A, 11/12

B, 12,6

a,

x- 7/12 = 1/3

x = 1/3 + 7/12

x = 11/12

b,

x + 31/10 = 14,5

x = 14,5 - 31/10

x = 57/5

\(a,\\ x=\dfrac{1}{3}+\dfrac{7}{12}=\dfrac{11}{12}\\ b,\\ x+\dfrac{31}{10}=\dfrac{157}{10}\\ x=\dfrac{157}{10}-\dfrac{31}{10}=\dfrac{63}{5}\)

\(x+\frac{31}{10}=14,5+\frac{12}{10}\)

\(x+\frac{31}{10}=\frac{29}{2}+\frac{12}{10}\)

\(x+\frac{31}{10}=\frac{157}{10}\)

\(x=\frac{157}{10}-\frac{31}{10}\)

\(x=\frac{63}{5}\)

Học tốt #

\(x+\frac{31}{10}=14,5+\frac{12}{10}\)

\(\Rightarrow x+\frac{31}{10}=\frac{157}{10}\)

\(\Rightarrow x=\frac{157}{10}-\frac{31}{10}\)

\(\Rightarrow x=\frac{63}{5}\)

Vậy  \(x=\frac{63}{5}\)

_Chúc bạn học tốt_

x+31/10=14,5+12/10

x+31/10=29/2 + 12 /10

x+31/10=145/10+12/10

x+31/10=157/10

x=157/10-31/10

x=63/5

Vậy x=63/5

\(x+\frac{31}{10}=x+\frac{12}{10}+\frac{19}{10}=14,5+\frac{12}{10}\)

\(x+\frac{19}{10}=14,5\)

\(x+1,9=14,5\)

\(x=14,5-1,9=12,6\)

x+\(\frac{31}{10}\)=\(\frac{157}{10}\)

x=\(\frac{157}{10}-\frac{31}{10}\)

x=\(\frac{63}{5}\)

a)Ta có :

x-8,7=5 x 1,2 = 6

=> x = 6+8,7 = 14,7

Vậy x=14,7

b) Ta có 

x+31/10=14,5+12/10=15,7

=> x=15,7-31/10=12,6.

Vậy x=12,6

a) ( x - 8,7 ) = 5 * 1,2

      x - 8,7   =     6

      x           =  6 + 8,7

      x           =     14,7

b) x + 31/10 = 14,5 +12/10

b) x=12,6

do mỏi tay ahihi

\(\frac{63}{5}\)

x+3.1=15.7

x=12.6

tik nha

63/5 duyệt đi

\(b,\Rightarrow x+1-4⋮x+1\\ \Rightarrow x+1\inƯ\left(4\right)=\left\{-4;-2;-1;1;2;4\right\}\\ \Rightarrow x\in\left\{-5;-3;-2;0;1;3\right\}\\ c,\Rightarrow3\left(2x+1\right)-2\left(3x-2\right)⋮3x-2\\ \Rightarrow6x+3-6x+4⋮3x-2\\ \Rightarrow7⋮3x-2\\ \Rightarrow3x-2\inƯ\left(7\right)=\left\{-7;-1;1;7\right\}\\ \Rightarrow x\in\left\{-\dfrac{5}{3};\dfrac{1}{3}1;3\right\}\)

Ta có: \(2^x=\dfrac{1}{4}\cdot\dfrac{2}{6}\cdot\dfrac{3}{8}\cdot\dfrac{4}{10}\cdot\dfrac{5}{12}\cdot...\cdot\dfrac{30}{62}\cdot\dfrac{31}{64}\)

\(\Leftrightarrow2^x=\dfrac{1\cdot2\cdot3\cdot4\cdot...\cdot31}{2\cdot\left(2\cdot3\cdot4\cdot...\cdot31\right)\cdot64}\)

\(\Leftrightarrow2^x=\dfrac{1}{2}\cdot\dfrac{1}{64}=\dfrac{1}{128}\)
\(\Leftrightarrow2^x=\dfrac{1}{2^6}\)

\(\Leftrightarrow2^{x+6}=1\)

\(\Leftrightarrow x+6=0\)

hay x=-6

Vậy: x=-6

`1/4 . 2/6 . 3/8 ... . 30/62 .31/64 =2^x`

`-> (1.2.3....30.31)/(4.6.8....62.64)=2^x`

`-> (1.(2.3...31))/(2.(2.3.4...31).32)=2^x`

`-> 1/(2.32)=2^x`

`-> 1/64=2^x`

`-> 1/(2^6)=2^x`

`-> x=-6`.

Có: \(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}...\frac{30}{62}.\frac{31}{64}=\frac{1}{2.2}.\frac{2}{2.3}.\frac{3}{2.4}...\frac{30}{2.31}.\frac{31}{2.32}=\frac{1}{2}.\frac{1}{2}.\frac{1}{2}...\frac{1}{2}.\frac{1}{2}.\frac{1}{32}\)

\(=\frac{1}{2^{31}.2^5}=\frac{1}{2^{36}}=2^x\)\(\Rightarrow1=2^x.2^{36}=2^{36+x}\)\(\Rightarrow2^{36+x}=2^0\Rightarrow36+x=0\Rightarrow x=-36\)