Ta có: \(\frac{1}{7}+\frac{2}{7}+\frac{3}{7}+...+\frac{35}{7}+\frac{36}{7}=\frac{1+2+3+....+36}{7}\)

\(=\frac{\left(1+36\right)\times36\div2}{7}=\frac{666}{7}=95\frac{1}{7}\)

Vậy giá trị của biểu thức là \(95\frac{1}{7}\)

1/7 + 2/7 + 3/7 + ............... + 35/7 + 36/7 = 666/7

a, \(A=\dfrac{1}{3}.\dfrac{-6}{-3}.\dfrac{-9}{10}.\dfrac{-13}{36}\)

\(A=\dfrac{1.\left(-6\right).\left(-9\right).\left(-13\right)}{3.13.10.36}\)

\(A=\dfrac{-1}{10.2}\)

\(A=\dfrac{-1}{20}\)

b, \(B=\dfrac{-1}{3}.\dfrac{-15}{17}.\dfrac{34}{45}\)

\(B=\dfrac{\left(-1\right).\left(-15\right).34}{3.17.45}\)

\(B=\dfrac{2}{3.3}\)

\(B=\dfrac{2}{9}\)

c, \(C=\dfrac{1}{3}.\dfrac{4}{5}+\dfrac{1}{3}.\dfrac{6}{5}+\dfrac{2}{3}\)

\(C=\dfrac{1}{3}.\left(\dfrac{4}{5}+\dfrac{6}{5}\right)+\dfrac{2}{3}\)

\(C=\dfrac{1}{3}.2+\dfrac{2}{3}\)

\(C=\dfrac{2}{3}+\dfrac{2}{3}\)

\(C=\dfrac{4}{3}\)

d, \(D=\dfrac{-5}{6}.\dfrac{4}{19}+\dfrac{-7}{12}.\dfrac{4}{19}-\dfrac{40}{57}\)

\(D=\dfrac{4}{19}.\left(\dfrac{-5}{6}+\dfrac{-7}{12}\right)-\dfrac{40}{57}\)

\(D=\dfrac{4}{19}.\dfrac{-17}{12}-\dfrac{40}{57}\)

\(D=\dfrac{-17}{57}-\dfrac{40}{57}\)

\(D=\dfrac{-57}{57}=-1\)

e, \(E=\dfrac{3}{7}.\dfrac{9}{26}-\dfrac{1}{14}.\dfrac{1}{13}-\dfrac{1}{7}\)

\(E=\dfrac{3}{7}.\dfrac{9}{26}-\left(\dfrac{1}{14}.\dfrac{1}{13}+\dfrac{1}{7}\right)\)

\(E=\dfrac{3}{7}.\dfrac{9}{26}-\left(\dfrac{1}{182}+\dfrac{1}{7}\right)\)

\(E=\dfrac{3}{7}.\dfrac{9}{26}-\dfrac{27}{182}\)

\(E=\dfrac{27}{182}-\dfrac{27}{182}\)

\(E=0\)

a) 3/5x7/9+11/9x3/5

=3/5 x(7/9+11/9)

= 3/5x2

=6/5

b)14/13:1/2+3/13x2-2x7/13

= 14/13 x 2 +3/13 x2 - 2x7/13

=2 x (14/13 +3/13 -7/13)

= 2 x 10/13

= 20/13

a) 3/5 x 7/9 + 11/9 x 3/5 - 3/10

=  3/5 x 7/9 + 11/9 x 3/5 - 3/5 x 2

=  3/5 x ( 7/9 + 11/9 - 2 )

=  3/5 x 0

=  0

b) 14/13 : 1/2 + 3/13 x 2 - 2 x 7/13

=  14/13 x 2/1 + 3/13 x 2 - 2 x 7/13

=  ( 14/13 + 3/13 - 7/13 ) x 2

=  10/13 x 2 = 20/13

chẳng hiể gì cả

a ,b

cách 1 : cộng 2 số trong ngặc rồi tính bình thường 

cách 2 : nhân phân phối ra rồi tính nhân chia trước cộng trừ sau

c,d

cách 1 : tính bình thường, nhân chia trc cộng trừ sau

cách 2 : đặt nhân tử ( thừa số ) chung

Cách 1 : \((\frac{6}{11}+\frac{5}{11})\cdot\frac{3}{7}=1\cdot\frac{3}{7}=\frac{3}{7}\)

Cách 2 : \(\frac{6}{11}\cdot\frac{3}{7}+\frac{5}{11}\cdot\frac{3}{7}=\frac{18}{77}+\frac{15}{77}=\frac{33}{77}=\frac{3}{7}\)

Cách 1 dễ rồi nha

Cách 2 : \(\frac{6}{7}:\frac{2}{5}-\frac{4}{7}:\frac{2}{5}=\frac{15}{7}-\frac{10}{7}=\frac{5}{7}\)

Cách 1 tự làm

Cách 2 : \(\frac{3}{5}\cdot(\frac{7}{9}-\frac{2}{9})=\frac{3}{5}\cdot\frac{5}{9}=\frac{1}{3}\)

Cách 1 : ...

Cách 2 : \((\frac{8}{15}+\frac{7}{15}):\frac{2}{11}=1:\frac{2}{11}=\frac{2}{11\cdot1}=\frac{2}{11}\)

\(\frac{\frac{1}{9}-\frac{5}{6}-4}{\frac{7}{12}-\frac{1}{36}-10}=\frac{36.\left(\frac{1}{9}-\frac{5}{6}-4\right)}{36.\left(\frac{7}{12}-\frac{1}{36}-10\right)}\)

                             \(=\frac{4-6.5-36.4}{3.7-1-36.10}\)

                               \(=\frac{4-30-144}{21-1-360}\)

                               \(=\frac{-26-144}{20-360}=\frac{-170}{-340}=\frac{1}{2}\)

\(\frac{\frac{4}{36}-\frac{30}{36}-\frac{144}{36}}{\frac{21}{36}-\frac{1}{36}-\frac{360}{36}}=\frac{\frac{-170}{36}}{\frac{-340}{36}}=\frac{-170}{36}:\frac{-340}{36}=\frac{-170}{36}.\frac{36}{-340}=\frac{-170}{-340}=\frac{1}{2}\)

Bấm máy tính là ra ^0^

a) (3- 5 ) + (7-9) + ( 11 - 13 ) + 15

= -2 + -2 + -2 + 15

= -6 + 15

= 9

  1+2+3+4+5+6+7+8+9:9

=1+2+3+4+5+6+7+8+1

=(1+1)+(2+8)+(3+7)+(4+6)+5

=2+10+10+10+5

=(2+5)+(10+10+10)

=7+30

=37

1 + 2 +  3 + 4 + 5 + 6 + 7 + 8 + 9 : 9

= ( 1 + 9 ) + ( 2 + 8 ) + ( 3 + 7 ) + ( 4 + 6 ) + 5 : 9

=      10    +      10     +     10      +     10     + 5 : 9

=             20              +              20             + 5 : 9

=                              40                              + 5 : 9

=                                                  45                : 9

=                                                                5

lam tiep ko

A 50

b 97

c 74

k cho mình nhé