiet giup minh nhe
a/-x4+x3-16x+1
b/-77
c/\(\frac{-4x^2+3}{4}\)
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Giai phương trình : \(3\left(\frac{x+2}{x-3}\right)^2+8\left(\frac{x^2-4}{x^2-9}\right)=3\left(\frac{x-2}{x+3}\right)^2\)
AI NHANH THÌ MÌNH TICK CHO
\(ĐKXĐ:x\ne\pm3\)
Đặt \(\frac{x+2}{x-3}=a;\frac{x-2}{x+3}=b\)
Ta có:
\(pt\Leftrightarrow3a^2+8ab=3b^2\)
\(\Leftrightarrow3a^2+8ab-3b^2=0\)
\(\Leftrightarrow\left(3a-b\right)\left(3b+a\right)=0\)
\(\Leftrightarrow3a=b;3b=-a\)
Đến đây bạn thay vào làm nhá,giải như pt bậc 2 thôi
giải pt:
a,\(\left(13-4x\right)\sqrt{2x-3}+\left(4x-3\right)\sqrt{5-2x}=2+8\sqrt{-4x^2+16x-15}\)
b,\(\left(9x-2\right)\sqrt{3x-1}+\left(10-9x\right)\sqrt{3-3x}-4\sqrt{-9x^2+12x-3}=4\)
c, \(\left(6x-5\right)\sqrt{x+1}-\left(6x+2\right)\sqrt{x-1}+4\sqrt{x^2-1}=4x-3\)
Giai giup minh cac phuong trinh nay voi a !!!! hepl pls
a) P = \(\left\{x\in R|x^4-3x^3-6x^2+3x+1=0\right\}\)
b) Q=\(\left\{x\in R|\text{x^4 + 6x^3 + 6x^2 -6x +1 = 0 }\right\}\)