5 x 3 +132 = 15 + 132 = 147

100 - 99 + 98 - 97 + 96 - 95 + ... + 4 - 3 + 2

= ( 100 - 99 ) + (98 - 97) + ..... + ( 4- 3 ) + 2

=       1           +    1         + .......+   1       + 2

Có số lượng số hạng là : 100 - 3 +1 = 98

Có số cặp là : 98 : 2 = 49 

Vậy số cần tìm là  (49 x 1)+ 2 = 51

con đầu bạn chép sai đề nha

( 132 x 6 - 66 x 12 ) x ( 132 x 6 + 66 )

= ( 66 x 2 x 6 - 66 x 12 ) x ( 132 x 6 + 66 )

= (  66 x 12 - 66 x 12 ) x ( 132  x 6 + 66 )

=  0 x 132 x 6 + 6

= 0 + 6 = 6

3/4.8/9.15/16......9999/10000
= 3.8.15.....9999/4.9.16......10000
=101/50

a; \(\dfrac{5}{6}\) + \(\dfrac{5}{12}\) + \(\dfrac{5}{20}\) + ... + \(\dfrac{5}{132}\)

 = 5.(\(\dfrac{1}{6}\) + \(\dfrac{1}{12}\) + \(\dfrac{1}{20}\) + ..+ \(\dfrac{1}{132}\))

= 5.(\(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + ... + \(\dfrac{1}{11.12}\))

= 5.(\(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{4}\) + ...+ \(\dfrac{1}{11}\) - \(\dfrac{1}{12}\))

= 5.(\(\dfrac{1}{2}\) - \(\dfrac{1}{12}\))

= 5.(\(\dfrac{6}{12}\) - \(\dfrac{1}{12}\))

= 5.\(\dfrac{5}{12}\)

= \(\dfrac{25}{12}\)

b; \(\dfrac{1}{2.4}\) + \(\dfrac{1}{4.6}\) + ... + \(\dfrac{1}{x.\left(x+2\right)}\)

= \(\dfrac{1}{2}\) .(\(\dfrac{2}{2.4}\) + \(\dfrac{2}{4.6}\) + ... + \(\dfrac{2}{x\left(x+2\right)}\))

= \(\dfrac{1}{2}\).(\(\dfrac{1}{2}\) - \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{6}\) +...+ \(\dfrac{1}{x}\) - \(\dfrac{1}{x+2}\))

= \(\dfrac{1}{2}\).(\(\dfrac{1}{2}\) - \(\dfrac{1}{x+2}\))

= \(\dfrac{1}{2}\).\(\dfrac{x+2-2}{x+2}\)

= \(\dfrac{x+\left(2-2\right)}{2.\left(x+2\right)}\)

= \(\dfrac{x+0}{2\left(x+2\right)}\)

= \(\dfrac{x}{2.\left(x+2\right)}\)

= 0.(-26...)

=0

=0.(-26-(-5)⁸:(-3)⁶)

=0

 132-132.(-26-(-5)⁸:(-3)⁶)

= 0.(-26-(-5)⁸:(-3)⁶)

= 0

30

30

Bài 1: 

a: -8/12<0<-3/-4

b: -56/24<0<7/3

c: 4/25<1<15/13

=>-4/25>-15/13

Bài 2: 

a: =-60/45=-4/3

b: =4/15-3/2-8/5=8/30-45/30-48/30=-85/30=-17/6