⇔\(x\) x 1=\(\dfrac{8}{3}\)

⇔\(x\) =\(\dfrac{8}{3}\)

Vậy \(x\)=\(\dfrac{8}{3}\)

\(x\times3\times\dfrac{1}{3}=2\dfrac{2}{3}\\x\times3\times\dfrac{1}{3}=\dfrac{8}{3}\\ x\times3=\dfrac{8}{3}:\dfrac{1}{3}\\ x\times3=8\\ x=8:3\\ x=\dfrac{8}{3}\)

\(\Rightarrow x=\dfrac{8}{3}\)

\(\Rightarrow x+\dfrac{1}{6}=\dfrac{3}{4}\\ \Rightarrow x=\dfrac{7}{12}\)

X+

\(x+\dfrac{1}{6}=\dfrac{3}{4}\)

nên x=7/12

\(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot...\cdot\dfrac{7}{8}=\dfrac{1}{8}\)

`= 1/2 xx 2/3 xx...xx 7/8`

`= 1/8`

\(=\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{6}{7}\times\dfrac{7}{8}\\ =\dfrac{1}{8}\)

Ta có: \(\dfrac{-5}{13}\cdot\dfrac{3}{7}-\dfrac{2}{17}\cdot\dfrac{8}{13}+\dfrac{5}{13}\cdot\dfrac{1}{7}\)

\(=\dfrac{5}{13}\left(-\dfrac{3}{7}+\dfrac{1}{7}\right)-\dfrac{2}{17}\cdot\dfrac{8}{13}\)

\(=\dfrac{5}{13}\cdot\dfrac{-2}{7}-\dfrac{2}{17}\cdot\dfrac{8}{13}\)

\(=\dfrac{-10}{91}-\dfrac{16}{221}\)

\(=\dfrac{-282}{1547}\)

\(\dfrac{-5}{13}.\dfrac{3}{7}-\dfrac{2}{17}.\dfrac{8}{13}+\dfrac{5}{13}.\dfrac{1}{7}\) 

\(=\dfrac{5}{13}.\dfrac{-3}{7}-\dfrac{2}{17}.\dfrac{8}{13}+\dfrac{5}{13}.\dfrac{1}{7}\)

\(=\dfrac{5}{13}.\left(\dfrac{-3}{7}+\dfrac{1}{7}\right)+\dfrac{-2}{17}.\dfrac{8}{13}\) 

\(=\dfrac{5}{13}.\dfrac{-2}{7}+\dfrac{-2}{13}.\dfrac{8}{17}\)

\(=\dfrac{-2}{13}.\dfrac{5}{7}+\dfrac{-2}{13}.\dfrac{8}{17}\) 

\(=\dfrac{-2}{13}.\left(\dfrac{5}{7}+\dfrac{8}{17}\right)\) 

\(=\dfrac{-2}{13}.\dfrac{141}{119}\) 

\(=\dfrac{-282}{1547}\)

Bài 1: 

=>y-69,3=20,5

hay y=89,8

Bài 2: 

a: \(=365.4:43.5-7.7\cdot0.2\)

=8,4-1,54=6,86

b: \(=\dfrac{2}{5}:\dfrac{8-5}{10}+\dfrac{3}{5}=\dfrac{2}{5}\cdot\dfrac{10}{3}+\dfrac{3}{5}=\dfrac{20+9}{15}=\dfrac{29}{15}\)

\(B=\left(1-\dfrac{1}{3}\right)\cdot\left(1-\dfrac{1}{6}\right)\cdot\left(1-\dfrac{1}{10}\right)\cdot\left(1-\dfrac{1}{15}\right)\cdot...\cdot\left(1-\dfrac{1}{780}\right)\)

\(B=\left(1-\dfrac{1}{3+6+10+15+...+780}\right)\)

\(B=\left(1-\dfrac{1}{\left(780-3\right)\div3+1}\right)\)

\(B=\left(1-\dfrac{1}{260}\right)\)

\(B=\dfrac{259}{260}\)

Lời giải:
$60\text{%}\times y+\frac{3}{5}\times y+y=19,8$

$\frac{3}{5}\times y+3,5\times y+y=19,8$

$y\times (\frac{3}{5}+\frac{3}{5}+1)=19,8$

$y\times 2,2=19,8$

$y=19,8:2,2=9$

=>11/5y=19,8

hay y=9