\(a,4^8.2^{20}=\left(2^2\right)^8.2^{20}=2^{16}.2^{20}=2^{16+20}=2^{36}\\ b,9^{12}.27^5.81^4=\left(3^2\right)^{12}.\left(3^3\right)^5.\left(3^4\right)^4=3^{24}.3^{15}.3^{16}=3^{24+15+16}=3^{55}\\ d,25^{20}.125^4=\left(5^2\right)^{20}.\left(5^3\right)^4=5^{40}.5^{12}=5^{40+12}=5^{52}\\ d,x^7.x^4.x^3=x^{7+4+3}=x^{14}\)

a: 4*8*2^20=2^2*2^3*2^20=2^25

b: 9^12*27^5*81^4=3^24*3^15*3^16=3^55

c: 25^20*125^4=5^40*5^12=5^52

d: =x^(7+4+3)=x^14

a)

4⁹:4⁴=4⁵

17⁸:17⁵=17³

2¹⁰:8²=2¹⁰:2⁴=2⁶

18¹⁰:3¹⁰=15¹⁰

27⁵:81³=3¹⁵:3¹²=3³

b)10⁶:10²=10⁴

5⁹:5⁶=5³

4¹⁰:64³=4

2²⁵:32⁴=2²⁵:2²⁰=2⁵

18⁴:9⁴=9⁴

\(4^9:4^4\)
=\(4^{9-4}\)
=\(4^5\)
\(17^8:17^5\)
=\(17^{8-5}\)
= \(17^3\)
\(2^{10}:8^2\)
\(=2^{^{ }10}:\left(2^3\right)^2\)
=\(2^{10}:2^6\)
\(=2^4\)
\(18^{10}:3^{10}\)
=\(\left(18:3\right)^{10}\)
=\(6^{10}\)

a: \(125^5:25^3=5^{15}:5^6=5^9\)

b: \(27^6:9^3=3^{18}:3^6=3^{12}\)

c: \(4^{20}:2^{15}=2^{40}:2^{15}=2^{45}\)

d: \(24^n:2^{2n}=24^n:4^n=6^n\)

e: \(64^4\cdot16^5:4^{20}=2^{24}\cdot2^{20}:2^{40}=2^4\)

a) 4.9.16=2.2.3.3.4.4=2.2.3.3.2.2.2.2=2⁶.3²

b)4.6.9.15.25=2.2.3.2.3.3.3.5.5.5=2³.3⁴.5³=10³.3⁴

a) \({3.3^3} = 3.(3.3.3)= 3.3.3.3={3^4}\)

b) \({2^2}{.2^4}=(2.2).(2.2.2.2) =2.2.2.2.2.2= {2^6}\)

l) 27^8=(3³)⁸=3²⁴

=>27⁸:3²²=3²⁴:3²²

=3^24-22=3²

m) 8^4=(2³)⁴=2¹²

4⁵=(2²)⁵=2¹⁰

=>8⁴:4⁵=2¹²:2¹⁰

=2^12-10=2²

a) \(27^8:3^{22}\)

\(=\left(3^3\right)^8:3^{22}\)

\(=3^{24}:3^{22}=3^{24-22}\)

\(=3^2\)

b) \(8^4:4^5\)

\(=\left(2^3\right)^4:\left(2^2\right)^5\)

\(=2^{12}:2^{10}=2^{12-10}=2^2\)

Bài 6: 

a: \(2^{27}=8^9\)

\(3^{18}=9^9\)

b: Vì \(8^9< 9^9\)

nên \(2^{27}< 3^{18}\)